## Ratio of Weights of 2 Immiscible Liquids forming Mixture Solution

STEP 0: Pre-Calculation Summary
Formula Used
Ratio of Weights of 2 Immiscible Liquids = (Vapor Pressure of Pure Component A*Molecular Mass of Liquid A)/(Vapor Pressure of Pure Component B*Molecular Mass of Liquid B)
WA/WB = (PAo*MA)/(PBo*MB)
This formula uses 5 Variables
Variables Used
Ratio of Weights of 2 Immiscible Liquids - The Ratio of Weights of 2 Immiscible Liquids in a mixture.
Vapor Pressure of Pure Component A - (Measured in Pascal) - Vapor Pressure of Pure Component A is the pressure exerted by a liquid or solid molecules of only A in a closed system in which they are in equilibrium with the vapour phase.
Molecular Mass of Liquid A - (Measured in Kilogram) - The Molecular Mass of Liquid A in a mixture of immiscible liquids.
Vapor Pressure of Pure Component B - (Measured in Pascal) - Vapor Pressure of Pure Component B is the pressure exerted by a liquid or solid molecules of only B in a closed system in which they are in equilibrium with the vapour phase.
Molecular Mass of Liquid B - (Measured in Kilogram) - The Molecular Mass of Liquid B in a mixture of immiscible liquids.
STEP 1: Convert Input(s) to Base Unit
Vapor Pressure of Pure Component A: 2700 Pascal --> 2700 Pascal No Conversion Required
Molecular Mass of Liquid A: 26 Gram --> 0.026 Kilogram (Check conversion here)
Vapor Pressure of Pure Component B: 10 Pascal --> 10 Pascal No Conversion Required
Molecular Mass of Liquid B: 25 Gram --> 0.025 Kilogram (Check conversion here)
STEP 2: Evaluate Formula
Substituting Input Values in Formula
WA/WB = (PAo*MA)/(PBo*MB) --> (2700*0.026)/(10*0.025)
Evaluating ... ...
WA/WB = 280.8
STEP 3: Convert Result to Output's Unit
280.8 --> No Conversion Required
280.8 <-- Ratio of Weights of 2 Immiscible Liquids
(Calculation completed in 00.031 seconds)
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National Institute of Technology (NIT), Meghalaya
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## < 10+ Immiscible Liquids Calculators

Total Vapour Pressure of mixture of given partial pressure of one liquid
Total Pressure of Mixture of Immiscible Liquids = Vapor Pressure of Pure Component B+((Vapor Pressure of Pure Component B*Weight of Liquid A*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Liquid A)) Go
Molecular Mass of Liquid forming Immiscible Mixture with Water
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Molecular Mass of Liquid in Mixture of Two Immiscible Liquids given Weight of Liquids
Molecular Mass of Liquid A = (Weight of Liquid A*Molecular Mass of Liquid B*Vapor Pressure of Pure Component B)/(Vapor Pressure of Pure Component A*Weight of Liquid B) Go
Partial Vapour Pressure of Immiscible Liquid given Partial Pressure of other Liquid
Vapor Pressure of Pure Component A = (Weight of Liquid A*Molecular Mass of Liquid B*Vapor Pressure of Pure Component B)/(Molecular Mass of Liquid A*Weight of Liquid B) Go
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Weight of Liquid A = (Vapor Pressure of Pure Component A*Molecular Mass of Liquid A*Weight of Liquid B)/(Vapor Pressure of Pure Component B*Molecular Mass of Liquid B) Go
Ratio of Weights of 2 Immiscible Liquids forming Mixture
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Ratio of Molecular Mass of 2 Immiscible Liquids
Ratio of Molecular Masses of 2 immiscible liquids = (Vapor Pressure of Pure Component B*Weight of Liquid A)/(Vapor Pressure of Pure Component A*Weight of Liquid B) Go
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Ratio of Partial Pressures of 2 Immiscible Liquids = (Weight of Liquid A*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Liquid A) Go
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Total Pressure of Mixture of Immiscible Liquids = Vapor Pressure of Pure Component A+Vapor Pressure of Pure Component B Go
Ratio of Partial Pressure of 2 Immiscible Liquids given Number of Moles
Ratio of Partial Pressures of 2 Immiscible Liquids = Number of moles of Liquid A/Number of Moles of Liquid B Go

## Ratio of Weights of 2 Immiscible Liquids forming Mixture Formula

Ratio of Weights of 2 Immiscible Liquids = (Vapor Pressure of Pure Component A*Molecular Mass of Liquid A)/(Vapor Pressure of Pure Component B*Molecular Mass of Liquid B)
WA/WB = (PAo*MA)/(PBo*MB)

## How does both liquids contribute to pressure of a mixture of 2 immiscible liquids?

Obviously if you have two immiscible liquids in a closed flask and keep everything still, the vapor pressure you measure will simply be the vapor pressure of the one which is floating on top. There is no way that the bottom liquid can turn to vapor. The top one is sealing it in. For the purposes of the rest of this topic, we always assume that the mixture is being stirred or agitated in some way so that the two liquids are broken up into drops. At any one time there will be drops of both liquids on the surface. That means that both of them contribute to the overall vapor pressure of the mixture.

## How to Calculate Ratio of Weights of 2 Immiscible Liquids forming Mixture?

Ratio of Weights of 2 Immiscible Liquids forming Mixture calculator uses Ratio of Weights of 2 Immiscible Liquids = (Vapor Pressure of Pure Component A*Molecular Mass of Liquid A)/(Vapor Pressure of Pure Component B*Molecular Mass of Liquid B) to calculate the Ratio of Weights of 2 Immiscible Liquids, The Ratio of Weights of 2 Immiscible Liquids forming Mixture formula is defined as the ratio of the weights of liquids in mixture. Ratio of Weights of 2 Immiscible Liquids is denoted by WA/WB symbol.

How to calculate Ratio of Weights of 2 Immiscible Liquids forming Mixture using this online calculator? To use this online calculator for Ratio of Weights of 2 Immiscible Liquids forming Mixture, enter Vapor Pressure of Pure Component A (PAo), Molecular Mass of Liquid A (MA), Vapor Pressure of Pure Component B (PBo) & Molecular Mass of Liquid B (MB) and hit the calculate button. Here is how the Ratio of Weights of 2 Immiscible Liquids forming Mixture calculation can be explained with given input values -> 280.8 = (2700*0.026)/(10*0.025).

### FAQ

What is Ratio of Weights of 2 Immiscible Liquids forming Mixture?
The Ratio of Weights of 2 Immiscible Liquids forming Mixture formula is defined as the ratio of the weights of liquids in mixture and is represented as WA/WB = (PAo*MA)/(PBo*MB) or Ratio of Weights of 2 Immiscible Liquids = (Vapor Pressure of Pure Component A*Molecular Mass of Liquid A)/(Vapor Pressure of Pure Component B*Molecular Mass of Liquid B). Vapor Pressure of Pure Component A is the pressure exerted by a liquid or solid molecules of only A in a closed system in which they are in equilibrium with the vapour phase, The Molecular Mass of Liquid A in a mixture of immiscible liquids, Vapor Pressure of Pure Component B is the pressure exerted by a liquid or solid molecules of only B in a closed system in which they are in equilibrium with the vapour phase & The Molecular Mass of Liquid B in a mixture of immiscible liquids.
How to calculate Ratio of Weights of 2 Immiscible Liquids forming Mixture?
The Ratio of Weights of 2 Immiscible Liquids forming Mixture formula is defined as the ratio of the weights of liquids in mixture is calculated using Ratio of Weights of 2 Immiscible Liquids = (Vapor Pressure of Pure Component A*Molecular Mass of Liquid A)/(Vapor Pressure of Pure Component B*Molecular Mass of Liquid B). To calculate Ratio of Weights of 2 Immiscible Liquids forming Mixture, you need Vapor Pressure of Pure Component A (PAo), Molecular Mass of Liquid A (MA), Vapor Pressure of Pure Component B (PBo) & Molecular Mass of Liquid B (MB). With our tool, you need to enter the respective value for Vapor Pressure of Pure Component A, Molecular Mass of Liquid A, Vapor Pressure of Pure Component B & Molecular Mass of Liquid B and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Ratio of Weights of 2 Immiscible Liquids?
In this formula, Ratio of Weights of 2 Immiscible Liquids uses Vapor Pressure of Pure Component A, Molecular Mass of Liquid A, Vapor Pressure of Pure Component B & Molecular Mass of Liquid B. We can use 1 other way(s) to calculate the same, which is/are as follows -
• Ratio of Weights of 2 Immiscible Liquids = (Partial Pressure of Pure Water*Molecular Mass of Water)/(Vapor Pressure of Pure Component B*Molecular Mass of Liquid B) Let Others Know