Ratio of Weights of 2 Immiscible Liquids forming Mixture Calculator

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Immiscible Liquids

Clausius-Clapeyron Equation

Depression in Freezing Point

Elevation in Boiling Point

Gibb's Phase Rule

Important Formulas of Clausius-Clapeyron Equation

Important Formulas of Colligative Properties

Osmotic Pressure

Relative Lowering of Vapour Pressure

Van't Hoff Factor

✖Vapor Pressure of Pure Component A is the pressure exerted by a liquid or solid molecules of only A in a closed system in which they are in equilibrium with the vapour phase.ⓘ Vapor Pressure of Pure Component A [P_A°]			+10% -10%
✖The Molecular Mass of Liquid A in a mixture of immiscible liquids.ⓘ Molecular Mass of Liquid A [M_A]			+10% -10%
✖Vapor Pressure of Pure Component B is the pressure exerted by a liquid or solid molecules of only B in a closed system in which they are in equilibrium with the vapour phase.ⓘ Vapor Pressure of Pure Component B [P_B°]			+10% -10%
✖The Molecular Mass of Liquid B in a mixture of immiscible liquids.ⓘ Molecular Mass of Liquid B [M_B]			+10% -10%

✖The Ratio of Weights of 2 Immiscible Liquids in a mixture.ⓘ Ratio of Weights of 2 Immiscible Liquids forming Mixture [W_A:B]

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Formula

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Ratio of Weights of 2 Immiscible Liquids forming Mixture

Formula

`"W"_{"A:B"} = (("P"_{"A"}"°")*"M"_{"A"})/(("P"_{"B"}"°")*"M"_{"B"})`

Example

`"4.999245"=("2.7Pa"*"14.72g")/("0.25Pa"*"31.8g")`

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Ratio of Weights of 2 Immiscible Liquids forming Mixture Solution

STEP 0: Pre-Calculation Summary

Formula Used

Ratio of Weights of 2 Immiscible Liquids = (Vapor Pressure of Pure Component A*Molecular Mass of Liquid A)/(Vapor Pressure of Pure Component B*Molecular Mass of Liquid B)
W_A:B = (P_A°*M_A)/(P_B°*M_B)
This formula uses 5 Variables

Variables Used

Ratio of Weights of 2 Immiscible Liquids - The Ratio of Weights of 2 Immiscible Liquids in a mixture.
Vapor Pressure of Pure Component A - (Measured in Pascal) - Vapor Pressure of Pure Component A is the pressure exerted by a liquid or solid molecules of only A in a closed system in which they are in equilibrium with the vapour phase.
Molecular Mass of Liquid A - (Measured in Kilogram) - The Molecular Mass of Liquid A in a mixture of immiscible liquids.
Vapor Pressure of Pure Component B - (Measured in Pascal) - Vapor Pressure of Pure Component B is the pressure exerted by a liquid or solid molecules of only B in a closed system in which they are in equilibrium with the vapour phase.
Molecular Mass of Liquid B - (Measured in Kilogram) - The Molecular Mass of Liquid B in a mixture of immiscible liquids.

STEP 1: Convert Input(s) to Base Unit

Vapor Pressure of Pure Component A: 2.7 Pascal --> 2.7 Pascal No Conversion Required
Molecular Mass of Liquid A: 14.72 Gram --> 0.01472 Kilogram (Check conversion here)
Vapor Pressure of Pure Component B: 0.25 Pascal --> 0.25 Pascal No Conversion Required
Molecular Mass of Liquid B: 31.8 Gram --> 0.0318 Kilogram (Check conversion here)

STEP 2: Evaluate Formula

Substituting Input Values in Formula

W_A:B = (P_A°*M_A)/(P_B°*M_B) --> (2.7*0.01472)/(0.25*0.0318)

Evaluating ... ...

W_A:B = 4.99924528301887

STEP 3: Convert Result to Output's Unit

4.99924528301887 --> No Conversion Required

FINAL ANSWER

4.99924528301887 ≈ 4.999245 <-- Ratio of Weights of 2 Immiscible Liquids

(Calculation completed in 00.004 seconds)

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Home » Chemistry » Solution and Colligative properties » Immiscible Liquids » Ratio of Weights of 2 Immiscible Liquids forming Mixture

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< 19 Immiscible Liquids Calculators

Total Pressure of Mixture of Water with Liquid given Vapour Pressure

Go Total Pressure of Mixture of Liquid with Water = Vapor Pressure of Pure Component B+((Weight of Water in Immiscible Mixture*Vapor Pressure of Pure Component B*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Water))

Total Pressure of Mixture of Liquid with Water given Vapour Pressure of Water

Go Total Pressure of Mixture of Liquid with Water = Partial Pressure of Pure Water+((Weight of Liquid B*Partial Pressure of Pure Water*Molecular Mass of Water)/(Weight of Water in Immiscible Mixture*Molecular Mass of Liquid B))

Total Vapour Pressure of Mixture of given Partial Pressure of One Liquid

Go Total Pressure of Mixture of Immiscible Liquids = Vapor Pressure of Pure Component B+((Vapor Pressure of Pure Component B*Weight of Liquid A*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Liquid A))

Weight of Water required to form Immiscible Mixture with Liquid given Weight

Go Weight of Water in Immiscible Mixture = (Weight of Liquid B*Partial Pressure of Pure Water*Molecular Mass of Water)/(Vapor Pressure of Pure Component B*Molecular Mass of Liquid B)

Weight of Liquid required to form Immiscible Mixture with Water

Go Weight of Liquid B = (Weight of Water in Immiscible Mixture*Vapor Pressure of Pure Component B*Molecular Mass of Liquid B)/(Partial Pressure of Pure Water*Molecular Mass of Water)

Vapour Pressure of Liquid forming Immiscible Mixture with Water

Go Vapor Pressure of Pure Component B = (Weight of Liquid B*Partial Pressure of Pure Water*Molecular Mass of Water)/(Weight of Water in Immiscible Mixture*Molecular Mass of Liquid B)

Vapour Pressure of Water forming Immiscible Mixture with Liquid

Go Partial Pressure of Pure Water = (Weight of Water in Immiscible Mixture*Vapor Pressure of Pure Component B*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Water)

Molecular Mass of Liquid forming Immiscible Mixture with Water

Go Molecular Mass of Liquid B = (Partial Pressure of Pure Water*Molecular Mass of Water*Weight of Liquid B)/(Vapor Pressure of Pure Component B*Weight of Water in Immiscible Mixture)

Molecular Mass of Liquid in Mixture of Two Immiscible Liquids given Weight of Liquids

Go Molecular Mass of Liquid A = (Weight of Liquid A*Molecular Mass of Liquid B*Vapor Pressure of Pure Component B)/(Vapor Pressure of Pure Component A*Weight of Liquid B)

Partial Vapour Pressure of Immiscible Liquid given Partial Pressure of other Liquid

Go Vapor Pressure of Pure Component A = (Weight of Liquid A*Molecular Mass of Liquid B*Vapor Pressure of Pure Component B)/(Molecular Mass of Liquid A*Weight of Liquid B)

Weight of Liquid in Mixture of 2 Immiscible Liquids given Weight of other Liquid

Go Weight of Liquid A = (Vapor Pressure of Pure Component A*Molecular Mass of Liquid A*Weight of Liquid B)/(Vapor Pressure of Pure Component B*Molecular Mass of Liquid B)

Ratio of Molecular Masses of Water to Liquid forming Immiscible Mixture

Go Ratio of Molecular Masses of 2 Immiscible Liquids = (Weight of Water in Immiscible Mixture*Vapor Pressure of Pure Component B)/(Partial Pressure of Pure Water*Weight of Liquid B)

Ratio of Weights of 2 Immiscible Liquids forming Mixture

Go Ratio of Weights of 2 Immiscible Liquids = (Vapor Pressure of Pure Component A*Molecular Mass of Liquid A)/(Vapor Pressure of Pure Component B*Molecular Mass of Liquid B)

Ratio of Molecular Mass of 2 Immiscible Liquids

Go Ratio of Molecular Masses of 2 Immiscible Liquids = (Vapor Pressure of Pure Component B*Weight of Liquid A)/(Vapor Pressure of Pure Component A*Weight of Liquid B)

Ratio of Partial Vapour Pressures of Water with Liquid forming Immiscible Mixture

Go Ratio of Partial Pressures of Water and Liquid = (Weight of Water in Immiscible Mixture*Molecular Mass of Liquid B)/(Molecular Mass of Water*Weight of Liquid B)

Ratio of Weights of Water to Liquid forming Immiscible Mixture

Go Ratio of Weights of Water and Liquid = (Partial Pressure of Pure Water*Molecular Mass of Water)/(Vapor Pressure of Pure Component B*Molecular Mass of Liquid B)

Ratio of Partial Vapour Pressures of 2 Immiscible Liquids given Weight and Molecular Mass

Go Ratio of Partial Pressures of 2 Immiscible Liquids = (Weight of Liquid A*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Liquid A)

Total Pressure of Mixture of Two Immiscible Liquids

Go Total Pressure of Mixture of Immiscible Liquids = Vapor Pressure of Pure Component A+Vapor Pressure of Pure Component B

Ratio of Partial Pressure of 2 Immiscible Liquids given Number of Moles

Go Ratio of Partial Pressures of 2 Immiscible Liquids = Number of Moles of Liquid A/Number of Moles of Liquid B

Ratio of Weights of 2 Immiscible Liquids forming Mixture Formula

How does both liquids contribute to pressure of a mixture of 2 immiscible liquids?

Obviously if you have two immiscible liquids in a closed flask and keep everything still, the vapor pressure you measure will simply be the vapor pressure of the one which is floating on top. There is no way that the bottom liquid can turn to vapor. The top one is sealing it in. For the purposes of the rest of this topic, we always assume that the mixture is being stirred or agitated in some way so that the two liquids are broken up into drops. At any one time there will be drops of both liquids on the surface. That means that both of them contribute to the overall vapor pressure of the mixture.

How to Calculate Ratio of Weights of 2 Immiscible Liquids forming Mixture?

Ratio of Weights of 2 Immiscible Liquids forming Mixture calculator uses Ratio of Weights of 2 Immiscible Liquids = (Vapor Pressure of Pure Component A*Molecular Mass of Liquid A)/(Vapor Pressure of Pure Component B*Molecular Mass of Liquid B) to calculate the Ratio of Weights of 2 Immiscible Liquids, The Ratio of Weights of 2 Immiscible Liquids forming Mixture formula is defined as the ratio of the weights of liquids in mixture. Ratio of Weights of 2 Immiscible Liquids is denoted by W_A:B symbol.

How to calculate Ratio of Weights of 2 Immiscible Liquids forming Mixture using this online calculator? To use this online calculator for Ratio of Weights of 2 Immiscible Liquids forming Mixture, enter Vapor Pressure of Pure Component A (P_A°), Molecular Mass of Liquid A (M_A), Vapor Pressure of Pure Component B (P_B°) & Molecular Mass of Liquid B (M_B) and hit the calculate button. Here is how the Ratio of Weights of 2 Immiscible Liquids forming Mixture calculation can be explained with given input values -> 4.999245 = (2.7*0.01472)/(0.25*0.0318).

FAQ

What is Ratio of Weights of 2 Immiscible Liquids forming Mixture?

The Ratio of Weights of 2 Immiscible Liquids forming Mixture formula is defined as the ratio of the weights of liquids in mixture and is represented as W_A:B = (P_A°*M_A)/(P_B°*M_B) or Ratio of Weights of 2 Immiscible Liquids = (Vapor Pressure of Pure Component A*Molecular Mass of Liquid A)/(Vapor Pressure of Pure Component B*Molecular Mass of Liquid B). Vapor Pressure of Pure Component A is the pressure exerted by a liquid or solid molecules of only A in a closed system in which they are in equilibrium with the vapour phase, The Molecular Mass of Liquid A in a mixture of immiscible liquids, Vapor Pressure of Pure Component B is the pressure exerted by a liquid or solid molecules of only B in a closed system in which they are in equilibrium with the vapour phase & The Molecular Mass of Liquid B in a mixture of immiscible liquids.

How to calculate Ratio of Weights of 2 Immiscible Liquids forming Mixture?

The Ratio of Weights of 2 Immiscible Liquids forming Mixture formula is defined as the ratio of the weights of liquids in mixture is calculated using Ratio of Weights of 2 Immiscible Liquids = (Vapor Pressure of Pure Component A*Molecular Mass of Liquid A)/(Vapor Pressure of Pure Component B*Molecular Mass of Liquid B). To calculate Ratio of Weights of 2 Immiscible Liquids forming Mixture, you need Vapor Pressure of Pure Component A (P_A°), Molecular Mass of Liquid A (M_A), Vapor Pressure of Pure Component B (P_B°) & Molecular Mass of Liquid B (M_B). With our tool, you need to enter the respective value for Vapor Pressure of Pure Component A, Molecular Mass of Liquid A, Vapor Pressure of Pure Component B & Molecular Mass of Liquid B and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

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