Reduced Temperature of Real Gas using Clausius Equation given Critical and Actual Parameters Calculator

✖Pressure is the force applied perpendicular to the surface of an object per unit area over which that force is distributed.ⓘ Pressure [p]			+10% -10%
✖Clausius parameter a is an empirical parameter characteristic to equation obtained from Clausius model of real gas.ⓘ Clausius Parameter a [a]			+10% -10%
✖Molar Volume is the volume occupied by one mole of a real gas at standard temperature and pressure.ⓘ Molar Volume [V_m]			+10% -10%
✖Clausius parameter c is an empirical parameter characteristic to equation obtained from Clausius model of real gas.ⓘ Clausius Parameter c [c]			+10% -10%
✖Clausius Parameter b for Real Gas is an empirical parameter characteristic to equation obtained from Clausius model of real gas.ⓘ Clausius Parameter b for Real Gas [b']			+10% -10%
✖Critical Temperature For Clausius Model is the highest temperature at which the substance can exist as a liquid. At this phase boundaries vanish, the substance can exist both as a liquid and vapor.ⓘ Critical Temperature For Clausius Model [T'_c]			+10% -10%

✖Reduced Temperature is the ratio of the actual temperature of the fluid to its critical temperature. It is dimensionless.ⓘ Reduced Temperature of Real Gas using Clausius Equation given Critical and Actual Parameters [T_r]

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Formula

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Reduced Temperature of Real Gas using Clausius Equation given Critical and Actual Parameters

Formula

`"T"_{"r"} = (("p"+("a"/((("V"_{"m"}+"c")^2))))*(("V"_{"m"}-"b'")/"[R]"))/"T'"_{"c"}`

Example

`"13.95756"=(("800Pa"+("0.1"/((("22.4m³/mol"+"0.0002")^2))))*(("22.4m³/mol"-"2.43E^-3")/"[R]"))/"154.4K"`

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Reduced Temperature of Real Gas using Clausius Equation given Critical and Actual Parameters Solution

STEP 0: Pre-Calculation Summary

Formula Used

Reduced Temperature = ((Pressure+(Clausius Parameter a/(((Molar Volume+Clausius Parameter c)^2))))*((Molar Volume-Clausius Parameter b for Real Gas)/[R]))/Critical Temperature For Clausius Model
T_r = ((p+(a/(((V_m+c)^2))))*((V_m-b')/[R]))/T'_c
This formula uses 1 Constants, 7 Variables

Constants Used

[R] - Universal gas constant Value Taken As 8.31446261815324

Variables Used

Reduced Temperature - Reduced Temperature is the ratio of the actual temperature of the fluid to its critical temperature. It is dimensionless.
Pressure - (Measured in Pascal) - Pressure is the force applied perpendicular to the surface of an object per unit area over which that force is distributed.
Clausius Parameter a - Clausius parameter a is an empirical parameter characteristic to equation obtained from Clausius model of real gas.
Molar Volume - (Measured in Cubic Meter per Mole) - Molar Volume is the volume occupied by one mole of a real gas at standard temperature and pressure.
Clausius Parameter c - Clausius parameter c is an empirical parameter characteristic to equation obtained from Clausius model of real gas.
Clausius Parameter b for Real Gas - Clausius Parameter b for Real Gas is an empirical parameter characteristic to equation obtained from Clausius model of real gas.
Critical Temperature For Clausius Model - (Measured in Kelvin) - Critical Temperature For Clausius Model is the highest temperature at which the substance can exist as a liquid. At this phase boundaries vanish, the substance can exist both as a liquid and vapor.

STEP 1: Convert Input(s) to Base Unit

Pressure: 800 Pascal --> 800 Pascal No Conversion Required
Clausius Parameter a: 0.1 --> No Conversion Required
Molar Volume: 22.4 Cubic Meter per Mole --> 22.4 Cubic Meter per Mole No Conversion Required
Clausius Parameter c: 0.0002 --> No Conversion Required
Clausius Parameter b for Real Gas: 0.00243 --> No Conversion Required
Critical Temperature For Clausius Model: 154.4 Kelvin --> 154.4 Kelvin No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

T_r = ((p+(a/(((V_m+c)^2))))*((V_m-b')/[R]))/T'_c --> ((800+(0.1/(((22.4+0.0002)^2))))*((22.4-0.00243)/[R]))/154.4

Evaluating ... ...

T_r = 13.95756042597

STEP 3: Convert Result to Output's Unit

13.95756042597 --> No Conversion Required

FINAL ANSWER

13.95756042597 ≈ 13.95756 <-- Reduced Temperature

(Calculation completed in 00.004 seconds)

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< 9 Reduced Temperature of Real Gas Calculators

Reduced Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters

Go Reduced Temperature = (((Reduced Pressure*Critical Pressure of Real Gas)+(Clausius Parameter a/((((Reduced Molar Volume for Real Gas*Critical Molar Volume)+Clausius Parameter c)^2))))*(((Reduced Molar Volume for Real Gas*Critical Molar Volume)-Clausius Parameter b for Real Gas)/[R]))/Critical Temperature For Clausius Model

Reduced Temperature of Real Gas using Clausius Equation given Critical and Actual Parameters

Go Reduced Temperature = ((Pressure+(Clausius Parameter a/(((Molar Volume+Clausius Parameter c)^2))))*((Molar Volume-Clausius Parameter b for Real Gas)/[R]))/Critical Temperature For Clausius Model

Reduced Temperature of Real Gas using Clausius Equation given Reduced and Actual Parameters

Go Reduced Temperature given RP AP = ((Pressure+(Clausius Parameter a/(((Molar Volume+Clausius Parameter c)^2))))*((Molar Volume-Clausius Parameter b for Real Gas)/[R]))/Temperature of Real Gas

Reduced Temperature of Real Gas using Clausius Parameter b given Reduced and Actual Parameters

Go Reduced Temperature = Temperature of Real Gas/(((Volume of Real Gas/Reduced Volume)-Clausius Parameter b for Real Gas)*((4*(Pressure/Reduced Pressure))/[R]))

Reduced Temperature of Real Gas given Clausius Parameter c given Reduced and Actual Parameters

Go Reduced Temperature = Temperature of Real Gas/(((Clausius Parameter c+(Volume of Real Gas/Reduced Volume))*8*(Pressure/Reduced Pressure))/(3*[R]))

Reduced Temperature of Real Gas using Clausius Parameter b and Actual Parameters

Go Reduced Temperature = Temperature of Real Gas/((Critical Volume-Clausius Parameter b for Real Gas)*((4*Critical Pressure of Real Gas)/[R]))

Reduced Temperature of Real Gas given Clausius Parameter c and Actual Parameters

Go Reduced Temperature = Temperature of Real Gas/(((Clausius Parameter c+Critical Volume)*8*Critical Pressure of Real Gas)/(3*[R]))

Reduced Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters

Go Reduced Temperature = Temperature of Real Gas/(((Clausius Parameter a*64*(Pressure/Reduced Pressure))/(27*([R]^2)))^(1/3))

Reduced Temperature of Real Gas given Clausius Parameter and Actual Parameters

Go Reduced Temperature = Temperature of Real Gas/(((Clausius Parameter a*64*Critical Pressure of Real Gas)/(27*([R]^2)))^(1/3))

Reduced Temperature of Real Gas using Clausius Equation given Critical and Actual Parameters Formula

What are Real Gases?

Real gases are non ideal gases whose molecules occupy space and have interactions; consequently, they do not adhere to the ideal gas law. To understand the behavior of real gases, the following must be taken into account:
- compressibility effects;
- variable specific heat capacity;
- van der Waals forces;
- non-equilibrium thermodynamic effects;
- issues with molecular dissociation and elementary reactions with variable composition.

How to Calculate Reduced Temperature of Real Gas using Clausius Equation given Critical and Actual Parameters?

Reduced Temperature of Real Gas using Clausius Equation given Critical and Actual Parameters calculator uses Reduced Temperature = ((Pressure+(Clausius Parameter a/(((Molar Volume+Clausius Parameter c)^2))))*((Molar Volume-Clausius Parameter b for Real Gas)/[R]))/Critical Temperature For Clausius Model to calculate the Reduced Temperature, The Reduced Temperature of real gas using Clausius equation given critical and actual parameters formula is defined as the ratio of the actual temperature of the fluid to its critical temperature. It is dimensionless. Reduced Temperature is denoted by T_r symbol.

How to calculate Reduced Temperature of Real Gas using Clausius Equation given Critical and Actual Parameters using this online calculator? To use this online calculator for Reduced Temperature of Real Gas using Clausius Equation given Critical and Actual Parameters, enter Pressure (p), Clausius Parameter a (a), Molar Volume (V_m), Clausius Parameter c (c), Clausius Parameter b for Real Gas (b') & Critical Temperature For Clausius Model (T'_c) and hit the calculate button. Here is how the Reduced Temperature of Real Gas using Clausius Equation given Critical and Actual Parameters calculation can be explained with given input values -> 3.33083 = ((800+(0.1/(((22.4+0.0002)^2))))*((22.4-0.00243)/[R]))/154.4.

FAQ

What is Reduced Temperature of Real Gas using Clausius Equation given Critical and Actual Parameters?

The Reduced Temperature of real gas using Clausius equation given critical and actual parameters formula is defined as the ratio of the actual temperature of the fluid to its critical temperature. It is dimensionless and is represented as T_r = ((p+(a/(((V_m+c)^2))))*((V_m-b')/[R]))/T'_c or Reduced Temperature = ((Pressure+(Clausius Parameter a/(((Molar Volume+Clausius Parameter c)^2))))*((Molar Volume-Clausius Parameter b for Real Gas)/[R]))/Critical Temperature For Clausius Model. Pressure is the force applied perpendicular to the surface of an object per unit area over which that force is distributed, Clausius parameter a is an empirical parameter characteristic to equation obtained from Clausius model of real gas, Molar Volume is the volume occupied by one mole of a real gas at standard temperature and pressure, Clausius parameter c is an empirical parameter characteristic to equation obtained from Clausius model of real gas, Clausius Parameter b for Real Gas is an empirical parameter characteristic to equation obtained from Clausius model of real gas & Critical Temperature For Clausius Model is the highest temperature at which the substance can exist as a liquid. At this phase boundaries vanish, the substance can exist both as a liquid and vapor.

How to calculate Reduced Temperature of Real Gas using Clausius Equation given Critical and Actual Parameters?

The Reduced Temperature of real gas using Clausius equation given critical and actual parameters formula is defined as the ratio of the actual temperature of the fluid to its critical temperature. It is dimensionless is calculated using Reduced Temperature = ((Pressure+(Clausius Parameter a/(((Molar Volume+Clausius Parameter c)^2))))*((Molar Volume-Clausius Parameter b for Real Gas)/[R]))/Critical Temperature For Clausius Model. To calculate Reduced Temperature of Real Gas using Clausius Equation given Critical and Actual Parameters, you need Pressure (p), Clausius Parameter a (a), Molar Volume (V_m), Clausius Parameter c (c), Clausius Parameter b for Real Gas (b') & Critical Temperature For Clausius Model (T'_c). With our tool, you need to enter the respective value for Pressure, Clausius Parameter a, Molar Volume, Clausius Parameter c, Clausius Parameter b for Real Gas & Critical Temperature For Clausius Model and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Reduced Temperature?

In this formula, Reduced Temperature uses Pressure, Clausius Parameter a, Molar Volume, Clausius Parameter c, Clausius Parameter b for Real Gas & Critical Temperature For Clausius Model. We can use 7 other way(s) to calculate the same, which is/are as follows -

Reduced Temperature = Temperature of Real Gas/(((Clausius Parameter a*64*Critical Pressure of Real Gas)/(27*([R]^2)))^(1/3))
Reduced Temperature = Temperature of Real Gas/(((Clausius Parameter a*64*(Pressure/Reduced Pressure))/(27*([R]^2)))^(1/3))
Reduced Temperature = Temperature of Real Gas/(((Clausius Parameter c+Critical Volume)*8*Critical Pressure of Real Gas)/(3*[R]))
Reduced Temperature = Temperature of Real Gas/(((Clausius Parameter c+(Volume of Real Gas/Reduced Volume))*8*(Pressure/Reduced Pressure))/(3*[R]))
Reduced Temperature = (((Reduced Pressure*Critical Pressure of Real Gas)+(Clausius Parameter a/((((Reduced Molar Volume for Real Gas*Critical Molar Volume)+Clausius Parameter c)^2))))*(((Reduced Molar Volume for Real Gas*Critical Molar Volume)-Clausius Parameter b for Real Gas)/[R]))/Critical Temperature For Clausius Model
Reduced Temperature = Temperature of Real Gas/((Critical Volume-Clausius Parameter b for Real Gas)*((4*Critical Pressure of Real Gas)/[R]))
Reduced Temperature = Temperature of Real Gas/(((Volume of Real Gas/Reduced Volume)-Clausius Parameter b for Real Gas)*((4*(Pressure/Reduced Pressure))/[R]))

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