Specific Capacity of Open Well with Base 10 Calculator

✖Time can be defined as the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future.ⓘ Time [t]			+10% -10%
✖Depression Head 1 is the difference of level of waters table and the water level in the well when pumping stopped.ⓘ Depression Head 1 [h₁]			+10% -10%
✖Depression Head 2 is the difference of level of waters table and the water level in the well when pumping stopped.ⓘ Depression Head 2 [h₂]			+10% -10%

✖Specific Capacity of an open well.ⓘ Specific Capacity of Open Well with Base 10 [KA]

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Formula

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Specific Capacity of Open Well with Base 10

Formula

`"KA" = (2.303/"t")*log(("h"_{"1"}/"h"_{"2"}),10)`

Example

`"1.33472m/h"=(2.303/"4h")*log(("27m"/"10m"),10)`

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Specific Capacity of Open Well with Base 10 Solution

STEP 0: Pre-Calculation Summary

Formula Used

Specific Capacity = (2.303/Time)*log((Depression Head 1/Depression Head 2),10)
KA = (2.303/t)*log((h₁/h₂),10)
This formula uses 1 Functions, 4 Variables

Functions Used

log - Logarithmic function is an inverse function to exponentiation., log(Base, Number)

Variables Used

Specific Capacity - (Measured in Meter per Second) - Specific Capacity of an open well.
Time - (Measured in Second) - Time can be defined as the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future.
Depression Head 1 - (Measured in Meter) - Depression Head 1 is the difference of level of waters table and the water level in the well when pumping stopped.
Depression Head 2 - (Measured in Meter) - Depression Head 2 is the difference of level of waters table and the water level in the well when pumping stopped.

STEP 1: Convert Input(s) to Base Unit

Time: 4 Hour --> 14400 Second (Check conversion here)
Depression Head 1: 27 Meter --> 27 Meter No Conversion Required
Depression Head 2: 10 Meter --> 10 Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

KA = (2.303/t)*log((h₁/h₂),10) --> (2.303/14400)*log((27/10),10)

Evaluating ... ...

KA = 0.000370755656464019

STEP 3: Convert Result to Output's Unit

0.000370755656464019 Meter per Second -->1.33472036327047 Meter per Hour (Check conversion here)

FINAL ANSWER

1.33472036327047 ≈ 1.33472 Meter per Hour <-- Specific Capacity

(Calculation completed in 00.004 seconds)

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Home » Engineering » Civil » Environmental Engineering » Water Resources : Ground Water » Yield of an Open Well » Constant Level Pumping Test » Specific Capacity » Specific Capacity of Open Well with Base 10

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Created by Suraj Kumar

Birsa Institute of Technology (BIT), Sindri

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< 4 Specific Capacity Calculators

Specific Capacity of Open Well

Go Specific Capacity = (1/Time)*log((Depression Head 1/Depression Head 2),e)

Specific Capacity of Open Well with Base 10

Go Specific Capacity = (2.303/Time)*log((Depression Head 1/Depression Head 2),10)

Specific Capacity given Discharge from Well

Go Specific Capacity = Discharge/(Cross-Sectional Area*Constant Depression Head)

Specific Capacity of open Well given Constant Depending upon Soil at Base

Go Specific Capacity = Constant/Cross-Sectional Area

Specific Capacity of Open Well with Base 10 Formula

Specific Capacity = (2.303/Time)*log((Depression Head 1/Depression Head 2),10)
KA = (2.303/t)*log((h₁/h₂),10)

What is specific capacity ?

Specific capacity is a quantity that which a water well can produce per unit of drawdown. It is normally obtained from a step drawdown test.

How to Calculate Specific Capacity of Open Well with Base 10?

Specific Capacity of Open Well with Base 10 calculator uses Specific Capacity = (2.303/Time)*log((Depression Head 1/Depression Head 2),10) to calculate the Specific Capacity, The Specific Capacity of Open Well with Base 10 calculates value of specific capacity of open well when we have prior information of other parameters used. Specific Capacity is denoted by KA symbol.

How to calculate Specific Capacity of Open Well with Base 10 using this online calculator? To use this online calculator for Specific Capacity of Open Well with Base 10, enter Time (t), Depression Head 1 (h₁) & Depression Head 2 (h₂) and hit the calculate button. Here is how the Specific Capacity of Open Well with Base 10 calculation can be explained with given input values -> 4804.993 = (2.303/14400)*log((27/10),10).

FAQ

What is Specific Capacity of Open Well with Base 10?

The Specific Capacity of Open Well with Base 10 calculates value of specific capacity of open well when we have prior information of other parameters used and is represented as KA = (2.303/t)*log((h₁/h₂),10) or Specific Capacity = (2.303/Time)*log((Depression Head 1/Depression Head 2),10). Time can be defined as the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future, Depression Head 1 is the difference of level of waters table and the water level in the well when pumping stopped & Depression Head 2 is the difference of level of waters table and the water level in the well when pumping stopped.

How to calculate Specific Capacity of Open Well with Base 10?

The Specific Capacity of Open Well with Base 10 calculates value of specific capacity of open well when we have prior information of other parameters used is calculated using Specific Capacity = (2.303/Time)*log((Depression Head 1/Depression Head 2),10). To calculate Specific Capacity of Open Well with Base 10, you need Time (t), Depression Head 1 (h₁) & Depression Head 2 (h₂). With our tool, you need to enter the respective value for Time, Depression Head 1 & Depression Head 2 and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Specific Capacity?

In this formula, Specific Capacity uses Time, Depression Head 1 & Depression Head 2. We can use 3 other way(s) to calculate the same, which is/are as follows -

Specific Capacity = (1/Time)*log((Depression Head 1/Depression Head 2),e)
Specific Capacity = Constant/Cross-Sectional Area
Specific Capacity = Discharge/(Cross-Sectional Area*Constant Depression Head)

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