Time in Hours given Clay Soil Calculator

✖Depression Head 1 is the difference of level of waters table and the water level in the well when pumping stopped.ⓘ Depression Head 1 [h₁]			+10% -10%
✖Depression Head 2 is the difference of level of waters table and the water level in the well when pumping stopped.ⓘ Depression Head 2 [h₂]			+10% -10%

✖Time can be defined as the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future.ⓘ Time in Hours given Clay Soil [t]

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Formula

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Time in Hours given Clay Soil

Formula

`"t" = (1/0.25)*log(("h"_{"1"}/"h"_{"2"}),e)`

Example

`"4.027176h"=(1/0.25)*log(("27m"/"10m"),e)`

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Time in Hours given Clay Soil Solution

STEP 0: Pre-Calculation Summary

Formula Used

Time = (1/0.25)*log((Depression Head 1/Depression Head 2),e)
t = (1/0.25)*log((h₁/h₂),e)
This formula uses 1 Constants, 1 Functions, 3 Variables

Constants Used

e - Napier's constant Value Taken As 2.71828182845904523536028747135266249

Functions Used

log - Logarithmic function is an inverse function to exponentiation., log(Base, Number)

Variables Used

Time - (Measured in Hour) - Time can be defined as the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future.
Depression Head 1 - (Measured in Meter) - Depression Head 1 is the difference of level of waters table and the water level in the well when pumping stopped.
Depression Head 2 - (Measured in Meter) - Depression Head 2 is the difference of level of waters table and the water level in the well when pumping stopped.

STEP 1: Convert Input(s) to Base Unit

Depression Head 1: 27 Meter --> 27 Meter No Conversion Required
Depression Head 2: 10 Meter --> 10 Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

t = (1/0.25)*log((h₁/h₂),e) --> (1/0.25)*log((27/10),e)

Evaluating ... ...

t = 4.02717629979865

STEP 3: Convert Result to Output's Unit

14497.8346792751 Second -->4.02717629979865 Hour (Check conversion here)

FINAL ANSWER

4.02717629979865 ≈ 4.027176 Hour <-- Time

(Calculation completed in 00.004 seconds)

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Home » Engineering » Civil » Environmental Engineering » Water Resources : Ground Water » Yield of an Open Well » Recuperation Test » Recuperate Time » Time in Hours given Clay Soil

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Created by Suraj Kumar

Birsa Institute of Technology (BIT), Sindri

Suraj Kumar has created this Calculator and 2200+ more calculators!

Verified by Ishita Goyal

Meerut Institute of Engineering and Technology (MIET), Meerut

Ishita Goyal has verified this Calculator and 2600+ more calculators!

< 9 Recuperate Time Calculators

Time in Hours given Constant Depression Head and Area of Well

Go Time = (2.303*Cross-Sectional Area*Constant Depression Head*log((Depression Head 1/Depression Head 2),10))/Discharge

Time in Hours given Constant Depending upon Soil at Base

Go Time = (Cross-Sectional Area/Constant)*log((Depression Head 1/Depression Head 2),e)

Time in Hours given Constant Depending upon Soil at Base with Base 10

Go Time = ((Cross-Sectional Area*2.303)/Constant)*log((Depression Head 1/Depression Head 2),10)

Time in Hours given Clay Soil

Go Time = (1/0.25)*log((Depression Head 1/Depression Head 2),e)

Time in Hours given Fine Sand

Go Time = (1/0.5)*log((Depression Head 1/Depression Head 2),e)

Time in Hours given Coarse Sand

Go Time = log((Depression Head 1/Depression Head 2),e)

Time in Hours with Base 10 given Clay Soil

Go Time = (2.303/0.25)*log((Depression Head 1/Depression Head 2),10)

Time in Hours with Base 10 given Fine Sand

Go Time = (2.303/0.5)*log((Depression Head 1/Depression Head 2),10)

Time in Hours with Base 10 given Coarse Sand

Go Time = (2.303/1)*log((Depression Head 1/Depression Head 2),10)

Time in Hours given Clay Soil Formula

Time = (1/0.25)*log((Depression Head 1/Depression Head 2),e)
t = (1/0.25)*log((h₁/h₂),e)

What is clay soil ?

Clay is a type of fine-grained natural soil material containing clay minerals. Clays develop plasticity when wet, due to a molecular film of water surrounding the clay particles, but become hard, brittle and non–plastic upon drying or firing.

How to Calculate Time in Hours given Clay Soil?

Time in Hours given Clay Soil calculator uses Time = (1/0.25)*log((Depression Head 1/Depression Head 2),e) to calculate the Time, Time in Hours given Clay Soil calculates value of time in hours when we have prior information of other parameters used. Time is denoted by t symbol.

How to calculate Time in Hours given Clay Soil using this online calculator? To use this online calculator for Time in Hours given Clay Soil, enter Depression Head 1 (h₁) & Depression Head 2 (h₂) and hit the calculate button. Here is how the Time in Hours given Clay Soil calculation can be explained with given input values -> 0.001119 = (1/0.25)*log((27/10),e).

FAQ

What is Time in Hours given Clay Soil?

Time in Hours given Clay Soil calculates value of time in hours when we have prior information of other parameters used and is represented as t = (1/0.25)*log((h₁/h₂),e) or Time = (1/0.25)*log((Depression Head 1/Depression Head 2),e). Depression Head 1 is the difference of level of waters table and the water level in the well when pumping stopped & Depression Head 2 is the difference of level of waters table and the water level in the well when pumping stopped.

How to calculate Time in Hours given Clay Soil?

Time in Hours given Clay Soil calculates value of time in hours when we have prior information of other parameters used is calculated using Time = (1/0.25)*log((Depression Head 1/Depression Head 2),e). To calculate Time in Hours given Clay Soil, you need Depression Head 1 (h₁) & Depression Head 2 (h₂). With our tool, you need to enter the respective value for Depression Head 1 & Depression Head 2 and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Time?

In this formula, Time uses Depression Head 1 & Depression Head 2. We can use 8 other way(s) to calculate the same, which is/are as follows -

Time = (2.303/0.25)*log((Depression Head 1/Depression Head 2),10)
Time = (1/0.5)*log((Depression Head 1/Depression Head 2),e)
Time = (2.303/0.5)*log((Depression Head 1/Depression Head 2),10)
Time = log((Depression Head 1/Depression Head 2),e)
Time = (2.303/1)*log((Depression Head 1/Depression Head 2),10)
Time = (Cross-Sectional Area/Constant)*log((Depression Head 1/Depression Head 2),e)
Time = ((Cross-Sectional Area*2.303)/Constant)*log((Depression Head 1/Depression Head 2),10)
Time = (2.303*Cross-Sectional Area*Constant Depression Head*log((Depression Head 1/Depression Head 2),10))/Discharge

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