Volume of Conductor Material using Constant(DC Three-Wire US) Calculator

Volume Of Conductor - (Measured in Cubic Meter) - Volume Of Conductor the 3-dimensional space enclosed by a conductor material.
Constant underground dc - Constant underground dc is used to define all the constant variables in the equation.

STEP 1: Convert Input(s) to Base Unit

Constant underground dc: 6 --> No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

V = 1.25*K --> 1.25*6

Evaluating ... ...

V = 7.5

STEP 3: Convert Result to Output's Unit

7.5 Cubic Meter --> No Conversion Required

FINAL ANSWER

7.5 Cubic Meter <-- Volume Of Conductor

(Calculation completed in 00.004 seconds)

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Created by Urvi Rathod

Vishwakarma Government Engineering College (VGEC), Ahmedabad

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Osmania University (OU), Hyderabad

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< 15 Wire Parameters Calculators

Volume of Conductor Material using Resistance (DC Three-Wire US)

Go Volume Of Conductor = (5*(Power Transmitted^2)*Resistance underground DC*Length of Wire DC*Area of underground dc wire)/(Line Losses*(Maximum Voltage^2))

Length using Volume of Conductor Material(DC Three-Wire US)

Go Length of Wire DC = sqrt(Volume Of Conductor*Line Losses*(Maximum Voltage^2)/((5)*Resistivity*(Power Transmitted^2)))

Length using Area of X-Section (DC Three-Wire US)

Go Length of Wire DC = Area of underground dc wire*Line Losses*(Maximum Voltage^2)/(2*Resistivity*(Power Transmitted^2))

Area of X-Section (DC Three-Wire US)

Go Area of underground dc wire = 2*(Power Transmitted^2)*Resistivity*Length of Wire DC/(Line Losses*(Maximum Voltage^2))

Line Losses (DC Three-Wire US)

Go Line Losses = 2*(Power Transmitted^2)*Resistivity*Length of Wire DC/((Maximum Voltage^2)*Area of underground dc wire)

Volume of Conductor Material (DC Three-Wire US)

Go Volume Of Conductor = 5*(Power Transmitted^2)*Resistivity*(Length of Wire DC^2)/(Line Losses*(Maximum Voltage^2))

Line Losses using Volume of Conductor Material(DC Three-Wire US)

Go Line Losses = 5*Resistivity*((Power Transmitted*Length of Wire DC)^2)/(Volume Of Conductor*(Maximum Voltage^2))

Line Losses using Area of X-Section (DC Three-Wire US)

Go Line Losses = 2*(Current underground DC^2)*Resistivity*Length of Wire DC/(Area of underground dc wire)

Length using Line Losses (DC Three-Wire US)

Go Length of Wire DC = Area of underground dc wire*Line Losses/(2*Resistivity*(Current underground DC^2))

Volume of Conductor Material using Load Current (DC Three-Wire US)

Go Volume Of Conductor = 5*Resistivity*(Length of Wire DC^2)*(Current underground DC^2)/Line Losses

Line Losses using Resistance (DC Three-Wire US)

Go Line Losses = 2*(Power Transmitted^2)*Resistance underground DC/((Maximum Voltage^2))

Area of X-section using Volume of Conductor Material(DC Three-Wire US)

Go Area of underground dc wire = Volume Of Conductor/(2.5*Length of Wire DC)

Volume of Conductor Material using Area and Length(DC Three-Wire US)

Go Volume Of Conductor = 2.5*Area of underground dc wire*Length of Wire DC

Constant using Volume of Conductor Material(DC Three-Wire US)

Go Constant underground dc = Volume Of Conductor/(1.25)

Volume of Conductor Material using Constant(DC Three-Wire US)

Go Volume Of Conductor = 1.25*Constant underground dc

Volume of Conductor Material using Constant(DC Three-Wire US) Formula

Volume Of Conductor = 1.25*Constant underground dc
V = 1.25*K

What is the volume of conductor material in 3-wire DC underground system?

The volume of conductor material required in this system is 1.25 times that of a 2-wire d.c.system with the one conductor earthed.

How to Calculate Volume of Conductor Material using Constant(DC Three-Wire US)?

Volume of Conductor Material using Constant(DC Three-Wire US) calculator uses Volume Of Conductor = 1.25*Constant underground dc to calculate the Volume Of Conductor, The Volume of Conductor Material using Constant(DC Three-Wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a 3-wire DC underground system. Volume Of Conductor is denoted by V symbol.

How to calculate Volume of Conductor Material using Constant(DC Three-Wire US) using this online calculator? To use this online calculator for Volume of Conductor Material using Constant(DC Three-Wire US), enter Constant underground dc (K) and hit the calculate button. Here is how the Volume of Conductor Material using Constant(DC Three-Wire US) calculation can be explained with given input values -> 7.5 = 1.25*6.

FAQ

What is Volume of Conductor Material using Constant(DC Three-Wire US)?

The Volume of Conductor Material using Constant(DC Three-Wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a 3-wire DC underground system and is represented as V = 1.25*K or Volume Of Conductor = 1.25*Constant underground dc. Constant underground dc is used to define all the constant variables in the equation.

How to calculate Volume of Conductor Material using Constant(DC Three-Wire US)?

The Volume of Conductor Material using Constant(DC Three-Wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a 3-wire DC underground system is calculated using Volume Of Conductor = 1.25*Constant underground dc. To calculate Volume of Conductor Material using Constant(DC Three-Wire US), you need Constant underground dc (K). With our tool, you need to enter the respective value for Constant underground dc and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Volume Of Conductor?

In this formula, Volume Of Conductor uses Constant underground dc. We can use 4 other way(s) to calculate the same, which is/are as follows -

Volume Of Conductor = 2.5*Area of underground dc wire*Length of Wire DC
Volume Of Conductor = 5*Resistivity*(Length of Wire DC^2)*(Current underground DC^2)/Line Losses
Volume Of Conductor = (5*(Power Transmitted^2)*Resistance underground DC*Length of Wire DC*Area of underground dc wire)/(Line Losses*(Maximum Voltage^2))
Volume Of Conductor = 5*(Power Transmitted^2)*Resistivity*(Length of Wire DC^2)/(Line Losses*(Maximum Voltage^2))

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