Volume of Conductor Material using Load Current(1 Phase 3 Wire US) Solution

STEP 0: Pre-Calculation Summary
Formula Used
Volume Of Conductor = 5*Resistivity*(Length of Underground AC Wire^2)*(Current Underground AC^2)/Line Losses
V = 5*ρ*(L^2)*(I^2)/Ploss
This formula uses 5 Variables
Variables Used
Volume Of Conductor - (Measured in Cubic Meter) - Volume Of Conductor the 3-dimensional space enclosed by a conductor material.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.
Current Underground AC - (Measured in Ampere) - Current Underground AC is defined as the current flowing through the overhead ac supply wire.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Underground AC line when in use.
STEP 1: Convert Input(s) to Base Unit
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required
Current Underground AC: 9 Ampere --> 9 Ampere No Conversion Required
Line Losses: 2.67 Watt --> 2.67 Watt No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
V = 5*ρ*(L^2)*(I^2)/Ploss --> 5*1.7E-05*(24^2)*(9^2)/2.67
Evaluating ... ...
V = 1.48530337078652
STEP 3: Convert Result to Output's Unit
1.48530337078652 Cubic Meter --> No Conversion Required
FINAL ANSWER
1.48530337078652 1.485303 Cubic Meter <-- Volume Of Conductor
(Calculation completed in 00.004 seconds)

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14 Wire Parameters Calculators

Volume of Conductor Material using Resistance (1 Phase 3 Wire US)
Go Volume Of Conductor = (10*(Power Transmitted^2)*Resistance Underground AC*Area of Underground AC Wire*Length of Underground AC Wire)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))
Angle of PF using Volume of Conductor Material(1 Phase 3 Wire US)
Go Phase Difference = acos(sqrt(10*Resistivity*((Power Transmitted*Length of Underground AC Wire)^2)/(Line Losses*Volume Of Conductor*((Maximum Voltage Underground AC)^2))))
Length using Volume of Conductor Material(1 Phase 3 Wire US)
Go Length of Underground AC Wire = sqrt(Volume Of Conductor*Line Losses*(cos(Phase Difference)*Maximum Voltage Underground AC)^2/((10)*Resistivity*(Power Transmitted^2)))
Angle using Area of X Section (1 Phase 3 Wire US)
Go Phase Difference = acos((2*Power Transmitted/Maximum Voltage Underground AC)*sqrt(Resistivity*Length of Underground AC Wire/(Line Losses*Area of Underground AC Wire)))
Length using Area of X Section (1 Phase 3 Wire US)
Go Length of Underground AC Wire = Area of Underground AC Wire*Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2)/(4*(Power Transmitted^2)*Resistivity)
Line Losses using Area of X Section (1 Phase 3 Wire US)
Go Line Losses = 2*Resistivity*Length of Underground AC Wire*(Power Transmitted^2)/(Area of Underground AC Wire*(Maximum Voltage Underground AC^2*cos(Phase Difference)^2))
Volume of Conductor Material(1 Phase 3 Wire US)
Go Volume Of Conductor = 10*(Power Transmitted^2)*Resistivity*(Length of Underground AC Wire^2)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))
Line Losses using Volume of Conductor Material(1 Phase 3 Wire US)
Go Line Losses = 10*Resistivity*((Power Transmitted*Length of Underground AC Wire)^2)/(Volume Of Conductor*((Maximum Voltage Underground AC*cos(Phase Difference))^2))
Area of X-Section using Line Losses (1 Phase 3 Wire US)
Go Area of Underground AC Wire = 2*Resistivity*Length of Underground AC Wire*(Current Underground AC^2)/Line Losses
Length using Line Losses (1 Phase 3 Wire US)
Go Length of Underground AC Wire = Area of Underground AC Wire*Line Losses/(2*Current Underground AC*Resistivity)
Volume of Conductor Material using Load Current(1 Phase 3 Wire US)
Go Volume Of Conductor = 5*Resistivity*(Length of Underground AC Wire^2)*(Current Underground AC^2)/Line Losses
Constant using Volume of Conductor Material(1 Phase 3 Wire US)
Go Constant Underground AC = Volume Of Conductor*(cos(Phase Difference)^2)/(2.5)
Volume of Conductor Material using Constant(1 Phase 3 Wire US)
Go Volume Of Conductor = 2.5*Constant Underground AC/(cos(Phase Difference)^2)
Volume of Conductor Material using Area and Length (1 Phase 3 Wire US)
Go Volume Of Conductor = Area of Underground AC Wire*Length of Underground AC Wire*2.5

Volume of Conductor Material using Load Current(1 Phase 3 Wire US) Formula

Volume Of Conductor = 5*Resistivity*(Length of Underground AC Wire^2)*(Current Underground AC^2)/Line Losses
V = 5*ρ*(L^2)*(I^2)/Ploss

What is the volume of conductor material in 1-phase 3-wire underground system?

The volume of conductor material required in this system is 2.5/cos2θ times that of 2-wire d.c.system with the one conductor earthed.

How to Calculate Volume of Conductor Material using Load Current(1 Phase 3 Wire US)?

Volume of Conductor Material using Load Current(1 Phase 3 Wire US) calculator uses Volume Of Conductor = 5*Resistivity*(Length of Underground AC Wire^2)*(Current Underground AC^2)/Line Losses to calculate the Volume Of Conductor, The Volume of Conductor Material using Load Current(1 phase 3 wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a 1-phase 3-wire underground system. Volume Of Conductor is denoted by V symbol.

How to calculate Volume of Conductor Material using Load Current(1 Phase 3 Wire US) using this online calculator? To use this online calculator for Volume of Conductor Material using Load Current(1 Phase 3 Wire US), enter Resistivity (ρ), Length of Underground AC Wire (L), Current Underground AC (I) & Line Losses (Ploss) and hit the calculate button. Here is how the Volume of Conductor Material using Load Current(1 Phase 3 Wire US) calculation can be explained with given input values -> 1.485303 = 5*1.7E-05*(24^2)*(9^2)/2.67.

FAQ

What is Volume of Conductor Material using Load Current(1 Phase 3 Wire US)?
The Volume of Conductor Material using Load Current(1 phase 3 wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a 1-phase 3-wire underground system and is represented as V = 5*ρ*(L^2)*(I^2)/Ploss or Volume Of Conductor = 5*Resistivity*(Length of Underground AC Wire^2)*(Current Underground AC^2)/Line Losses. Resistivity is the measure of how strongly a material opposes the flow of current through them, Length of Underground AC Wire is the total length of the wire from one end to other end, Current Underground AC is defined as the current flowing through the overhead ac supply wire & Line Losses is defined as the total losses occurring in an Underground AC line when in use.
How to calculate Volume of Conductor Material using Load Current(1 Phase 3 Wire US)?
The Volume of Conductor Material using Load Current(1 phase 3 wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a 1-phase 3-wire underground system is calculated using Volume Of Conductor = 5*Resistivity*(Length of Underground AC Wire^2)*(Current Underground AC^2)/Line Losses. To calculate Volume of Conductor Material using Load Current(1 Phase 3 Wire US), you need Resistivity (ρ), Length of Underground AC Wire (L), Current Underground AC (I) & Line Losses (Ploss). With our tool, you need to enter the respective value for Resistivity, Length of Underground AC Wire, Current Underground AC & Line Losses and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Volume Of Conductor?
In this formula, Volume Of Conductor uses Resistivity, Length of Underground AC Wire, Current Underground AC & Line Losses. We can use 4 other way(s) to calculate the same, which is/are as follows -
  • Volume Of Conductor = 10*(Power Transmitted^2)*Resistivity*(Length of Underground AC Wire^2)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))
  • Volume Of Conductor = 2.5*Constant Underground AC/(cos(Phase Difference)^2)
  • Volume Of Conductor = (10*(Power Transmitted^2)*Resistance Underground AC*Area of Underground AC Wire*Length of Underground AC Wire)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))
  • Volume Of Conductor = Area of Underground AC Wire*Length of Underground AC Wire*2.5
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