Volume of Conductor Material when Resistance is Given(3 Phase 4 Wire US) Solution

STEP 0: Pre-Calculation Summary
Formula Used
Volume Of Conductor = (7*Resistance Underground AC*Area of Underground AC Wire*(Power Transmitted^2)*(Length of Underground AC Wire))/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))
V = (7*R*A*(P^2)*(L))/(Ploss*(Vm^2)*(cos(Φ)^2))
This formula uses 1 Functions, 8 Variables
Functions Used
cos - Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle., cos(Angle)
Variables Used
Volume Of Conductor - (Measured in Cubic Meter) - Volume Of Conductor the 3-dimensional space enclosed by a conductor material.
Resistance Underground AC - (Measured in Ohm) - Resistance Underground AC is defined as the property of the wire or line that opposes the flow of current through it.
Area of Underground AC Wire - (Measured in Square Meter) - Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.
Power Transmitted - (Measured in Watt) - Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Underground AC line when in use.
Maximum Voltage Underground AC - (Measured in Volt) - Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.
Phase Difference - (Measured in Radian) - Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.
STEP 1: Convert Input(s) to Base Unit
Resistance Underground AC: 5 Ohm --> 5 Ohm No Conversion Required
Area of Underground AC Wire: 1.28 Square Meter --> 1.28 Square Meter No Conversion Required
Power Transmitted: 300 Watt --> 300 Watt No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required
Line Losses: 2.67 Watt --> 2.67 Watt No Conversion Required
Maximum Voltage Underground AC: 230 Volt --> 230 Volt No Conversion Required
Phase Difference: 30 Degree --> 0.5235987755982 Radian (Check conversion here)
STEP 2: Evaluate Formula
Substituting Input Values in Formula
V = (7*R*A*(P^2)*(L))/(Ploss*(Vm^2)*(cos(Φ)^2)) --> (7*5*1.28*(300^2)*(24))/(2.67*(230^2)*(cos(0.5235987755982)^2))
Evaluating ... ...
V = 913.489518064612
STEP 3: Convert Result to Output's Unit
913.489518064612 Cubic Meter --> No Conversion Required
FINAL ANSWER
913.489518064612 913.4895 Cubic Meter <-- Volume Of Conductor
(Calculation completed in 00.004 seconds)

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18 Wire Parameters Calculators

Volume of Conductor Material when Resistance is Given(3 Phase 4 Wire US)
Go Volume Of Conductor = (7*Resistance Underground AC*Area of Underground AC Wire*(Power Transmitted^2)*(Length of Underground AC Wire))/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))
Angle using Area of X-Section (3 Phase 4 Wire US)
Go Phase Difference = acos((Power Transmitted/Maximum Voltage Underground AC)*sqrt(2*Resistivity*Length of Underground AC Wire/(Area of Underground AC Wire*Line Losses)))
Angle using Line Losses (3 Phase 4 Wire US)
Go Phase Difference = acos((Power Transmitted/Maximum Voltage Underground AC)*sqrt(2*Resistivity*Length of Underground AC Wire/(Line Losses*Area of Underground AC Wire)))
Length using Area of X-Section (3 Phase 4 Wire US)
Go Length of Underground AC Wire = (Area of Underground AC Wire*Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference))^2)/(4*Resistivity*(Power Transmitted^2))
Line Losses using Area of X-Section (3 Phase 4 Wire US)
Go Line Losses = 2*Resistivity*Length of Underground AC Wire*(Power Transmitted^2)/(Area of Underground AC Wire*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))
Area of X-Section (3 Phase 4 Wire US)
Go Area of Underground AC Wire = (Power Transmitted^2)*2*Resistivity*Length of Underground AC Wire/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))
Line Losses (3 Phase 4 Wire US)
Go Line Losses = 2*Resistivity*Length of Underground AC Wire*(Power Transmitted^2)/(Area of Underground AC Wire*(Maximum Voltage Underground AC^2*cos(Phase Difference)^2))
Volume of Conductor Material (3 Phase 4 Wire US)
Go Volume Of Conductor = 7*Resistivity*(Power Transmitted^2)*(Length of Underground AC Wire^2)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))
Line Losses using Volume of Conductor Material (3 Phase 4 Wire US)
Go Line Losses = 7*(Power Transmitted)^2*Resistivity*(Length of Underground AC Wire)^2/((Maximum Voltage Underground AC*cos(Phase Difference))^2*Volume Of Conductor)
Angle using Load Current (3 Phase 4 Wire US)
Go Phase Difference = acos(sqrt(6)*Power Transmitted/(3*Maximum Voltage Underground AC*Current Underground AC))
Length using Line Losses (3 Phase 4 Wire US)
Go Length of Underground AC Wire = Line Losses*Area of Underground AC Wire/(2*(Current Underground AC^2)*Resistivity)
Volume of Conductor Material using Load Current (3 Phase 4 Wire US)
Go Volume Of Conductor = 18*Resistivity*(Current Underground AC^2)*(Length of Underground AC Wire^2)/(2*Line Losses)
Line Losses using Load Current (3 Phase 4 Wire US)
Go Line Losses = 3*(Current Underground AC^2)*Resistivity*Length of Underground AC Wire/Area of Underground AC Wire
Area using Line Losses (3 Phase 4 Wire US)
Go Area of Underground AC Wire = (Current Underground AC^2)*2*Resistivity*Length of Underground AC Wire/Line Losses
Constant using Volume of Conductor Material (3 Phase 4 Wire US)
Go Constant Underground AC = Volume Of Conductor*(cos(Phase Difference))^2/(1.75)
Volume of Conductor Material when K is Given(3 Phase 4 Wire US)
Go Volume Of Conductor = Constant Underground AC*1.75/(cos(Phase Difference)^2)
Area of X-Section using Volume of Conductor Material (3 Phase 4 Wire US)
Go Area of Underground AC Wire = Volume Of Conductor/((3.5)*Length of Underground AC Wire)
Volume of Conductor Material when Area and Length is Given(3 Phase 4 Wire US)
Go Volume Of Conductor = 3.5*Area of Underground AC Wire*Length of Underground AC Wire

Volume of Conductor Material when Resistance is Given(3 Phase 4 Wire US) Formula

Volume Of Conductor = (7*Resistance Underground AC*Area of Underground AC Wire*(Power Transmitted^2)*(Length of Underground AC Wire))/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))
V = (7*R*A*(P^2)*(L))/(Ploss*(Vm^2)*(cos(Φ)^2))

What is the volume of conductor material in 3-phase 4-wire underground system?

The volume of conductor material required in this system is 1.75/cos2θ times that of 2-wire d.c.system with the one conductor earthed.

How to Calculate Volume of Conductor Material when Resistance is Given(3 Phase 4 Wire US)?

Volume of Conductor Material when Resistance is Given(3 Phase 4 Wire US) calculator uses Volume Of Conductor = (7*Resistance Underground AC*Area of Underground AC Wire*(Power Transmitted^2)*(Length of Underground AC Wire))/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2)) to calculate the Volume Of Conductor, The Volume of Conductor Material when Resistance is Given(3 phase 4 wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a three-phase four-wire earthed underground system. Volume Of Conductor is denoted by V symbol.

How to calculate Volume of Conductor Material when Resistance is Given(3 Phase 4 Wire US) using this online calculator? To use this online calculator for Volume of Conductor Material when Resistance is Given(3 Phase 4 Wire US), enter Resistance Underground AC (R), Area of Underground AC Wire (A), Power Transmitted (P), Length of Underground AC Wire (L), Line Losses (Ploss), Maximum Voltage Underground AC (Vm) & Phase Difference (Φ) and hit the calculate button. Here is how the Volume of Conductor Material when Resistance is Given(3 Phase 4 Wire US) calculation can be explained with given input values -> 913.4895 = (7*5*1.28*(300^2)*(24))/(2.67*(230^2)*(cos(0.5235987755982)^2)).

FAQ

What is Volume of Conductor Material when Resistance is Given(3 Phase 4 Wire US)?
The Volume of Conductor Material when Resistance is Given(3 phase 4 wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a three-phase four-wire earthed underground system and is represented as V = (7*R*A*(P^2)*(L))/(Ploss*(Vm^2)*(cos(Φ)^2)) or Volume Of Conductor = (7*Resistance Underground AC*Area of Underground AC Wire*(Power Transmitted^2)*(Length of Underground AC Wire))/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2)). Resistance Underground AC is defined as the property of the wire or line that opposes the flow of current through it, Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system, Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work, Length of Underground AC Wire is the total length of the wire from one end to other end, Line Losses is defined as the total losses occurring in an Underground AC line when in use, Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire & Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.
How to calculate Volume of Conductor Material when Resistance is Given(3 Phase 4 Wire US)?
The Volume of Conductor Material when Resistance is Given(3 phase 4 wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a three-phase four-wire earthed underground system is calculated using Volume Of Conductor = (7*Resistance Underground AC*Area of Underground AC Wire*(Power Transmitted^2)*(Length of Underground AC Wire))/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2)). To calculate Volume of Conductor Material when Resistance is Given(3 Phase 4 Wire US), you need Resistance Underground AC (R), Area of Underground AC Wire (A), Power Transmitted (P), Length of Underground AC Wire (L), Line Losses (Ploss), Maximum Voltage Underground AC (Vm) & Phase Difference (Φ). With our tool, you need to enter the respective value for Resistance Underground AC, Area of Underground AC Wire, Power Transmitted, Length of Underground AC Wire, Line Losses, Maximum Voltage Underground AC & Phase Difference and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Volume Of Conductor?
In this formula, Volume Of Conductor uses Resistance Underground AC, Area of Underground AC Wire, Power Transmitted, Length of Underground AC Wire, Line Losses, Maximum Voltage Underground AC & Phase Difference. We can use 4 other way(s) to calculate the same, which is/are as follows -
  • Volume Of Conductor = 18*Resistivity*(Current Underground AC^2)*(Length of Underground AC Wire^2)/(2*Line Losses)
  • Volume Of Conductor = 3.5*Area of Underground AC Wire*Length of Underground AC Wire
  • Volume Of Conductor = Constant Underground AC*1.75/(cos(Phase Difference)^2)
  • Volume Of Conductor = 7*Resistivity*(Power Transmitted^2)*(Length of Underground AC Wire^2)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))
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