Volume of wasted sludge Per Day given Oxygen Demand and Ultimate BOD Both Calculator

✖Sewage discharge is the flow rate of sewage when it is being discharged in the river.ⓘ Sewage Discharge [Q_s]			+10% -10%
✖Influent BOD is the total amount of BOD which is present in the incoming sewage.ⓘ Influent BOD [Q_i]			+10% -10%
✖Effluent BOD is the amount of BOD present in the outing sewage.ⓘ Effluent BOD [Q_o]			+10% -10%
✖5 days BOD is an indicator of how much oxygen is utilized by a natural water sample in five days at 20 degrees C.ⓘ 5 days BOD [BOD5]			+10% -10%
✖Ultimate BOD is the amount of oxygen required to decompose all of the organic material after infinite time.ⓘ Ultimate BOD [BOD^u]			+10% -10%
✖Theoretical oxygen requirement is the calculated amount of oxygen required to oxidize a compound to its final oxidation products.ⓘ Theoretical Oxygen Requirement [O₂]			+10% -10%
✖Oxygen demand of biomass is the amount of oxygen required.ⓘ Oxygen demand of biomass [D^O2]			+10% -10%
✖MLSS is the sum of volatile suspended solids (organics) and fixed suspended solids (inorganics).ⓘ MLSS [X]			+10% -10%

✖Volume of wasted sludge per day is measured in terms of discharge.ⓘ Volume of wasted sludge Per Day given Oxygen Demand and Ultimate BOD Both [Q_w]

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Volume of wasted sludge Per Day given Oxygen Demand and Ultimate BOD Both

Formula

`"Q"_{"w"} = ((("Q"_{"s"}*("Q"_{"i"}-"Q"_{"o"}))/("BOD5"/"BOD"^{"u"}))-"O"_{"2"})/("D"^{"O2"}*"X")`

Example

`"0.045m³/s"=((("10m³/s"*("11.2mg/L"-"0.4mg/L"))/("2mg/L"/"2mg/L"))-"2.5mg/d")/("2"*"1200mg/L")`

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Volume of wasted sludge Per Day given Oxygen Demand and Ultimate BOD Both Solution

STEP 0: Pre-Calculation Summary

Formula Used

Volume of Wasted Sludge per day = (((Sewage Discharge*(Influent BOD-Effluent BOD))/(5 days BOD/Ultimate BOD))-Theoretical Oxygen Requirement)/(Oxygen demand of biomass*MLSS)
Q_w = (((Q_s*(Q_i-Q_o))/(BOD5/BOD^u))-O₂)/(D^O2*X)
This formula uses 9 Variables

Variables Used

Volume of Wasted Sludge per day - (Measured in Cubic Meter per Second) - Volume of wasted sludge per day is measured in terms of discharge.
Sewage Discharge - (Measured in Cubic Meter per Second) - Sewage discharge is the flow rate of sewage when it is being discharged in the river.
Influent BOD - (Measured in Kilogram per Cubic Meter) - Influent BOD is the total amount of BOD which is present in the incoming sewage.
Effluent BOD - (Measured in Kilogram per Cubic Meter) - Effluent BOD is the amount of BOD present in the outing sewage.
5 days BOD - (Measured in Kilogram per Cubic Meter) - 5 days BOD is an indicator of how much oxygen is utilized by a natural water sample in five days at 20 degrees C.
Ultimate BOD - (Measured in Kilogram per Cubic Meter) - Ultimate BOD is the amount of oxygen required to decompose all of the organic material after infinite time.
Theoretical Oxygen Requirement - (Measured in Kilogram per Second) - Theoretical oxygen requirement is the calculated amount of oxygen required to oxidize a compound to its final oxidation products.
Oxygen demand of biomass - Oxygen demand of biomass is the amount of oxygen required.
MLSS - (Measured in Kilogram per Cubic Meter) - MLSS is the sum of volatile suspended solids (organics) and fixed suspended solids (inorganics).

STEP 1: Convert Input(s) to Base Unit

Sewage Discharge: 10 Cubic Meter per Second --> 10 Cubic Meter per Second No Conversion Required
Influent BOD: 11.2 Milligram per Liter --> 0.0112 Kilogram per Cubic Meter (Check conversion here)
Effluent BOD: 0.4 Milligram per Liter --> 0.0004 Kilogram per Cubic Meter (Check conversion here)
5 days BOD: 2 Milligram per Liter --> 0.002 Kilogram per Cubic Meter (Check conversion here)
Ultimate BOD: 2 Milligram per Liter --> 0.002 Kilogram per Cubic Meter (Check conversion here)
Theoretical Oxygen Requirement: 2.5 Milligram per Day --> 2.89351851851852E-11 Kilogram per Second (Check conversion here)
Oxygen demand of biomass: 2 --> No Conversion Required
MLSS: 1200 Milligram per Liter --> 1.2 Kilogram per Cubic Meter (Check conversion here)

STEP 2: Evaluate Formula

Substituting Input Values in Formula

Q_w = (((Q_s*(Q_i-Q_o))/(BOD5/BOD^u))-O₂)/(D^O2*X) --> (((10*(0.0112-0.0004))/(0.002/0.002))-2.89351851851852E-11)/(2*1.2)

Evaluating ... ...

Q_w = 0.0449999999879437

STEP 3: Convert Result to Output's Unit

0.0449999999879437 Cubic Meter per Second --> No Conversion Required

FINAL ANSWER

0.0449999999879437 ≈ 0.045 Cubic Meter per Second <-- Volume of Wasted Sludge per day

(Calculation completed in 00.004 seconds)

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Home » Engineering » Civil » Environmental Engineering » Treatment of Sewage » Oxygen Requirement of the Aeration Tanks » Volume of Wasted Sludge » Volume of wasted sludge Per Day given Oxygen Demand and Ultimate BOD Both

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Created by Suraj Kumar

Birsa Institute of Technology (BIT), Sindri

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Meerut Institute of Engineering and Technology (MIET), Meerut

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< 4 Volume of Wasted Sludge Calculators

Volume of wasted sludge Per Day given Oxygen Demand and Ultimate BOD Both

Go Volume of Wasted Sludge per day = (((Sewage Discharge*(Influent BOD-Effluent BOD))/(5 days BOD/Ultimate BOD))-Theoretical Oxygen Requirement)/(Oxygen demand of biomass*MLSS)

Volume of wasted sludge Per Day given Oxygen Demand of Biomass

Go Volume of Wasted Sludge per day = (((Sewage Discharge*(Influent BOD-Effluent BOD))/Ratio of BOD to Ultimate BOD)-Theoretical Oxygen Requirement)/(Oxygen demand of biomass*MLSS)

Volume of wasted sludge Per Day given Ultimate BOD

Go Volume of Wasted Sludge per day = (((Sewage Discharge*(Influent BOD-Effluent BOD))/(5 days BOD/Ultimate BOD))-Theoretical Oxygen Requirement)/(1.42*MLSS)

Volume of wasted sludge Per Day given Oxygen Required in Aeration Tank

Go Volume of Wasted Sludge per day = (((Sewage Discharge*(Influent BOD-Effluent BOD))/Ratio of BOD to Ultimate BOD)-Theoretical Oxygen Requirement)/(1.42*MLSS)

Volume of wasted sludge Per Day given Oxygen Demand and Ultimate BOD Both Formula

What is sludge ?

Sludge is a semi-solid slurry that can be produced from a range of industrial processes, from water treatment, wastewater treatment or on-site sanitation systems.

How to Calculate Volume of wasted sludge Per Day given Oxygen Demand and Ultimate BOD Both?

Volume of wasted sludge Per Day given Oxygen Demand and Ultimate BOD Both calculator uses Volume of Wasted Sludge per day = (((Sewage Discharge*(Influent BOD-Effluent BOD))/(5 days BOD/Ultimate BOD))-Theoretical Oxygen Requirement)/(Oxygen demand of biomass*MLSS) to calculate the Volume of Wasted Sludge per day, Volume of wasted sludge Per Day given Oxygen Demand and Ultimate BOD Both calculates volume of wasted sludge per day when we have prior information of other parameters used. Volume of Wasted Sludge per day is denoted by Q_w symbol.

How to calculate Volume of wasted sludge Per Day given Oxygen Demand and Ultimate BOD Both using this online calculator? To use this online calculator for Volume of wasted sludge Per Day given Oxygen Demand and Ultimate BOD Both, enter Sewage Discharge (Q_s), Influent BOD (Q_i), Effluent BOD (Q_o), 5 days BOD (BOD5), Ultimate BOD (BOD^u), Theoretical Oxygen Requirement (O₂), Oxygen demand of biomass (D^O2) & MLSS (X) and hit the calculate button. Here is how the Volume of wasted sludge Per Day given Oxygen Demand and Ultimate BOD Both calculation can be explained with given input values -> 0.045 = (((10*(0.0112-0.0004))/(0.002/0.002))-2.89351851851852E-11)/(2*1.2).

FAQ

What is Volume of wasted sludge Per Day given Oxygen Demand and Ultimate BOD Both?

Volume of wasted sludge Per Day given Oxygen Demand and Ultimate BOD Both calculates volume of wasted sludge per day when we have prior information of other parameters used and is represented as Q_w = (((Q_s*(Q_i-Q_o))/(BOD5/BOD^u))-O₂)/(D^O2*X) or Volume of Wasted Sludge per day = (((Sewage Discharge*(Influent BOD-Effluent BOD))/(5 days BOD/Ultimate BOD))-Theoretical Oxygen Requirement)/(Oxygen demand of biomass*MLSS). Sewage discharge is the flow rate of sewage when it is being discharged in the river, Influent BOD is the total amount of BOD which is present in the incoming sewage, Effluent BOD is the amount of BOD present in the outing sewage, 5 days BOD is an indicator of how much oxygen is utilized by a natural water sample in five days at 20 degrees C, Ultimate BOD is the amount of oxygen required to decompose all of the organic material after infinite time, Theoretical oxygen requirement is the calculated amount of oxygen required to oxidize a compound to its final oxidation products, Oxygen demand of biomass is the amount of oxygen required & MLSS is the sum of volatile suspended solids (organics) and fixed suspended solids (inorganics).

How to calculate Volume of wasted sludge Per Day given Oxygen Demand and Ultimate BOD Both?

Volume of wasted sludge Per Day given Oxygen Demand and Ultimate BOD Both calculates volume of wasted sludge per day when we have prior information of other parameters used is calculated using Volume of Wasted Sludge per day = (((Sewage Discharge*(Influent BOD-Effluent BOD))/(5 days BOD/Ultimate BOD))-Theoretical Oxygen Requirement)/(Oxygen demand of biomass*MLSS). To calculate Volume of wasted sludge Per Day given Oxygen Demand and Ultimate BOD Both, you need Sewage Discharge (Q_s), Influent BOD (Q_i), Effluent BOD (Q_o), 5 days BOD (BOD5), Ultimate BOD (BOD^u), Theoretical Oxygen Requirement (O₂), Oxygen demand of biomass (D^O2) & MLSS (X). With our tool, you need to enter the respective value for Sewage Discharge, Influent BOD, Effluent BOD, 5 days BOD, Ultimate BOD, Theoretical Oxygen Requirement, Oxygen demand of biomass & MLSS and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Volume of Wasted Sludge per day?

In this formula, Volume of Wasted Sludge per day uses Sewage Discharge, Influent BOD, Effluent BOD, 5 days BOD, Ultimate BOD, Theoretical Oxygen Requirement, Oxygen demand of biomass & MLSS. We can use 3 other way(s) to calculate the same, which is/are as follows -

Volume of Wasted Sludge per day = (((Sewage Discharge*(Influent BOD-Effluent BOD))/Ratio of BOD to Ultimate BOD)-Theoretical Oxygen Requirement)/(1.42*MLSS)
Volume of Wasted Sludge per day = (((Sewage Discharge*(Influent BOD-Effluent BOD))/Ratio of BOD to Ultimate BOD)-Theoretical Oxygen Requirement)/(Oxygen demand of biomass*MLSS)
Volume of Wasted Sludge per day = (((Sewage Discharge*(Influent BOD-Effluent BOD))/(5 days BOD/Ultimate BOD))-Theoretical Oxygen Requirement)/(1.42*MLSS)

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