Weight of liquid in mixture of 2 immiscible liquids given weight of other liquid Calculator

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✖Vapor Pressure of Pure Component A is the pressure exerted by a liquid or solid molecules of only A in a closed system in which they are in equilibrium with the vapour phase.ⓘ Vapor Pressure of Pure Component A [P_A^o]			+10% -10%
✖The Molecular Mass of Liquid A in a mixture of immiscible liquids.ⓘ Molecular Mass of Liquid A [M_A]			+10% -10%
✖The Weight of Liquid B in a mixture of immiscible liquids.ⓘ Weight of Liquid B [W_B]			+10% -10%
✖Vapor Pressure of Pure Component B is the pressure exerted by a liquid or solid molecules of only B in a closed system in which they are in equilibrium with the vapour phase.ⓘ Vapor Pressure of Pure Component B [P_B^o]			+10% -10%
✖The Molecular Mass of Liquid B in a mixture of immiscible liquids.ⓘ Molecular Mass of Liquid B [M_B]			+10% -10%

✖The Weight of Liquid A in a mixture of immiscible liquids.ⓘ Weight of liquid in mixture of 2 immiscible liquids given weight of other liquid [W_A]

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Weight of liquid in mixture of 2 immiscible liquids given weight of other liquid Solution

STEP 0: Pre-Calculation Summary

Formula Used

Weight of Liquid A = (Vapor Pressure of Pure Component A*Molecular Mass of Liquid A*Weight of Liquid B)/(Vapor Pressure of Pure Component B*Molecular Mass of Liquid B)
W_A = (P_A^o*M_A*W_B)/(P_B^o*M_B)
This formula uses 6 Variables

Variables Used

Weight of Liquid A - (Measured in Kilogram) - The Weight of Liquid A in a mixture of immiscible liquids.
Vapor Pressure of Pure Component A - (Measured in Pascal) - Vapor Pressure of Pure Component A is the pressure exerted by a liquid or solid molecules of only A in a closed system in which they are in equilibrium with the vapour phase.
Molecular Mass of Liquid A - (Measured in Kilogram) - The Molecular Mass of Liquid A in a mixture of immiscible liquids.
Weight of Liquid B - (Measured in Kilogram) - The Weight of Liquid B in a mixture of immiscible liquids.
Vapor Pressure of Pure Component B - (Measured in Pascal) - Vapor Pressure of Pure Component B is the pressure exerted by a liquid or solid molecules of only B in a closed system in which they are in equilibrium with the vapour phase.
Molecular Mass of Liquid B - (Measured in Kilogram) - The Molecular Mass of Liquid B in a mixture of immiscible liquids.

STEP 1: Convert Input(s) to Base Unit

Vapor Pressure of Pure Component A: 2700 Pascal --> 2700 Pascal No Conversion Required
Molecular Mass of Liquid A: 25 Gram --> 0.025 Kilogram (Check conversion here)
Weight of Liquid B: 0.1 Kilogram --> 0.1 Kilogram No Conversion Required
Vapor Pressure of Pure Component B: 10 Pascal --> 10 Pascal No Conversion Required
Molecular Mass of Liquid B: 25 Gram --> 0.025 Kilogram (Check conversion here)

STEP 2: Evaluate Formula

Substituting Input Values in Formula

W_A = (P_A^o*M_A*W_B)/(P_B^o*M_B) --> (2700*0.025*0.1)/(10*0.025)

Evaluating ... ...

W_A = 27

STEP 3: Convert Result to Output's Unit

27 Kilogram --> No Conversion Required

FINAL ANSWER

27 Kilogram <-- Weight of Liquid A

(Calculation completed in 00.031 seconds)

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Home » Chemistry » Solution and Colligative properties » Immiscible Liquids » Weight of liquid in mixture of 2 immiscible liquids given weight of other liquid

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Created by Prerana Bakli

National Institute of Technology (NIT), Meghalaya

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Verified by Akshada Kulkarni

National Institute of Information Technology (NIIT), Neemrana

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Total Vapour Pressure of mixture of given partial pressure of one liquid

Total Pressure of Mixture of Immiscible Liquids = Vapor Pressure of Pure Component B+((Vapor Pressure of Pure Component B*Weight of Liquid A*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Liquid A)) Go

Molecular Mass of a liquid forming an immiscible mixture with Water

Molecular Mass of Liquid B = (Partial Pressure of pure Water*Molecular Mass of Water*Weight of Liquid B)/(Vapor Pressure of Pure Component B*Weight of water in an immiscible mixture) Go

Molecular Mass of liquid in mixture of 2 immiscible liquids given weights of liquids

Molecular Mass of Liquid A = (Weight of Liquid A*Molecular Mass of Liquid B*Vapor Pressure of Pure Component B)/(Vapor Pressure of Pure Component A*Weight of Liquid B) Go

Weight of liquid in mixture of 2 immiscible liquids given weight of other liquid

Weight of Liquid A = (Vapor Pressure of Pure Component A*Molecular Mass of Liquid A*Weight of Liquid B)/(Vapor Pressure of Pure Component B*Molecular Mass of Liquid B) Go

Partial Vapour Pressure of immiscible liquid given partial pressure of other

Vapor Pressure of Pure Component A = (Weight of Liquid A*Molecular Mass of Liquid B*Vapor Pressure of Pure Component B)/(Molecular Mass of Liquid A*Weight of Liquid B) Go

Ratio of Weights of 2 Immiscible Liquids forming Mixture

Ratio of Weights of 2 immiscible liquids = (Vapor Pressure of Pure Component A*Molecular Mass of Liquid A)/(Vapor Pressure of Pure Component B*Molecular Mass of Liquid B) Go

Ratio of Molecular Mass of 2 immiscible liquids

Ratio of Molecular Masses of 2 immiscible liquids = (Vapor Pressure of Pure Component B*Weight of Liquid A)/(Vapor Pressure of Pure Component A*Weight of Liquid B) Go

Ratio of partial vapour pressures of 2 Immiscible Liquids in terms of weight and molecular mass

Ratio of Partial Pressures of 2 Immiscible Liquids = (Weight of Liquid A*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Liquid A) Go

Total Pressure of mixture of two Immiscible Liquids

Total Pressure of Mixture of Immiscible Liquids = Vapor Pressure of Pure Component A+Vapor Pressure of Pure Component B Go

Ratio of partial pressure of 2 immiscible liquids in terms their number of moles

Ratio of Partial Pressures of 2 Immiscible Liquids = Number of moles of Liquid A/No. of moles of Liquid B Go

Weight of liquid in mixture of 2 immiscible liquids given weight of other liquid Formula

How does both liquids contribute to pressure of a mixture of 2 immiscible liquids?

Obviously if you have two immiscible liquids in a closed flask and keep everything still, the vapor pressure you measure will simply be the vapor pressure of the one which is floating on top. There is no way that the bottom liquid can turn to vapor. The top one is sealing it in. For the purposes of the rest of this topic, we always assume that the mixture is being stirred or agitated in some way so that the two liquids are broken up into drops. At any one time there will be drops of both liquids on the surface. That means that both of them contribute to the overall vapor pressure of the mixture.

How to Calculate Weight of liquid in mixture of 2 immiscible liquids given weight of other liquid?

Weight of liquid in mixture of 2 immiscible liquids given weight of other liquid calculator uses Weight of Liquid A = (Vapor Pressure of Pure Component A*Molecular Mass of Liquid A*Weight of Liquid B)/(Vapor Pressure of Pure Component B*Molecular Mass of Liquid B) to calculate the Weight of Liquid A, The Weight of liquid in mixture of 2 immiscible liquids given weight of other liquid considering A as unknown parameter and B as known parameter. Weight of Liquid A is denoted by W_A symbol.

How to calculate Weight of liquid in mixture of 2 immiscible liquids given weight of other liquid using this online calculator? To use this online calculator for Weight of liquid in mixture of 2 immiscible liquids given weight of other liquid, enter Vapor Pressure of Pure Component A (P_A^o), Molecular Mass of Liquid A (M_A), Weight of Liquid B (W_B), Vapor Pressure of Pure Component B (P_B^o) & Molecular Mass of Liquid B (M_B) and hit the calculate button. Here is how the Weight of liquid in mixture of 2 immiscible liquids given weight of other liquid calculation can be explained with given input values -> 27 = (2700*0.025*0.1)/(10*0.025).

FAQ

What is Weight of liquid in mixture of 2 immiscible liquids given weight of other liquid?

The Weight of liquid in mixture of 2 immiscible liquids given weight of other liquid considering A as unknown parameter and B as known parameter and is represented as W_A = (P_A^o*M_A*W_B)/(P_B^o*M_B) or Weight of Liquid A = (Vapor Pressure of Pure Component A*Molecular Mass of Liquid A*Weight of Liquid B)/(Vapor Pressure of Pure Component B*Molecular Mass of Liquid B). Vapor Pressure of Pure Component A is the pressure exerted by a liquid or solid molecules of only A in a closed system in which they are in equilibrium with the vapour phase, The Molecular Mass of Liquid A in a mixture of immiscible liquids, The Weight of Liquid B in a mixture of immiscible liquids, Vapor Pressure of Pure Component B is the pressure exerted by a liquid or solid molecules of only B in a closed system in which they are in equilibrium with the vapour phase & The Molecular Mass of Liquid B in a mixture of immiscible liquids.

How to calculate Weight of liquid in mixture of 2 immiscible liquids given weight of other liquid?

The Weight of liquid in mixture of 2 immiscible liquids given weight of other liquid considering A as unknown parameter and B as known parameter is calculated using Weight of Liquid A = (Vapor Pressure of Pure Component A*Molecular Mass of Liquid A*Weight of Liquid B)/(Vapor Pressure of Pure Component B*Molecular Mass of Liquid B). To calculate Weight of liquid in mixture of 2 immiscible liquids given weight of other liquid, you need Vapor Pressure of Pure Component A (P_A^o), Molecular Mass of Liquid A (M_A), Weight of Liquid B (W_B), Vapor Pressure of Pure Component B (P_B^o) & Molecular Mass of Liquid B (M_B). With our tool, you need to enter the respective value for Vapor Pressure of Pure Component A, Molecular Mass of Liquid A, Weight of Liquid B, Vapor Pressure of Pure Component B & Molecular Mass of Liquid B and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

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