Rudrani Tidke
Cummins College of Engineering for Women (CCEW), Pune
Rudrani Tidke has created this Calculator and 100+ more calculators!
Kethavath Srinath
Osmania University (OU), Hyderabad
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11 Other formulas that you can solve using the same Inputs

Ultimate Strength for Symmetrical Reinforcement in Single Layers
Axial Load Capacity=Capacity reduction factor*((Area of Compressive Reinforcement*Yield strength of reinforcing steel/((Eccentricity/Distance from Compression to Tensile Reinforcement)-Distance from Compression to Centroid Reinforcment+0.5))+(Width of compression face*Depth of column*28 Day Compressive Strength of Concrete/((3*Depth of column*Eccentricity/(Distance from Compression to Tensile Reinforcement^2))+1.18))) GO
Ultimate Strength for Short, Circular Members when Governed by Compression
Axial Load Capacity=Capacity reduction factor*((Area of steel reinforcement*Yield strength of reinforcing steel/((3*Eccentricity/Diameter of reinforcement)+1))+(Gross area*28 Day Compressive Strength of Concrete/(9.6*Diameter at eccentricity/((0.8*Overall diameter of section+0.67*Diameter of reinforcement)^2)+1.18))) GO
Ultimate Strength for Short, Square Members when Governed by Compression
Axial Load Capacity=Capacity reduction factor*((Area of steel reinforcement*Yield strength of reinforcing steel/((3*Eccentricity/Diameter of reinforcement)+1))+(Gross area*28 Day Compressive Strength of Concrete/((12*Depth of column*Eccentricity/((Depth of column+0.67*Diameter of reinforcement)^2))+1.18))) GO
Stirrup Spacing for Practical Design
Spacing of Stirrups=(Stirrup Area*Capacity reduction factor*Yield strength of reinforcing steel*Effective depth of beam)/((Design Shear )-((2*Capacity reduction factor)*sqrt(28 Day Compressive Strength of Concrete)*Breadth of the web*Effective depth of beam)) GO
Stirrup Area when Stirrup Spacing for Practical Design is Given
Stirrup Area=(Spacing of Stirrups)*(Design Shear -(2*Capacity reduction factor*sqrt(28 Day Compressive Strength of Concrete)*Effective depth of beam*Breadth of the web))/(Capacity reduction factor*Yield strength of reinforcing steel*Effective depth of beam) GO
Lateral Deflection of a Pile
lateral deflection=((coefficient Ay*lateral load*(characteristic pile length^3))/pile stiffness)+((coefficient By*moment*(characteristic pile length^2))/pile stiffness) GO
Positive Moment Imposed on a Pile
positive moment=(coefficient of lateral load in positive moment*lateral load*characteristic pile length)+(coefficient of moment term in positive moment*moment) GO
Axial Load for Spiral Columns
Bending moment=0.12*Total area*yield strength of reinforcement*Diameter of reinforcement GO
Longitudinal Reinforcement Area when Axial Load for Spiral Columns is Given
Total area=moment/(0.12*Yield strength of reinforcing steel*Diameter ) GO
Reinforcement Yield Strength when Axial Load for Spiral Columns is Given
Yield strength of reinforcing steel=moment/(0.12*Total area*Diameter ) GO
Stress in Steel
Stress=moment/(Tensile Reinforcement Area*Ratio j*Depth of the Beam) GO

11 Other formulas that calculate the same Output

Circle Diameter when Maximum Permissible Eccentricity for Spiral Columns is Given
Diameter =(Maximum permissible eccentricity-0.14*Overall depth of column)/(0.43*Area ratio of cross sectional area to gross area*Force ratio of strengths of reinforcements) GO
Diameter of Roller or Rocker for milled surface when Allowable Stress is Given for d > 635 mm
Diameter =(6.67*Allowable Bearing Stresses on Pins/(yield strength of steel-13))^2 GO
Diameter of Roller or Rocker for milled surface when Allowable Stress is Given for d < 635 mm
Diameter =33.33*Allowable Bearing Stresses on Pins/(yield strength of steel-13) GO
Diameter bisecting chords of slope m to the parabola y2 = 4ax
Diameter =(2*x coordinate of focus of parabola)/Slope of Line GO
Diameter of a Rod Circular Fin when area of cross-section is Given
Diameter =sqrt((Cross sectional area*4)/pi) GO
Diameter of a circle when circumference is given
Diameter =Circumference of Circle/pi GO
Diameter of a circle when area is given
Diameter =2*sqrt(Area of Circle/pi) GO
Diameter of a Nugget
Diameter =6*(Thickness)^1/2 GO
Diameter of a circular cylinder of maximum convex surface area in a given circular cone
Diameter =Radius of cone GO
Diameter of a circle when radius is given
Diameter =2*Radius GO
Diameter of Sphere
Diameter =2*Radius GO

Circle Diameter when Axial Load for Spiral Columns is Given Formula

Diameter =moment/(0.12*Total area*Yield strength of reinforcing steel)
d=M<sub>t</sub>/(0.12*A<sub>st</sub>*f<sub>y</sub>)
More formulas
Maximum Permissible Eccentricity for Spiral Columns GO
Maximum Permissible Eccentricity for Tied Columns GO
Circle Diameter when Maximum Permissible Eccentricity for Spiral Columns is Given GO
Column Diameter when Maximum Permissible Eccentricity for Spiral Columns is Given GO
Reinforcement Yield Strength when Axial Load for Spiral Columns is Given GO
Longitudinal Reinforcement Area when Axial Load for Spiral Columns is Given GO
Axial Load for Spiral Columns GO
Reinforcement Yield Strength when Axial Load for Tied Columns is Given GO
Tension Reinforcement Area when Axial Load for Tied Columns is Given GO
Axial Load for Tied Columns GO
Axial Moment at Balanced Condition GO
Axial Load at Balanced Condition GO

What does spiral mean?

Spiral defined as the path of a point in a plane moving around a central point while continuously receding from or approaching it.

How to Calculate Circle Diameter when Axial Load for Spiral Columns is Given?

Circle Diameter when Axial Load for Spiral Columns is Given calculator uses Diameter =moment/(0.12*Total area*Yield strength of reinforcing steel) to calculate the Diameter , The Circle Diameter when Axial Load for Spiral Columns is Given formula is defined as the length of the line through the center that touches two points on the edge of the circle. Diameter and is denoted by d symbol.

How to calculate Circle Diameter when Axial Load for Spiral Columns is Given using this online calculator? To use this online calculator for Circle Diameter when Axial Load for Spiral Columns is Given, enter moment (Mt), Total area (Ast) and Yield strength of reinforcing steel (fy and hit the calculate button. Here is how the Circle Diameter when Axial Load for Spiral Columns is Given calculation can be explained with given input values -> 0.010622 = 1/(0.12*8*98.0664999999931).

FAQ

What is Circle Diameter when Axial Load for Spiral Columns is Given?
The Circle Diameter when Axial Load for Spiral Columns is Given formula is defined as the length of the line through the center that touches two points on the edge of the circle and is represented as d=Mt/(0.12*Ast*fy or Diameter =moment/(0.12*Total area*Yield strength of reinforcing steel). moment is an overturning effect (tends to bend or turn the member) created by the force(load) acting on a structural member, Total area is the sum of all areas of of longitudinal reinforcement and Yield strength of reinforcing steel is the stress at which a predetermined amount of permanent deformation occurs.
How to calculate Circle Diameter when Axial Load for Spiral Columns is Given?
The Circle Diameter when Axial Load for Spiral Columns is Given formula is defined as the length of the line through the center that touches two points on the edge of the circle is calculated using Diameter =moment/(0.12*Total area*Yield strength of reinforcing steel). To calculate Circle Diameter when Axial Load for Spiral Columns is Given, you need moment (Mt), Total area (Ast) and Yield strength of reinforcing steel (fy. With our tool, you need to enter the respective value for moment, Total area and Yield strength of reinforcing steel and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Diameter ?
In this formula, Diameter uses moment, Total area and Yield strength of reinforcing steel. We can use 11 other way(s) to calculate the same, which is/are as follows -
  • Diameter =Circumference of Circle/pi
  • Diameter =2*sqrt(Area of Circle/pi)
  • Diameter =2*Radius
  • Diameter =Radius of cone
  • Diameter =6*(Thickness)^1/2
  • Diameter =sqrt((Cross sectional area*4)/pi)
  • Diameter =2*Radius
  • Diameter =(Maximum permissible eccentricity-0.14*Overall depth of column)/(0.43*Area ratio of cross sectional area to gross area*Force ratio of strengths of reinforcements)
  • Diameter =(2*x coordinate of focus of parabola)/Slope of Line
  • Diameter =33.33*Allowable Bearing Stresses on Pins/(yield strength of steel-13)
  • Diameter =(6.67*Allowable Bearing Stresses on Pins/(yield strength of steel-13))^2
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