Fanout of Gate Calculator

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CMOS Special Purpose Subsystem

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CMOS Delay Characteristics

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✖Stage effort is a measure of how much effort (or delay) is required to drive the output of a logic gate or circuit to the next stage in the design.ⓘ Stage Effort [f]			+10% -10%
✖Logical effort is a metric that represents the intrinsic speed of a logic gate.ⓘ Logical Effort [g]			+10% -10%

✖Fanout is the number of similar gate inputs that a gate output can drive. In other words, it represents the number of gates or loads connected to the output of the current gate.ⓘ Fanout of Gate [h]

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Formula

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Fanout of Gate

Formula

`"h" = "f"/"g"`

Example

`"0.838235"="3.99"/"4.76"`

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Fanout of Gate Solution

STEP 0: Pre-Calculation Summary

Formula Used

Fanout = Stage Effort/Logical Effort
h = f/g
This formula uses 3 Variables

Variables Used

Fanout - Fanout is the number of similar gate inputs that a gate output can drive. In other words, it represents the number of gates or loads connected to the output of the current gate.
Stage Effort - Stage effort is a measure of how much effort (or delay) is required to drive the output of a logic gate or circuit to the next stage in the design.
Logical Effort - Logical effort is a metric that represents the intrinsic speed of a logic gate.

STEP 1: Convert Input(s) to Base Unit

Stage Effort: 3.99 --> No Conversion Required
Logical Effort: 4.76 --> No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

h = f/g --> 3.99/4.76

Evaluating ... ...

h = 0.838235294117647

STEP 3: Convert Result to Output's Unit

0.838235294117647 --> No Conversion Required

FINAL ANSWER

0.838235294117647 ≈ 0.838235 <-- Fanout

(Calculation completed in 00.004 seconds)

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Created by Shobhit Dimri

Bipin Tripathi Kumaon Institute of Technology (BTKIT), Dwarahat

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Invertor Power

Go Inverter Power = (Delay of Chains-(Electric Effort 1+Electric Effort 2))/2

Invertor Electric Effort 1

Go Electric Effort 1 = Delay of Chains-(Electric Effort 2+2*Inverter Power)

Invertor Electric Effort 2

Go Electric Effort 2 = Delay of Chains-(Electric Effort 1+2*Inverter Power)

Delay for Two Inverters in Series

Go Delay of Chains = Electric Effort 1+Electric Effort 2+2*Inverter Power

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Go PLL Output Clock Phase = Transfer Function PLL*Input Reference Clock Phase

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Go Input Reference Clock Phase = PLL Output Clock Phase/Transfer Function PLL

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Go Change in Phase of Clock = PLL Output Clock Phase/Absolute Frequency

PLL Phase Detector Error

Go PLL Error Detector = Input Reference Clock Phase-Feedback Clock PLL

Feedback Clock PLL

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Change in Frequency of Clock

Go Change in Frequency of Clock = Fanout/Absolute Frequency

Capacitance of External Load

Go Capacitance of External Load = Fanout*Input Capacitance

Fanout of Gate

Go Fanout = Stage Effort/Logical Effort

Stage Effort

Go Stage Effort = Fanout*Logical Effort

Gate Delay

Go Gate Delay = 2^(N Bit SRAM)

Fanout of Gate Formula

Fanout = Stage Effort/Logical Effort
h = f/g

What is stage effort?

Stage effort is a measure of the effort required to drive the load capacitance of the next stage in a CMOS circuit. It takes into account the intrinsic delay of the gate and the load capacitance it drives.

How to Calculate Fanout of Gate?

Fanout of Gate calculator uses Fanout = Stage Effort/Logical Effort to calculate the Fanout, Fanout of Gate is a measure of how many gates are connected to the output of a given gate. It represents the number of gate inputs driven by the output of the gate in the question. Fanout is denoted by h symbol.

How to calculate Fanout of Gate using this online calculator? To use this online calculator for Fanout of Gate, enter Stage Effort (f) & Logical Effort (g) and hit the calculate button. Here is how the Fanout of Gate calculation can be explained with given input values -> 0.840336 = 3.99/4.76.

FAQ

What is Fanout of Gate?

Fanout of Gate is a measure of how many gates are connected to the output of a given gate. It represents the number of gate inputs driven by the output of the gate in the question and is represented as h = f/g or Fanout = Stage Effort/Logical Effort. Stage effort is a measure of how much effort (or delay) is required to drive the output of a logic gate or circuit to the next stage in the design & Logical effort is a metric that represents the intrinsic speed of a logic gate.

How to calculate Fanout of Gate?

Fanout of Gate is a measure of how many gates are connected to the output of a given gate. It represents the number of gate inputs driven by the output of the gate in the question is calculated using Fanout = Stage Effort/Logical Effort. To calculate Fanout of Gate, you need Stage Effort (f) & Logical Effort (g). With our tool, you need to enter the respective value for Stage Effort & Logical Effort and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

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