Force Acting in x Direction in Momentum Equation Calculator

✖Density of Liquid is mass of a unit volume of a material substance.ⓘ Density of Liquid [ρ_l]			+10% -10%
✖Discharge is the rate of flow of a liquid.ⓘ Discharge [Q]			+10% -10%
✖The Velocity at section 1-1 is the flow velocity of a liquid flowing at a particular section in the pipe before the sudden enlargement.ⓘ Velocity at Section 1-1 [v₁]			+10% -10%
✖The Velocity at section 2-2 is the flow velocity of the liquid flowing in a pipe at a particular section after the sudden enlargement of the pipe size.ⓘ Velocity at Section 2-2 [v₂]			+10% -10%
✖Theta is an angle that can be defined as the figure formed by two rays meeting at a common endpoint.ⓘ Theta [θ]			+10% -10%
✖Pressure at section 1 is defined as the physical force exerted on an object.ⓘ Pressure at Section 1 [P₁]			+10% -10%
✖Cross-Sectional Area at Point 1 is defined as the area of the section at point 1.ⓘ Cross-Sectional Area at Point 1 [A₁]			+10% -10%
✖Pressure at section 2 is defined as the physical force exerted on an object.ⓘ Pressure at Section 2 [P₂]			+10% -10%
✖Cross-Sectional area at point 2 is the area of cross section at a point 2.ⓘ Cross-Sectional Area at Point 2 [A₂]			+10% -10%

✖Force in X-Direction is defines as push or pull exerted on an object that causes a change in motion, it has both magnitude and direction and may be contact or a field of force.ⓘ Force Acting in x Direction in Momentum Equation [F_x]

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Formula

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Force Acting in x Direction in Momentum Equation

Formula

`"F"_{"x"} = "ρ"_{"l"}*"Q"*("v"_{"1"}-"v"_{"2"}*cos("θ"))+"P"_{"1"}*"A"_{"1"}-("P"_{"2"}*"A"_{"2"}*cos("θ"))`

Example

`"1121.539N"="4kg/m³"*"1.1m³/s"*("20m/s"-"12m/s"*cos("30°"))+"122Pa"*"14m²"-("121Pa"*"6m²"*cos("30°"))`

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Force Acting in x Direction in Momentum Equation Solution

STEP 0: Pre-Calculation Summary

Formula Used

Force in X-Direction = Density of Liquid*Discharge*(Velocity at Section 1-1-Velocity at Section 2-2*cos(Theta))+Pressure at Section 1*Cross-Sectional Area at Point 1-(Pressure at Section 2*Cross-Sectional Area at Point 2*cos(Theta))
F_x = ρ_l*Q*(v₁-v₂*cos(θ))+P₁*A₁-(P₂*A₂*cos(θ))
This formula uses 1 Functions, 10 Variables

Functions Used

cos - Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle., cos(Angle)

Variables Used

Force in X-Direction - (Measured in Newton) - Force in X-Direction is defines as push or pull exerted on an object that causes a change in motion, it has both magnitude and direction and may be contact or a field of force.
Density of Liquid - (Measured in Kilogram per Cubic Meter) - Density of Liquid is mass of a unit volume of a material substance.
Discharge - (Measured in Cubic Meter per Second) - Discharge is the rate of flow of a liquid.
Velocity at Section 1-1 - (Measured in Meter per Second) - The Velocity at section 1-1 is the flow velocity of a liquid flowing at a particular section in the pipe before the sudden enlargement.
Velocity at Section 2-2 - (Measured in Meter per Second) - The Velocity at section 2-2 is the flow velocity of the liquid flowing in a pipe at a particular section after the sudden enlargement of the pipe size.
Theta - (Measured in Radian) - Theta is an angle that can be defined as the figure formed by two rays meeting at a common endpoint.
Pressure at Section 1 - (Measured in Pascal) - Pressure at section 1 is defined as the physical force exerted on an object.
Cross-Sectional Area at Point 1 - (Measured in Square Meter) - Cross-Sectional Area at Point 1 is defined as the area of the section at point 1.
Pressure at Section 2 - (Measured in Pascal) - Pressure at section 2 is defined as the physical force exerted on an object.
Cross-Sectional Area at Point 2 - (Measured in Square Meter) - Cross-Sectional area at point 2 is the area of cross section at a point 2.

STEP 1: Convert Input(s) to Base Unit

Density of Liquid: 4 Kilogram per Cubic Meter --> 4 Kilogram per Cubic Meter No Conversion Required
Discharge: 1.1 Cubic Meter per Second --> 1.1 Cubic Meter per Second No Conversion Required
Velocity at Section 1-1: 20 Meter per Second --> 20 Meter per Second No Conversion Required
Velocity at Section 2-2: 12 Meter per Second --> 12 Meter per Second No Conversion Required
Theta: 30 Degree --> 0.5235987755982 Radian (Check conversion here)
Pressure at Section 1: 122 Pascal --> 122 Pascal No Conversion Required
Cross-Sectional Area at Point 1: 14 Square Meter --> 14 Square Meter No Conversion Required
Pressure at Section 2: 121 Pascal --> 121 Pascal No Conversion Required
Cross-Sectional Area at Point 2: 6 Square Meter --> 6 Square Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

F_x = ρ_l*Q*(v₁-v₂*cos(θ))+P₁*A₁-(P₂*A₂*cos(θ)) --> 4*1.1*(20-12*cos(0.5235987755982))+122*14-(121*6*cos(0.5235987755982))

Evaluating ... ...

F_x = 1121.53941553268

STEP 3: Convert Result to Output's Unit

1121.53941553268 Newton --> No Conversion Required

FINAL ANSWER

1121.53941553268 ≈ 1121.539 Newton <-- Force in X-Direction

(Calculation completed in 00.004 seconds)

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< 20 Hydrostatic Fluid Calculators

Force Acting in x Direction in Momentum Equation

Go Force in X-Direction = Density of Liquid*Discharge*(Velocity at Section 1-1-Velocity at Section 2-2*cos(Theta))+Pressure at Section 1*Cross-Sectional Area at Point 1-(Pressure at Section 2*Cross-Sectional Area at Point 2*cos(Theta))

Force Acting in y-Direction in Momentum Equation

Go Force in Y-Direction = Density of Liquid*Discharge*(-Velocity at Section 2-2*sin(Theta)-Pressure at Section 2*Cross-Sectional Area at Point 2*sin(Theta))

Experimental Determination of Metacentric height

Go Metacentric Height = (Movable Weight on Ship*Transverse Displacement)/((Movable Weight on Ship+Ship Weight)*tan(Angle of Tilt))

Radius of Gyration given Time Period of Rolling

Go Radius of Gyration = sqrt(Acceleration Due to Gravity*Metacentric Height*(Time Period of Rolling/2*pi)^2)

Fluid Dynamic or Shear Viscosity Formula

Go Dynamic Viscosity = (Applied Force*Distance between Two Masses)/(Area of Solid Plates*Peripheral Speed)

Moment of Inertia of Waterline Area using Metacentric Height

Go Moment of Inertia of Waterline Area = (Metacentric Height+Distance Between Point B and G)*Volume of Liquid Displaced by Body

Volume of Liquid Displaced given Metacentric Height

Go Volume of Liquid Displaced by Body = Moment of Inertia of Waterline Area/(Metacentric Height+Distance Between Point B and G)

Distance between Buoyancy Point and Center of Gravity given Metacenter Height

Go Distance Between Point B and G = Moment of Inertia of Waterline Area/Volume of Liquid Displaced by Body-Metacentric Height

Metacentric Height given Moment of Inertia

Go Metacentric Height = Moment of Inertia of Waterline Area/Volume of Liquid Displaced by Body-Distance Between Point B and G

Center of Gravity

Go Centre of Gravity = Moment of Inertia/(Volume of Object*(Centre of Buoyancy+Metacenter))

Center of Buoyancy

Go Centre of Buoyancy = Moment of Inertia/(Volume of Object*Centre of Gravity)-Metacenter

Metacenter

Go Metacenter = Moment of Inertia/(Volume of Object*Centre of Gravity)-Centre of Buoyancy

Theoretical Velocity for Pitot Tube

Go Theoretical Velocity = sqrt(2*Acceleration Due to Gravity*Dynamic Pressure Head)

Metacentric Height

Go Metacentric Height = Distance between Point B and M-Distance Between Point B and G

Volume of Submerged Object given Buoyancy Force

Go Volume of Object = Buoyancy Force/Specific Weight of Liquid

Buoyancy Force

Go Buoyancy Force = Specific Weight of Liquid*Volume of Object

Surface Tension given Surface Energy and Area

Go Surface Tension = (Surface Energy)/(Surface Area)

Pressure in Bubble

Go Pressure = (8*Surface Tension)/Diameter of Bubble

Surface Energy given Surface Tension

Go Surface Energy = Surface Tension*Surface Area

Surface Area given Surface Tension

Go Surface Area = Surface Energy/Surface Tension

Force Acting in x Direction in Momentum Equation Formula

What is a force acting in the opposite direction?

Equal forces acting in opposite directions are called balanced forces. Balanced forces acting on an object will not change the object's motion. When you add equal forces in opposite direction, the net force is zero.

What is Action force definition?

Action force is force acting in one direction. Reaction force is force acting in the opposite direction. Learn more about Newton's Third Law as it explains action and reaction forces through several examples, and test your knowledge with quiz questions.

How to Calculate Force Acting in x Direction in Momentum Equation?

Force Acting in x Direction in Momentum Equation calculator uses Force in X-Direction = Density of Liquid*Discharge*(Velocity at Section 1-1-Velocity at Section 2-2*cos(Theta))+Pressure at Section 1*Cross-Sectional Area at Point 1-(Pressure at Section 2*Cross-Sectional Area at Point 2*cos(Theta)) to calculate the Force in X-Direction, The Force acting in x direction in momentum equation formula is defined as a push or pull exerted on an object that causes a change in motion, it has both magnitude and direction and maybe contact or a field of force. Force in X-Direction is denoted by F_x symbol.

How to calculate Force Acting in x Direction in Momentum Equation using this online calculator? To use this online calculator for Force Acting in x Direction in Momentum Equation, enter Density of Liquid (ρ_l), Discharge (Q), Velocity at Section 1-1 (v₁), Velocity at Section 2-2 (v₂), Theta (θ), Pressure at Section 1 (P₁), Cross-Sectional Area at Point 1 (A₁), Pressure at Section 2 (P₂) & Cross-Sectional Area at Point 2 (A₂) and hit the calculate button. Here is how the Force Acting in x Direction in Momentum Equation calculation can be explained with given input values -> 1121.539 = 4*1.1*(20-12*cos(0.5235987755982))+122*14-(121*6*cos(0.5235987755982)).

FAQ

What is Force Acting in x Direction in Momentum Equation?

The Force acting in x direction in momentum equation formula is defined as a push or pull exerted on an object that causes a change in motion, it has both magnitude and direction and maybe contact or a field of force and is represented as F_x = ρ_l*Q*(v₁-v₂*cos(θ))+P₁*A₁-(P₂*A₂*cos(θ)) or Force in X-Direction = Density of Liquid*Discharge*(Velocity at Section 1-1-Velocity at Section 2-2*cos(Theta))+Pressure at Section 1*Cross-Sectional Area at Point 1-(Pressure at Section 2*Cross-Sectional Area at Point 2*cos(Theta)). Density of Liquid is mass of a unit volume of a material substance, Discharge is the rate of flow of a liquid, The Velocity at section 1-1 is the flow velocity of a liquid flowing at a particular section in the pipe before the sudden enlargement, The Velocity at section 2-2 is the flow velocity of the liquid flowing in a pipe at a particular section after the sudden enlargement of the pipe size, Theta is an angle that can be defined as the figure formed by two rays meeting at a common endpoint, Pressure at section 1 is defined as the physical force exerted on an object, Cross-Sectional Area at Point 1 is defined as the area of the section at point 1, Pressure at section 2 is defined as the physical force exerted on an object & Cross-Sectional area at point 2 is the area of cross section at a point 2.

How to calculate Force Acting in x Direction in Momentum Equation?

The Force acting in x direction in momentum equation formula is defined as a push or pull exerted on an object that causes a change in motion, it has both magnitude and direction and maybe contact or a field of force is calculated using Force in X-Direction = Density of Liquid*Discharge*(Velocity at Section 1-1-Velocity at Section 2-2*cos(Theta))+Pressure at Section 1*Cross-Sectional Area at Point 1-(Pressure at Section 2*Cross-Sectional Area at Point 2*cos(Theta)). To calculate Force Acting in x Direction in Momentum Equation, you need Density of Liquid (ρ_l), Discharge (Q), Velocity at Section 1-1 (v₁), Velocity at Section 2-2 (v₂), Theta (θ), Pressure at Section 1 (P₁), Cross-Sectional Area at Point 1 (A₁), Pressure at Section 2 (P₂) & Cross-Sectional Area at Point 2 (A₂). With our tool, you need to enter the respective value for Density of Liquid, Discharge, Velocity at Section 1-1, Velocity at Section 2-2, Theta, Pressure at Section 1, Cross-Sectional Area at Point 1, Pressure at Section 2 & Cross-Sectional Area at Point 2 and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

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