Heat Transfer Calculator

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Basics of HMT

Conduction

Convection

Convective Mass Transfer

✖Thermal potential difference is the difference in electric potential between two points in an electric field(T2-T1).ⓘ Thermal Potential Difference [T_vd]			+10% -10%
✖Thermal resistance is a heat property and a measurement of a temperature difference by which an object or material resists a heat flow.ⓘ Thermal Resistance [R_th]			+10% -10%

✖Heat Flow Rate can be referred as the flow of thermal energy through a body per unit time.ⓘ Heat Transfer [Q_{heat transfer}]

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Formula

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Heat Transfer

Formula

`"Q"_{"heat transfer"} = "T"_{"vd"}/"R"_{"th"}`

Example

`"14714.29W"="103K"/"0.007K/W"`

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Heat Transfer Solution

STEP 0: Pre-Calculation Summary

Formula Used

Heat Flow Rate = Thermal Potential Difference/Thermal Resistance
Q_{heat transfer} = T_vd/R_th
This formula uses 3 Variables

Variables Used

Heat Flow Rate - (Measured in Watt) - Heat Flow Rate can be referred as the flow of thermal energy through a body per unit time.
Thermal Potential Difference - (Measured in Kelvin) - Thermal potential difference is the difference in electric potential between two points in an electric field(T2-T1).
Thermal Resistance - (Measured in Kelvin per Watt) - Thermal resistance is a heat property and a measurement of a temperature difference by which an object or material resists a heat flow.

STEP 1: Convert Input(s) to Base Unit

Thermal Potential Difference: 103 Kelvin --> 103 Kelvin No Conversion Required
Thermal Resistance: 0.007 Kelvin per Watt --> 0.007 Kelvin per Watt No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

Q_{heat transfer} = T_vd/R_th --> 103/0.007

Evaluating ... ...

Q_{heat transfer} = 14714.2857142857

STEP 3: Convert Result to Output's Unit

14714.2857142857 Watt --> No Conversion Required

FINAL ANSWER

14714.2857142857 ≈ 14714.29 Watt <-- Heat Flow Rate

(Calculation completed in 00.004 seconds)

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Created by Kethavath Srinath

Osmania University (OU), Hyderabad

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< 13 Heat and Mass Transfer Calculators

Heat Transfer by Conduction at Base

Go Rate of Conductive Heat Transfer = (Thermal Conductivity*Cross Sectional Area of Fin*Perimeter of the Fin*Convective Heat Transfer Coefficient)^0.5*(Base Temperature-Ambient Temperature)

Heat Exchange by Radiation due to Geometric Arrangement

Go Heat Transfer = Emissivity*Area*[Stefan-BoltZ]*Shape Factor*(Temperature of Surface 1^(4)-Temperature of Surface 2^(4))

Black Bodies Heat Exchange by Radiation

Go Heat Transfer = Emissivity*[Stefan-BoltZ]*Area*(Temperature of Surface 1^(4)-Temperature of Surface 2^(4))

Heat Transfer According to Fourier's Law

Go Heat Flow Through a Body = -(Thermal Conductivity of Material*Surface Area of Heat Flow*Temperature Difference/Thickness)

One Dimensional Heat Flux

Go Heat Flux = -Thermal Conductivity of Fin/Wall Thickness*(Temperature of Wall 2-Temperature of Wall 1)

Newton's Law of Cooling

Go Heat Flux = Heat Transfer Coefficient*(Surface Temperature-Temperature of Characteristic Fluid)

Non Ideal Body Surface Emittance

Go Real Surface Radiant Surface Emittance = Emissivity*[Stefan-BoltZ]*Surface Temperature^(4)

Convective Processes Heat Transfer Coefficient

Go Heat Flux = Heat Transfer Coefficient*(Surface Temperature-Recovery temperature)

Thermal Conductivity given Critical Thickness of Insulation for Cylinder

Go Thermal Conductivity of Fin = Critical Thickness of Insulation*Heat Transfer Coefficient at Outer Surface

Diameter of Rod Circular Fin given Area of Cross-Section

Go Diameter of Circular Rod = sqrt((Cross-sectional area*4)/pi)

Critical Thickness of Insulation for Cylinder

Go Critical Thickness of Insulation = Thermal Conductivity of Fin/Heat Transfer Coefficient

Thermal Resistance in Convection Heat Transfer

Go Thermal Resistance = 1/(Exposed Surface Area*Co-efficient of Convective Heat Transfer)

Heat Transfer

Go Heat Flow Rate = Thermal Potential Difference/Thermal Resistance

< 13 Conduction, Convection and Radiation Calculators

Heat Transfer by Conduction at Base

Go Rate of Conductive Heat Transfer = (Thermal Conductivity*Cross Sectional Area of Fin*Perimeter of the Fin*Convective Heat Transfer Coefficient)^0.5*(Base Temperature-Ambient Temperature)

Heat Exchange by Radiation due to Geometric Arrangement

Go Heat Transfer = Emissivity*Area*[Stefan-BoltZ]*Shape Factor*(Temperature of Surface 1^(4)-Temperature of Surface 2^(4))

Black Bodies Heat Exchange by Radiation

Go Heat Transfer = Emissivity*[Stefan-BoltZ]*Area*(Temperature of Surface 1^(4)-Temperature of Surface 2^(4))

Heat Transfer According to Fourier's Law

Go Heat Flow Through a Body = -(Thermal Conductivity of Material*Surface Area of Heat Flow*Temperature Difference/Thickness)

One Dimensional Heat Flux

Go Heat Flux = -Thermal Conductivity of Fin/Wall Thickness*(Temperature of Wall 2-Temperature of Wall 1)

Newton's Law of Cooling

Go Heat Flux = Heat Transfer Coefficient*(Surface Temperature-Temperature of Characteristic Fluid)

Non Ideal Body Surface Emittance

Go Real Surface Radiant Surface Emittance = Emissivity*[Stefan-BoltZ]*Surface Temperature^(4)

Thermal Resistance in Conduction

Go Thermal Resistance = (Thickness)/(Thermal Conductivity of Fin*Cross Sectional Area)

Convective Processes Heat Transfer Coefficient

Go Heat Flux = Heat Transfer Coefficient*(Surface Temperature-Recovery temperature)

Thermal Conductivity given Critical Thickness of Insulation for Cylinder

Go Thermal Conductivity of Fin = Critical Thickness of Insulation*Heat Transfer Coefficient at Outer Surface

Critical Thickness of Insulation for Cylinder

Go Critical Thickness of Insulation = Thermal Conductivity of Fin/Heat Transfer Coefficient

Thermal Resistance in Convection Heat Transfer

Go Thermal Resistance = 1/(Exposed Surface Area*Co-efficient of Convective Heat Transfer)

Heat Transfer

Go Heat Flow Rate = Thermal Potential Difference/Thermal Resistance

Heat Transfer Formula

Heat Flow Rate = Thermal Potential Difference/Thermal Resistance
Q_{heat transfer} = T_vd/R_th

What is heat transfer?

Heat transfer is a discipline of thermal engineering that concerns the generation, use, conversion, and exchange of thermal energy between physical systems. Heat transfer is classified into various mechanisms, such as thermal conduction, thermal convection, thermal radiation, and transfer of energy by phase changes.

How to Calculate Heat Transfer?

Heat Transfer calculator uses Heat Flow Rate = Thermal Potential Difference/Thermal Resistance to calculate the Heat Flow Rate, Heat Transfer, any or all of several kinds of phenomena, considered as mechanisms, that convey energy and entropy from one location to another. Heat Flow Rate is denoted by Q_{heat transfer} symbol.

How to calculate Heat Transfer using this online calculator? To use this online calculator for Heat Transfer, enter Thermal Potential Difference (T_vd) & Thermal Resistance (R_th) and hit the calculate button. Here is how the Heat Transfer calculation can be explained with given input values -> 14714.29 = 103/0.007.

FAQ

What is Heat Transfer?

Heat Transfer, any or all of several kinds of phenomena, considered as mechanisms, that convey energy and entropy from one location to another and is represented as Q_{heat transfer} = T_vd/R_th or Heat Flow Rate = Thermal Potential Difference/Thermal Resistance. Thermal potential difference is the difference in electric potential between two points in an electric field(T2-T1) & Thermal resistance is a heat property and a measurement of a temperature difference by which an object or material resists a heat flow.

How to calculate Heat Transfer?

Heat Transfer, any or all of several kinds of phenomena, considered as mechanisms, that convey energy and entropy from one location to another is calculated using Heat Flow Rate = Thermal Potential Difference/Thermal Resistance. To calculate Heat Transfer, you need Thermal Potential Difference (T_vd) & Thermal Resistance (R_th). With our tool, you need to enter the respective value for Thermal Potential Difference & Thermal Resistance and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

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