🔍
🔍

## Credits

Vishwakarma Government Engineering College (VGEC), Ahmedabad
Urvi Rathod has created this Calculator and 1000+ more calculators!
Bipin Tripathi Kumaon Institute of Technology (BTKIT), Dwarahat
Shobhit Dimri has verified this Calculator and 100+ more calculators!

## Load Current Using Area Of X-Section(1-Phase 2-Wire Mid-point Earthed OS) Solution

STEP 0: Pre-Calculation Summary
Formula Used
current5 = sqrt(Area Of 1-Φ 2-wire mid-point system*Line Losses/(2*Resistivity*Length))
I5 = sqrt(a5*W/(2*ρ*l))
This formula uses 1 Functions, 4 Variables
Functions Used
sqrt - Squre root function, sqrt(Number)
Variables Used
Area Of 1-Φ 2-wire mid-point system - The Area Of 1-Φ 2-wire mid-point system is the amount of two-dimensional space taken up by an object. (Measured in Square Meter)
Line Losses - Line Losses is defined as the losses that are produced in the line. (Measured in Watt)
Resistivity - Resistivity is the measure of how strongly a material opposes the flow of current through them. (Measured in Ohm Meter)
Length - Length is the measurement or extent of something from end to end. (Measured in Meter)
STEP 1: Convert Input(s) to Base Unit
Area Of 1-Φ 2-wire mid-point system: 6 Square Meter --> 6 Square Meter No Conversion Required
Line Losses: 0.6 Watt --> 0.6 Watt No Conversion Required
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Length: 3 Meter --> 3 Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
I5 = sqrt(a5*W/(2*ρ*l)) --> sqrt(6*0.6/(2*1.7E-05*3))
Evaluating ... ...
I5 = 187.867287325545
STEP 3: Convert Result to Output's Unit
187.867287325545 Ampere --> No Conversion Required
187.867287325545 Ampere <-- Current Of 1-Φ 2-wire mid-point system
(Calculation completed in 00.016 seconds)

## < 9 Area Of X-Section Calculators

Power Transmitted Using Area Of X-section(1-Phase 2-Wire Mid-point Earthed OS)
power_transmitted = sqrt((Area Of 1-Φ 2-wire mid-point system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2))/(Resistivity*Length)) Go
Maximum Voltage Using Area Of X-section(1-Phase 2-Wire Mid-point Earthed OS)
maximum_voltage = sqrt((Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 2-wire mid-point system*Line Losses*((cos(Theta))^2))) Go
RMS Voltage Using Area Of X-section(1-Phase 2-Wire Mid-point Earthed OS)
rms_voltage = sqrt((2*Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 2-wire mid-point system*Line Losses*((cos(Theta))^2))) Go
Power Factor Using Area Of X-section(1-Phase 2-Wire Mid-point Earthed OS)
power_factor = sqrt((Power Transmitted^2)*Resistivity*Length/(Area Of 1-Φ 2-wire mid-point system*Line Losses*(Maximum Voltage^2))) Go
Line Losses Using Area Of X-section(1-Phase 2-Wire Mid-point Earthed OS)
line_losses = (Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 2-wire mid-point system*(Maximum Voltage^2)*((cos(Theta))^2)) Go
Length Of Wire Using Area Of X-section(1-Phase 2-Wire Mid-point Earthed OS)
length = Area Of 1-Φ 2-wire mid-point system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/(Resistivity*(Power Transmitted^2)) Go
Resistivity Using Area Of X-section(1-Phase 2-Wire Mid-point Earthed OS)
resistivity = Area Of 1-Φ 2-wire mid-point system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/(Length*(Power Transmitted^2)) Go
Load Current Using Area Of X-Section(1-Phase 2-Wire Mid-point Earthed OS)
current5 = sqrt(Area Of 1-Φ 2-wire mid-point system*Line Losses/(2*Resistivity*Length)) Go
Volume Of Conductor Material Using Area Of X-section(1-Phase 2-Wire Mid-point Earthed OS)
volume_of_conductor_material = (2)*Area Of 1-Φ 2-wire mid-point system*Length Go

### Load Current Using Area Of X-Section(1-Phase 2-Wire Mid-point Earthed OS) Formula

current5 = sqrt(Area Of 1-Φ 2-wire mid-point system*Line Losses/(2*Resistivity*Length))
I5 = sqrt(a5*W/(2*ρ*l))

## What is the value of maximum voltage and volume of conductor material in this system?

The volume of conductor material required in this system is 1/2cos2θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is 2vm so that r.m.s. value of voltage between them is √2vm.

## How to Calculate Load Current Using Area Of X-Section(1-Phase 2-Wire Mid-point Earthed OS)?

Load Current Using Area Of X-Section(1-Phase 2-Wire Mid-point Earthed OS) calculator uses current5 = sqrt(Area Of 1-Φ 2-wire mid-point system*Line Losses/(2*Resistivity*Length)) to calculate the Current Of 1-Φ 2-wire mid-point system, The Load Current Using Area Of X-section(1-Phase 2-Wire Mid-point Earthed OS) formula is defined as the current that flows into the load of the 1-phase 2-wire mid-point earthed overhead system. Current Of 1-Φ 2-wire mid-point system and is denoted by I5 symbol.

How to calculate Load Current Using Area Of X-Section(1-Phase 2-Wire Mid-point Earthed OS) using this online calculator? To use this online calculator for Load Current Using Area Of X-Section(1-Phase 2-Wire Mid-point Earthed OS), enter Area Of 1-Φ 2-wire mid-point system (a5), Line Losses (W), Resistivity (ρ) and Length (l) and hit the calculate button. Here is how the Load Current Using Area Of X-Section(1-Phase 2-Wire Mid-point Earthed OS) calculation can be explained with given input values -> 187.8673 = sqrt(6*0.6/(2*1.7E-05*3)).

### FAQ

What is Load Current Using Area Of X-Section(1-Phase 2-Wire Mid-point Earthed OS)?
The Load Current Using Area Of X-section(1-Phase 2-Wire Mid-point Earthed OS) formula is defined as the current that flows into the load of the 1-phase 2-wire mid-point earthed overhead system and is represented as I5 = sqrt(a5*W/(2*ρ*l)) or current5 = sqrt(Area Of 1-Φ 2-wire mid-point system*Line Losses/(2*Resistivity*Length)). The Area Of 1-Φ 2-wire mid-point system is the amount of two-dimensional space taken up by an object, Line Losses is defined as the losses that are produced in the line, Resistivity is the measure of how strongly a material opposes the flow of current through them and Length is the measurement or extent of something from end to end.
How to calculate Load Current Using Area Of X-Section(1-Phase 2-Wire Mid-point Earthed OS)?
The Load Current Using Area Of X-section(1-Phase 2-Wire Mid-point Earthed OS) formula is defined as the current that flows into the load of the 1-phase 2-wire mid-point earthed overhead system is calculated using current5 = sqrt(Area Of 1-Φ 2-wire mid-point system*Line Losses/(2*Resistivity*Length)). To calculate Load Current Using Area Of X-Section(1-Phase 2-Wire Mid-point Earthed OS), you need Area Of 1-Φ 2-wire mid-point system (a5), Line Losses (W), Resistivity (ρ) and Length (l). With our tool, you need to enter the respective value for Area Of 1-Φ 2-wire mid-point system, Line Losses, Resistivity and Length and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Current Of 1-Φ 2-wire mid-point system?
In this formula, Current Of 1-Φ 2-wire mid-point system uses Area Of 1-Φ 2-wire mid-point system, Line Losses, Resistivity and Length. We can use 9 other way(s) to calculate the same, which is/are as follows -
• length = Area Of 1-Φ 2-wire mid-point system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/(Resistivity*(Power Transmitted^2))
• resistivity = Area Of 1-Φ 2-wire mid-point system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/(Length*(Power Transmitted^2))
• power_transmitted = sqrt((Area Of 1-Φ 2-wire mid-point system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2))/(Resistivity*Length))
• line_losses = (Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 2-wire mid-point system*(Maximum Voltage^2)*((cos(Theta))^2))
• maximum_voltage = sqrt((Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 2-wire mid-point system*Line Losses*((cos(Theta))^2)))
• rms_voltage = sqrt((2*Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 2-wire mid-point system*Line Losses*((cos(Theta))^2)))
• power_factor = sqrt((Power Transmitted^2)*Resistivity*Length/(Area Of 1-Φ 2-wire mid-point system*Line Losses*(Maximum Voltage^2)))
• current5 = sqrt(Area Of 1-Φ 2-wire mid-point system*Line Losses/(2*Resistivity*Length))
• volume_of_conductor_material = (2)*Area Of 1-Φ 2-wire mid-point system*Length
Where is the Load Current Using Area Of X-Section(1-Phase 2-Wire Mid-point Earthed OS) calculator used?
Among many, Load Current Using Area Of X-Section(1-Phase 2-Wire Mid-point Earthed OS) calculator is widely used in real life applications like {FormulaUses}. Here are few more real life examples -
{FormulaExamplesList}
Let Others Know