Magnetic Field on Axis of Ring Solution

STEP 0: Pre-Calculation Summary
Formula Used
Magnetic Field = ([Permeability-vacuum]*Electric Current*Radius of Ring^2)/(2*(Radius of Ring^2+Perpendicular Distance^2)^(3/2))
B = ([Permeability-vacuum]*i*rring^2)/(2*(rring^2+d^2)^(3/2))
This formula uses 1 Constants, 4 Variables
Constants Used
[Permeability-vacuum] - Permeability of vacuum Value Taken As 1.2566E-6
Variables Used
Magnetic Field - (Measured in Tesla) - Magnetic fields are produced by electric currents, which can be macroscopic currents in wires, or microscopic currents associated with electrons in atomic orbits.
Electric Current - (Measured in Ampere) - Electric Current is the time rate of flow of charge through a cross sectional area.
Radius of Ring - (Measured in Meter) - Radius of Ring is a line segment extending from the center of a circle or sphere to the circumference or bounding surface.
Perpendicular Distance - (Measured in Meter) - The perpendicular distance between two objects is the distance from one to the other, measured along a line that is perpendicular to one or both.
STEP 1: Convert Input(s) to Base Unit
Electric Current: 2.2 Ampere --> 2.2 Ampere No Conversion Required
Radius of Ring: 6 Millimeter --> 0.006 Meter (Check conversion here)
Perpendicular Distance: 31 Millimeter --> 0.031 Meter (Check conversion here)
STEP 2: Evaluate Formula
Substituting Input Values in Formula
B = ([Permeability-vacuum]*i*rring^2)/(2*(rring^2+d^2)^(3/2)) --> ([Permeability-vacuum]*2.2*0.006^2)/(2*(0.006^2+0.031^2)^(3/2))
Evaluating ... ...
B = 1.58074680423016E-06
STEP 3: Convert Result to Output's Unit
1.58074680423016E-06 Tesla -->1.58074680423016E-06 Weber per Square Meter (Check conversion here)
FINAL ANSWER
1.58074680423016E-06 1.6E-6 Weber per Square Meter <-- Magnetic Field
(Calculation completed in 00.004 seconds)

Credits

Created by Mayank Tayal
National Institute of Technology (NIT), Durgapur
Mayank Tayal has created this Calculator and 25+ more calculators!
Verified by Rushi Shah
K J Somaiya College of Engineering (K J Somaiya), Mumbai
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15 Magnetic Field due to Current Calculators

Magnetic Field due to Straight Conductor
Go Magnetic Field = ([Permeability-vacuum]*Electric Current)/(4*pi*Perpendicular Distance)*(cos(Theta 1)-cos(Theta 2))
Magnetic Field for Tangent Galvanometer
Go Horizontal Component of Earth's Magnetic Field = ([Permeability-vacuum]*Number of Turns of Coil*Electric Current)/(2*Radius of Ring*tan(Angle of Deflection of Galvanometer))
Force between Parallel Wires
Go Magnetic Force per Unit Length = ([Permeability-vacuum]*Electric Current in Conductor 1*Electric Current in Conductor 2)/(2*pi*Perpendicular Distance)
Current in Moving Coil Galvanometer
Go Electric Current = (Spring Constant*Angle of Deflection of Galvanometer)/(Number of Turns of Coil*Cross-Sectional Area*Magnetic Field)
Magnetic Field on Axis of Ring
Go Magnetic Field = ([Permeability-vacuum]*Electric Current*Radius of Ring^2)/(2*(Radius of Ring^2+Perpendicular Distance^2)^(3/2))
Time Period of Magnetometer
Go Time Period of Magnetometer = 2*pi*sqrt(Moment of Inertia/(Magnetic Moment*Horizontal Component of Earth's Magnetic Field))
Magnetic Field at Center of Arc
Go Field at Center of Arc = ([Permeability-vacuum]*Electric Current*Angle Obtained by Arc at Center)/(4*pi*Radius of Ring)
Field of Bar Magnet at Equatorial position
Go Field at Equitorial Position of Bar Magnet = ([Permeability-vacuum]*Magnetic Moment)/(4*pi*Distance from Center to Point^3)
Field of Bar Magnet at Axial position
Go Field at Axial Position of Bar Magnet = (2*[Permeability-vacuum]*Magnetic Moment)/(4*pi*Distance from Center to Point^3)
Field Inside Solenoid
Go Magnetic Field = ([Permeability-vacuum]*Electric Current*Number of Turns)/Length of Solonoid
Magnetic Field Due to Infinite Straight Wire
Go Magnetic Field = ([Permeability-vacuum]*Electric Current)/(2*pi*Perpendicular Distance)
Electric Current for Tangent Galvanometer
Go Electric Current = Reduction Factor of Tangent Galvanometer*tan(Angle of Deflection of Galvanometer)
Angle of Dip
Go Angle of Dip = arccos(Horizontal Component of Earth's Magnetic Field/Net Earth's Magnetic Field)
Magnetic Field at Center of Ring
Go Field at Center of Ring = ([Permeability-vacuum]*Electric Current)/(2*Radius of Ring)
Magnetic Permeability
Go Magnetic Permeability of Medium = Magnetic Field/Magnetic Field Intensity

Magnetic Field on Axis of Ring Formula

Magnetic Field = ([Permeability-vacuum]*Electric Current*Radius of Ring^2)/(2*(Radius of Ring^2+Perpendicular Distance^2)^(3/2))
B = ([Permeability-vacuum]*i*rring^2)/(2*(rring^2+d^2)^(3/2))

What is Magnetic Field ?

A magnetic field is a vector field that describes the magnetic influence on moving electric charges, electric currents, and magnetic materials. A moving charge in a magnetic field experiences a force perpendicular to its own velocity and to the magnetic field.

How to Calculate Magnetic Field on Axis of Ring?

Magnetic Field on Axis of Ring calculator uses Magnetic Field = ([Permeability-vacuum]*Electric Current*Radius of Ring^2)/(2*(Radius of Ring^2+Perpendicular Distance^2)^(3/2)) to calculate the Magnetic Field, The Magnetic Field on Axis of Ring formula is defined as the magnitude of magnetic field produced by a circular conductor carrying current of value 'i' and radius 'r' at a distance 'd' from the centre of ring on its axis. Magnetic Field is denoted by B symbol.

How to calculate Magnetic Field on Axis of Ring using this online calculator? To use this online calculator for Magnetic Field on Axis of Ring, enter Electric Current (i), Radius of Ring (rring) & Perpendicular Distance (d) and hit the calculate button. Here is how the Magnetic Field on Axis of Ring calculation can be explained with given input values -> 1.6E-6 = ([Permeability-vacuum]*2.2*0.006^2)/(2*(0.006^2+0.031^2)^(3/2)).

FAQ

What is Magnetic Field on Axis of Ring?
The Magnetic Field on Axis of Ring formula is defined as the magnitude of magnetic field produced by a circular conductor carrying current of value 'i' and radius 'r' at a distance 'd' from the centre of ring on its axis and is represented as B = ([Permeability-vacuum]*i*rring^2)/(2*(rring^2+d^2)^(3/2)) or Magnetic Field = ([Permeability-vacuum]*Electric Current*Radius of Ring^2)/(2*(Radius of Ring^2+Perpendicular Distance^2)^(3/2)). Electric Current is the time rate of flow of charge through a cross sectional area, Radius of Ring is a line segment extending from the center of a circle or sphere to the circumference or bounding surface & The perpendicular distance between two objects is the distance from one to the other, measured along a line that is perpendicular to one or both.
How to calculate Magnetic Field on Axis of Ring?
The Magnetic Field on Axis of Ring formula is defined as the magnitude of magnetic field produced by a circular conductor carrying current of value 'i' and radius 'r' at a distance 'd' from the centre of ring on its axis is calculated using Magnetic Field = ([Permeability-vacuum]*Electric Current*Radius of Ring^2)/(2*(Radius of Ring^2+Perpendicular Distance^2)^(3/2)). To calculate Magnetic Field on Axis of Ring, you need Electric Current (i), Radius of Ring (rring) & Perpendicular Distance (d). With our tool, you need to enter the respective value for Electric Current, Radius of Ring & Perpendicular Distance and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Magnetic Field?
In this formula, Magnetic Field uses Electric Current, Radius of Ring & Perpendicular Distance. We can use 3 other way(s) to calculate the same, which is/are as follows -
  • Magnetic Field = ([Permeability-vacuum]*Electric Current*Number of Turns)/Length of Solonoid
  • Magnetic Field = ([Permeability-vacuum]*Electric Current)/(4*pi*Perpendicular Distance)*(cos(Theta 1)-cos(Theta 2))
  • Magnetic Field = ([Permeability-vacuum]*Electric Current)/(2*pi*Perpendicular Distance)
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