Minimum Periodic Time of SHM for Compound Pendulum Calculator

✖The Radius of Gyration or gyradius is defined as the radial distance to a point that would have a moment of inertia the same as the body's actual distribution of mass.ⓘ Radius of Gyration [k_G]			+10% -10%
✖Acceleration due to Gravity is acceleration gained by an object because of gravitational force.ⓘ Acceleration due to Gravity [g]			+10% -10%

✖Time Period SHM is time required for the periodic motion.ⓘ Minimum Periodic Time of SHM for Compound Pendulum [t_p]

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Minimum Periodic Time of SHM for Compound Pendulum

Formula

`"t"_{"p"} = 2*pi*sqrt(2*"k"_{"G"}/"g")`

Example

`"0.621874s"=2*pi*sqrt(2*"48mm"/"9.8m/s²")`

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Minimum Periodic Time of SHM for Compound Pendulum Solution

STEP 0: Pre-Calculation Summary

Formula Used

Time Period SHM = 2*pi*sqrt(2*Radius of Gyration/Acceleration due to Gravity)
t_p = 2*pi*sqrt(2*k_G/g)
This formula uses 1 Constants, 1 Functions, 3 Variables

Constants Used

pi - Archimedes' constant Value Taken As 3.14159265358979323846264338327950288

Functions Used

sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)

Variables Used

Time Period SHM - (Measured in Second) - Time Period SHM is time required for the periodic motion.
Radius of Gyration - (Measured in Meter) - The Radius of Gyration or gyradius is defined as the radial distance to a point that would have a moment of inertia the same as the body's actual distribution of mass.
Acceleration due to Gravity - (Measured in Meter per Square Second) - Acceleration due to Gravity is acceleration gained by an object because of gravitational force.

STEP 1: Convert Input(s) to Base Unit

Radius of Gyration: 48 Millimeter --> 0.048 Meter (Check conversion here)
Acceleration due to Gravity: 9.8 Meter per Square Second --> 9.8 Meter per Square Second No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

t_p = 2*pi*sqrt(2*k_G/g) --> 2*pi*sqrt(2*0.048/9.8)

Evaluating ... ...

t_p = 0.621874067737446

STEP 3: Convert Result to Output's Unit

0.621874067737446 Second --> No Conversion Required

FINAL ANSWER

0.621874067737446 ≈ 0.621874 Second <-- Time Period SHM

(Calculation completed in 00.004 seconds)

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< 3 Compound Pendulum Calculators

Periodic Time of SHM for Compound Pendulum given Radius of Gyration

Go Periodic time for compound pendulum = 2*pi*sqrt((Radius of Gyration^2+Distance of pt of suspension of pendulum from cg^2)/(Acceleration due to Gravity*Distance of pt of suspension of pendulum from cg))

Minimum Periodic Time of SHM for Compound Pendulum

Go Time Period SHM = 2*pi*sqrt(2*Radius of Gyration/Acceleration due to Gravity)

Frequency of Compound Pendulum in SHM

Go Frequency = 1/Periodic time for compound pendulum

Minimum Periodic Time of SHM for Compound Pendulum Formula

Time Period SHM = 2*pi*sqrt(2*Radius of Gyration/Acceleration due to Gravity)
t_p = 2*pi*sqrt(2*k_G/g)

What is the meaning of time period or periodic time?

The time period is the time taken by a complete cycle of the wave to pass a point, Frequency is the number of the complete cycles of waves passing a point in unit time. Angular frequency is the angular displacement of any element of the wave per unit time.

How to Calculate Minimum Periodic Time of SHM for Compound Pendulum?

Minimum Periodic Time of SHM for Compound Pendulum calculator uses Time Period SHM = 2*pi*sqrt(2*Radius of Gyration/Acceleration due to Gravity) to calculate the Time Period SHM, The Minimum Periodic Time of SHM for Compound Pendulum is the minimum time taken by a complete cycle of the wave to pass a point. Time Period SHM is denoted by t_p symbol.

How to calculate Minimum Periodic Time of SHM for Compound Pendulum using this online calculator? To use this online calculator for Minimum Periodic Time of SHM for Compound Pendulum, enter Radius of Gyration (k_G) & Acceleration due to Gravity (g) and hit the calculate button. Here is how the Minimum Periodic Time of SHM for Compound Pendulum calculation can be explained with given input values -> 0.621874 = 2*pi*sqrt(2*0.048/9.8).

FAQ

What is Minimum Periodic Time of SHM for Compound Pendulum?

The Minimum Periodic Time of SHM for Compound Pendulum is the minimum time taken by a complete cycle of the wave to pass a point and is represented as t_p = 2*pi*sqrt(2*k_G/g) or Time Period SHM = 2*pi*sqrt(2*Radius of Gyration/Acceleration due to Gravity). The Radius of Gyration or gyradius is defined as the radial distance to a point that would have a moment of inertia the same as the body's actual distribution of mass & Acceleration due to Gravity is acceleration gained by an object because of gravitational force.

How to calculate Minimum Periodic Time of SHM for Compound Pendulum?

The Minimum Periodic Time of SHM for Compound Pendulum is the minimum time taken by a complete cycle of the wave to pass a point is calculated using Time Period SHM = 2*pi*sqrt(2*Radius of Gyration/Acceleration due to Gravity). To calculate Minimum Periodic Time of SHM for Compound Pendulum, you need Radius of Gyration (k_G) & Acceleration due to Gravity (g). With our tool, you need to enter the respective value for Radius of Gyration & Acceleration due to Gravity and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

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