Thermal Conductivity given Critical Thickness of Insulation for Cylinder Calculator

⤿

Basics of HMT

Conduction

Convection

Convective Mass Transfer

✖Critical thickness of insulation means maximum heat loss with min thermal resistance.ⓘ Critical Thickness of Insulation [r_c]			+10% -10%
✖Heat Transfer Coefficient at Outer Surface is the amount of heat transferred for a unit temperature difference between the surrounding fluid and the unit area of the insulation surface in unit time.ⓘ Heat Transfer Coefficient at Outer Surface [h_o]			+10% -10%

✖Thermal Conductivity of Fin is rate of heat passes through Fin, expressed as amount of heat flows per unit time through a unit area with a temperature gradient of one degree per unit distance.ⓘ Thermal Conductivity given Critical Thickness of Insulation for Cylinder [k_o]

⎘ Copy

👎

Formula

✖

Thermal Conductivity given Critical Thickness of Insulation for Cylinder

Formula

`"k"_{"o"} = "r"_{"c"}*"h"_{"o"}`

Example

`"42.5W/(m*K)"="5m"*"8.5W/m²*K"`

Calculator

LaTeX

Reset

👍

Download Heat and Mass Transfer Formula PDF PDF Image

Thermal Conductivity given Critical Thickness of Insulation for Cylinder Solution

STEP 0: Pre-Calculation Summary

Formula Used

Thermal Conductivity of Fin = Critical Thickness of Insulation*Heat Transfer Coefficient at Outer Surface
k_o = r_c*h_o
This formula uses 3 Variables

Variables Used

Thermal Conductivity of Fin - (Measured in Watt per Meter per K) - Thermal Conductivity of Fin is rate of heat passes through Fin, expressed as amount of heat flows per unit time through a unit area with a temperature gradient of one degree per unit distance.
Critical Thickness of Insulation - (Measured in Meter) - Critical thickness of insulation means maximum heat loss with min thermal resistance.
Heat Transfer Coefficient at Outer Surface - (Measured in Watt per Square Meter per Kelvin) - Heat Transfer Coefficient at Outer Surface is the amount of heat transferred for a unit temperature difference between the surrounding fluid and the unit area of the insulation surface in unit time.

STEP 1: Convert Input(s) to Base Unit

Critical Thickness of Insulation: 5 Meter --> 5 Meter No Conversion Required
Heat Transfer Coefficient at Outer Surface: 8.5 Watt per Square Meter per Kelvin --> 8.5 Watt per Square Meter per Kelvin No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

k_o = r_c*h_o --> 5*8.5

Evaluating ... ...

k_o = 42.5

STEP 3: Convert Result to Output's Unit

42.5 Watt per Meter per K --> No Conversion Required

FINAL ANSWER

42.5 Watt per Meter per K <-- Thermal Conductivity of Fin

(Calculation completed in 00.004 seconds)

You are here -

Home » Physics » Heat and Mass Transfer » Thermal Conductivity given Critical Thickness of Insulation for Cylinder

Credits

Created by Rushi Shah

K J Somaiya College of Engineering (K J Somaiya), Mumbai

Rushi Shah has created this Calculator and 25+ more calculators!

Verified by Suman Ray Pramanik

Indian Institute of Technology (IIT), Kanpur

Suman Ray Pramanik has verified this Calculator and 100+ more calculators!

< 13 Heat and Mass Transfer Calculators

Heat Transfer by Conduction at Base

Go Rate of Conductive Heat Transfer = (Thermal Conductivity*Cross Sectional Area of Fin*Perimeter of the Fin*Convective Heat Transfer Coefficient)^0.5*(Base Temperature-Ambient Temperature)

Heat Exchange by Radiation due to Geometric Arrangement

Go Heat Transfer = Emissivity*Area*[Stefan-BoltZ]*Shape Factor*(Temperature of Surface 1^(4)-Temperature of Surface 2^(4))

Black Bodies Heat Exchange by Radiation

Go Heat Transfer = Emissivity*[Stefan-BoltZ]*Area*(Temperature of Surface 1^(4)-Temperature of Surface 2^(4))

Heat Transfer According to Fourier's Law

Go Heat Flow Through a Body = -(Thermal Conductivity of Material*Surface Area of Heat Flow*Temperature Difference/Thickness)

One Dimensional Heat Flux

Go Heat Flux = -Thermal Conductivity of Fin/Wall Thickness*(Temperature of Wall 2-Temperature of Wall 1)

Newton's Law of Cooling

Go Heat Flux = Heat Transfer Coefficient*(Surface Temperature-Temperature of Characteristic Fluid)

Non Ideal Body Surface Emittance

Go Real Surface Radiant Surface Emittance = Emissivity*[Stefan-BoltZ]*Surface Temperature^(4)

Convective Processes Heat Transfer Coefficient

Go Heat Flux = Heat Transfer Coefficient*(Surface Temperature-Recovery temperature)

Thermal Conductivity given Critical Thickness of Insulation for Cylinder

Go Thermal Conductivity of Fin = Critical Thickness of Insulation*Heat Transfer Coefficient at Outer Surface

Diameter of Rod Circular Fin given Area of Cross-Section

Go Diameter of Circular Rod = sqrt((Cross-sectional area*4)/pi)

Critical Thickness of Insulation for Cylinder

Go Critical Thickness of Insulation = Thermal Conductivity of Fin/Heat Transfer Coefficient

Thermal Resistance in Convection Heat Transfer

Go Thermal Resistance = 1/(Exposed Surface Area*Co-efficient of Convective Heat Transfer)

Heat Transfer

Go Heat Flow Rate = Thermal Potential Difference/Thermal Resistance

< 13 Conduction, Convection and Radiation Calculators

Heat Transfer by Conduction at Base

Go Rate of Conductive Heat Transfer = (Thermal Conductivity*Cross Sectional Area of Fin*Perimeter of the Fin*Convective Heat Transfer Coefficient)^0.5*(Base Temperature-Ambient Temperature)

Heat Exchange by Radiation due to Geometric Arrangement

Go Heat Transfer = Emissivity*Area*[Stefan-BoltZ]*Shape Factor*(Temperature of Surface 1^(4)-Temperature of Surface 2^(4))

Black Bodies Heat Exchange by Radiation

Go Heat Transfer = Emissivity*[Stefan-BoltZ]*Area*(Temperature of Surface 1^(4)-Temperature of Surface 2^(4))

Heat Transfer According to Fourier's Law

Go Heat Flow Through a Body = -(Thermal Conductivity of Material*Surface Area of Heat Flow*Temperature Difference/Thickness)

One Dimensional Heat Flux

Go Heat Flux = -Thermal Conductivity of Fin/Wall Thickness*(Temperature of Wall 2-Temperature of Wall 1)

Newton's Law of Cooling

Go Heat Flux = Heat Transfer Coefficient*(Surface Temperature-Temperature of Characteristic Fluid)

Non Ideal Body Surface Emittance

Go Real Surface Radiant Surface Emittance = Emissivity*[Stefan-BoltZ]*Surface Temperature^(4)

Thermal Resistance in Conduction

Go Thermal Resistance = (Thickness)/(Thermal Conductivity of Fin*Cross Sectional Area)

Convective Processes Heat Transfer Coefficient

Go Heat Flux = Heat Transfer Coefficient*(Surface Temperature-Recovery temperature)

Thermal Conductivity given Critical Thickness of Insulation for Cylinder

Go Thermal Conductivity of Fin = Critical Thickness of Insulation*Heat Transfer Coefficient at Outer Surface

Critical Thickness of Insulation for Cylinder

Go Critical Thickness of Insulation = Thermal Conductivity of Fin/Heat Transfer Coefficient

Thermal Resistance in Convection Heat Transfer

Go Thermal Resistance = 1/(Exposed Surface Area*Co-efficient of Convective Heat Transfer)

Heat Transfer

Go Heat Flow Rate = Thermal Potential Difference/Thermal Resistance

Thermal Conductivity given Critical Thickness of Insulation for Cylinder Formula

Thermal Conductivity of Fin = Critical Thickness of Insulation*Heat Transfer Coefficient at Outer Surface
k_o = r_c*h_o

What is Heat Transfer Coefficient?

Heat transfer coefficient is a quantitative characteristic of convective heat transfer between a fluid medium (a fluid) and the surface (wall) flowed over by the fluid.

How to Calculate Thermal Conductivity given Critical Thickness of Insulation for Cylinder?

Thermal Conductivity given Critical Thickness of Insulation for Cylinder calculator uses Thermal Conductivity of Fin = Critical Thickness of Insulation*Heat Transfer Coefficient at Outer Surface to calculate the Thermal Conductivity of Fin, Thermal Conductivity given Critical Thickness of Insulation for Cylinder is the product of critical Thickness of Insulation and Heat Transfer Coefficient. Thermal Conductivity of Fin is denoted by k_o symbol.

How to calculate Thermal Conductivity given Critical Thickness of Insulation for Cylinder using this online calculator? To use this online calculator for Thermal Conductivity given Critical Thickness of Insulation for Cylinder, enter Critical Thickness of Insulation (r_c) & Heat Transfer Coefficient at Outer Surface (h_o) and hit the calculate button. Here is how the Thermal Conductivity given Critical Thickness of Insulation for Cylinder calculation can be explained with given input values -> 66 = 5*8.5.

FAQ

What is Thermal Conductivity given Critical Thickness of Insulation for Cylinder?

Thermal Conductivity given Critical Thickness of Insulation for Cylinder is the product of critical Thickness of Insulation and Heat Transfer Coefficient and is represented as k_o = r_c*h_o or Thermal Conductivity of Fin = Critical Thickness of Insulation*Heat Transfer Coefficient at Outer Surface. Critical thickness of insulation means maximum heat loss with min thermal resistance & Heat Transfer Coefficient at Outer Surface is the amount of heat transferred for a unit temperature difference between the surrounding fluid and the unit area of the insulation surface in unit time.

How to calculate Thermal Conductivity given Critical Thickness of Insulation for Cylinder?

Thermal Conductivity given Critical Thickness of Insulation for Cylinder is the product of critical Thickness of Insulation and Heat Transfer Coefficient is calculated using Thermal Conductivity of Fin = Critical Thickness of Insulation*Heat Transfer Coefficient at Outer Surface. To calculate Thermal Conductivity given Critical Thickness of Insulation for Cylinder, you need Critical Thickness of Insulation (r_c) & Heat Transfer Coefficient at Outer Surface (h_o). With our tool, you need to enter the respective value for Critical Thickness of Insulation & Heat Transfer Coefficient at Outer Surface and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

Home

FREE PDFs

🔍 Search