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## Credits

Vishwakarma Government Engineering College (VGEC), Ahmedabad
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## Volume Of Conductor Material Using Area Of X-section(1-Phase 2-Wire Mid-point Earthed OS) Solution

STEP 0: Pre-Calculation Summary
Formula Used
volume_of_conductor_material = (2)*Area Of 1-Φ 2-wire mid-point system*Length
V = (2)*a5*l
This formula uses 2 Variables
Variables Used
Area Of 1-Φ 2-wire mid-point system - The Area Of 1-Φ 2-wire mid-point system is the amount of two-dimensional space taken up by an object. (Measured in Square Meter)
Length - Length is the measurement or extent of something from end to end. (Measured in Meter)
STEP 1: Convert Input(s) to Base Unit
Area Of 1-Φ 2-wire mid-point system: 6 Square Meter --> 6 Square Meter No Conversion Required
Length: 3 Meter --> 3 Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
V = (2)*a5*l --> (2)*6*3
Evaluating ... ...
V = 36
STEP 3: Convert Result to Output's Unit
36 Cubic Meter --> No Conversion Required
FINAL ANSWER
36 Cubic Meter <-- Volume Of Conductor Material
(Calculation completed in 00.016 seconds)

## < 9 Area Of X-Section Calculators

Power Transmitted Using Area Of X-section(1-Phase 2-Wire Mid-point Earthed OS)
power_transmitted = sqrt((Area Of 1-Φ 2-wire mid-point system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2))/(Resistivity*Length)) Go
Maximum Voltage Using Area Of X-section(1-Phase 2-Wire Mid-point Earthed OS)
maximum_voltage = sqrt((Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 2-wire mid-point system*Line Losses*((cos(Theta))^2))) Go
RMS Voltage Using Area Of X-section(1-Phase 2-Wire Mid-point Earthed OS)
rms_voltage = sqrt((2*Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 2-wire mid-point system*Line Losses*((cos(Theta))^2))) Go
Power Factor Using Area Of X-section(1-Phase 2-Wire Mid-point Earthed OS)
power_factor = sqrt((Power Transmitted^2)*Resistivity*Length/(Area Of 1-Φ 2-wire mid-point system*Line Losses*(Maximum Voltage^2))) Go
Line Losses Using Area Of X-section(1-Phase 2-Wire Mid-point Earthed OS)
line_losses = (Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 2-wire mid-point system*(Maximum Voltage^2)*((cos(Theta))^2)) Go
Length Of Wire Using Area Of X-section(1-Phase 2-Wire Mid-point Earthed OS)
length = Area Of 1-Φ 2-wire mid-point system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/(Resistivity*(Power Transmitted^2)) Go
Resistivity Using Area Of X-section(1-Phase 2-Wire Mid-point Earthed OS)
resistivity = Area Of 1-Φ 2-wire mid-point system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/(Length*(Power Transmitted^2)) Go
Load Current Using Area Of X-Section(1-Phase 2-Wire Mid-point Earthed OS)
current5 = sqrt(Area Of 1-Φ 2-wire mid-point system*Line Losses/(2*Resistivity*Length)) Go
Volume Of Conductor Material Using Area Of X-section(1-Phase 2-Wire Mid-point Earthed OS)
volume_of_conductor_material = (2)*Area Of 1-Φ 2-wire mid-point system*Length Go

### Volume Of Conductor Material Using Area Of X-section(1-Phase 2-Wire Mid-point Earthed OS) Formula

volume_of_conductor_material = (2)*Area Of 1-Φ 2-wire mid-point system*Length
V = (2)*a5*l

## What is the value of maximum voltage and volume of conductor material in this system?

The volume of conductor material required in this system is 0.5/cos2θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is vm so that r.m.s. value of voltage between them is vm/√2.

## How to Calculate Volume Of Conductor Material Using Area Of X-section(1-Phase 2-Wire Mid-point Earthed OS)?

Volume Of Conductor Material Using Area Of X-section(1-Phase 2-Wire Mid-point Earthed OS) calculator uses volume_of_conductor_material = (2)*Area Of 1-Φ 2-wire mid-point system*Length to calculate the Volume Of Conductor Material, The Volume Of Conductor Material Using Area Of X-section(1-Phase 2-Wire Mid-point Earthed OS) formula is defined as the 3-dimensional space enclosed by a conductor material of a one-phase two-wire mid-point earthed overhead system. Volume Of Conductor Material and is denoted by V symbol.

How to calculate Volume Of Conductor Material Using Area Of X-section(1-Phase 2-Wire Mid-point Earthed OS) using this online calculator? To use this online calculator for Volume Of Conductor Material Using Area Of X-section(1-Phase 2-Wire Mid-point Earthed OS), enter Area Of 1-Φ 2-wire mid-point system (a5) and Length (l) and hit the calculate button. Here is how the Volume Of Conductor Material Using Area Of X-section(1-Phase 2-Wire Mid-point Earthed OS) calculation can be explained with given input values -> 36 = (2)*6*3.

### FAQ

What is Volume Of Conductor Material Using Area Of X-section(1-Phase 2-Wire Mid-point Earthed OS)?
The Volume Of Conductor Material Using Area Of X-section(1-Phase 2-Wire Mid-point Earthed OS) formula is defined as the 3-dimensional space enclosed by a conductor material of a one-phase two-wire mid-point earthed overhead system and is represented as V = (2)*a5*l or volume_of_conductor_material = (2)*Area Of 1-Φ 2-wire mid-point system*Length. The Area Of 1-Φ 2-wire mid-point system is the amount of two-dimensional space taken up by an object and Length is the measurement or extent of something from end to end.
How to calculate Volume Of Conductor Material Using Area Of X-section(1-Phase 2-Wire Mid-point Earthed OS)?
The Volume Of Conductor Material Using Area Of X-section(1-Phase 2-Wire Mid-point Earthed OS) formula is defined as the 3-dimensional space enclosed by a conductor material of a one-phase two-wire mid-point earthed overhead system is calculated using volume_of_conductor_material = (2)*Area Of 1-Φ 2-wire mid-point system*Length. To calculate Volume Of Conductor Material Using Area Of X-section(1-Phase 2-Wire Mid-point Earthed OS), you need Area Of 1-Φ 2-wire mid-point system (a5) and Length (l). With our tool, you need to enter the respective value for Area Of 1-Φ 2-wire mid-point system and Length and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Volume Of Conductor Material?
In this formula, Volume Of Conductor Material uses Area Of 1-Φ 2-wire mid-point system and Length. We can use 9 other way(s) to calculate the same, which is/are as follows -
• length = Area Of 1-Φ 2-wire mid-point system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/(Resistivity*(Power Transmitted^2))
• resistivity = Area Of 1-Φ 2-wire mid-point system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/(Length*(Power Transmitted^2))
• power_transmitted = sqrt((Area Of 1-Φ 2-wire mid-point system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2))/(Resistivity*Length))
• line_losses = (Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 2-wire mid-point system*(Maximum Voltage^2)*((cos(Theta))^2))
• maximum_voltage = sqrt((Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 2-wire mid-point system*Line Losses*((cos(Theta))^2)))
• rms_voltage = sqrt((2*Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 2-wire mid-point system*Line Losses*((cos(Theta))^2)))
• power_factor = sqrt((Power Transmitted^2)*Resistivity*Length/(Area Of 1-Φ 2-wire mid-point system*Line Losses*(Maximum Voltage^2)))
• current5 = sqrt(Area Of 1-Φ 2-wire mid-point system*Line Losses/(2*Resistivity*Length))
• volume_of_conductor_material = (2)*Area Of 1-Φ 2-wire mid-point system*Length
Where is the Volume Of Conductor Material Using Area Of X-section(1-Phase 2-Wire Mid-point Earthed OS) calculator used?
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