Field of Bar Magnet at Axial position Calculator

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✖Magnetic Moment is a determination of its tendency to get arranged through a magnetic field.ⓘ Magnetic Moment [M]			+10% -10%
✖Distance from center to point is the length of line segment measured from the center of a body to a particular point.ⓘ Distance from Center to Point [a]			+10% -10%

✖Field at Axial Position of Bar Magnet is the magnetic field generated by the magnet at the distance of d from the center of magnet.ⓘ Field of Bar Magnet at Axial position [B_axial]

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Formula

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Field of Bar Magnet at Axial position

Formula

`"B"_{"axial"} = (2*"[Permeability-vacuum]"*"M")/(4*pi*"a"^3)`

Example

`"4.080759Wb/m²"=(2*"[Permeability-vacuum]"*"90Wb/m²")/(4*pi*("16.4mm")^3)`

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Download Magnetic Field due to Current Formulas PDF

Field of Bar Magnet at Axial position Solution

STEP 0: Pre-Calculation Summary

Formula Used

Field at Axial Position of Bar Magnet = (2*[Permeability-vacuum]*Magnetic Moment)/(4*pi*Distance from Center to Point^3)
B_axial = (2*[Permeability-vacuum]*M)/(4*pi*a^3)
This formula uses 2 Constants, 3 Variables

Constants Used

[Permeability-vacuum] - Permeability of vacuum Value Taken As 1.2566E-6
pi - Archimedes' constant Value Taken As 3.14159265358979323846264338327950288

Variables Used

Field at Axial Position of Bar Magnet - (Measured in Tesla) - Field at Axial Position of Bar Magnet is the magnetic field generated by the magnet at the distance of d from the center of magnet.
Magnetic Moment - (Measured in Tesla) - Magnetic Moment is a determination of its tendency to get arranged through a magnetic field.
Distance from Center to Point - (Measured in Meter) - Distance from center to point is the length of line segment measured from the center of a body to a particular point.

STEP 1: Convert Input(s) to Base Unit

Magnetic Moment: 90 Weber per Square Meter --> 90 Tesla (Check conversion here)
Distance from Center to Point: 16.4 Millimeter --> 0.0164 Meter (Check conversion here)

STEP 2: Evaluate Formula

Substituting Input Values in Formula

B_axial = (2*[Permeability-vacuum]*M)/(4*pi*a^3) --> (2*[Permeability-vacuum]*90)/(4*pi*0.0164^3)

Evaluating ... ...

B_axial = 4.08075913001843

STEP 3: Convert Result to Output's Unit

4.08075913001843 Tesla -->4.08075913001843 Weber per Square Meter (Check conversion here)

FINAL ANSWER

4.08075913001843 ≈ 4.080759 Weber per Square Meter <-- Field at Axial Position of Bar Magnet

(Calculation completed in 00.004 seconds)

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Credits

Created by Aditya Ranjan

Indian Institute of Technology (IIT), Mumbai

Aditya Ranjan has created this Calculator and 6 more calculators!

Verified by Mayank Tayal

National Institute of Technology (NIT), Durgapur

Mayank Tayal has verified this Calculator and 10+ more calculators!

< 15 Magnetic Field due to Current Calculators

Magnetic Field due to Straight Conductor

Go Magnetic Field = ([Permeability-vacuum]*Electric Current)/(4*pi*Perpendicular Distance)*(cos(Theta 1)-cos(Theta 2))

Magnetic Field for Tangent Galvanometer

Go Horizontal Component of Earth's Magnetic Field = ([Permeability-vacuum]*Number of Turns of Coil*Electric Current)/(2*Radius of Ring*tan(Angle of Deflection of Galvanometer))

Force between Parallel Wires

Go Magnetic Force per Unit Length = ([Permeability-vacuum]*Electric Current in Conductor 1*Electric Current in Conductor 2)/(2*pi*Perpendicular Distance)

Current in Moving Coil Galvanometer

Go Electric Current = (Spring Constant*Angle of Deflection of Galvanometer)/(Number of Turns of Coil*Cross-Sectional Area*Magnetic Field)

Magnetic Field on Axis of Ring

Go Magnetic Field = ([Permeability-vacuum]*Electric Current*Radius of Ring^2)/(2*(Radius of Ring^2+Perpendicular Distance^2)^(3/2))

Time Period of Magnetometer

Go Time Period of Magnetometer = 2*pi*sqrt(Moment of Inertia/(Magnetic Moment*Horizontal Component of Earth's Magnetic Field))

Magnetic Field at Center of Arc

Go Field at Center of Arc = ([Permeability-vacuum]*Electric Current*Angle Obtained by Arc at Center)/(4*pi*Radius of Ring)

Field of Bar Magnet at Equatorial position

Go Field at Equitorial Position of Bar Magnet = ([Permeability-vacuum]*Magnetic Moment)/(4*pi*Distance from Center to Point^3)

Field of Bar Magnet at Axial position

Go Field at Axial Position of Bar Magnet = (2*[Permeability-vacuum]*Magnetic Moment)/(4*pi*Distance from Center to Point^3)

Field Inside Solenoid

Go Magnetic Field = ([Permeability-vacuum]*Electric Current*Number of Turns)/Length of Solonoid

Magnetic Field Due to Infinite Straight Wire

Go Magnetic Field = ([Permeability-vacuum]*Electric Current)/(2*pi*Perpendicular Distance)

Electric Current for Tangent Galvanometer

Go Electric Current = Reduction Factor of Tangent Galvanometer*tan(Angle of Deflection of Galvanometer)

Angle of Dip

Go Angle of Dip = arccos(Horizontal Component of Earth's Magnetic Field/Net Earth's Magnetic Field)

Magnetic Field at Center of Ring

Go Field at Center of Ring = ([Permeability-vacuum]*Electric Current)/(2*Radius of Ring)

Magnetic Permeability

Go Magnetic Permeability of Medium = Magnetic Field/Magnetic Field Intensity

Field of Bar Magnet at Axial position Formula

Field at Axial Position of Bar Magnet = (2*[Permeability-vacuum]*Magnetic Moment)/(4*pi*Distance from Center to Point^3)
B_axial = (2*[Permeability-vacuum]*M)/(4*pi*a^3)

how to calculate Magnetic field strength at a point due to a bar magnet on the axial line?

Let NS be a bar magnet of magnetic length 2l and having each pole of magnetic strength m . O is the center of magnet and P is a point on axial line at a distance r from the center O of magnet , at which magnetic field has to be measured .
B=mu_naught*2*M/4*Pi*d^3

Similarly at the south pole the force exerted would be as in equation,

Thus the strength at point B will be difference in force experienced at north pole and south pole

But dipole moment m = 2l.qm

How to Calculate Field of Bar Magnet at Axial position?

Field of Bar Magnet at Axial position calculator uses Field at Axial Position of Bar Magnet = (2*[Permeability-vacuum]*Magnetic Moment)/(4*pi*Distance from Center to Point^3) to calculate the Field at Axial Position of Bar Magnet, Field of Bar Magnet at axial position is defined as a region around a magnetic material or a moving electric charge within which the force of magnetism acts. Field at Axial Position of Bar Magnet is denoted by B_axial symbol.

How to calculate Field of Bar Magnet at Axial position using this online calculator? To use this online calculator for Field of Bar Magnet at Axial position, enter Magnetic Moment (M) & Distance from Center to Point (a) and hit the calculate button. Here is how the Field of Bar Magnet at Axial position calculation can be explained with given input values -> 4.080759 = (2*[Permeability-vacuum]*90)/(4*pi*0.0164^3).

FAQ

What is Field of Bar Magnet at Axial position?

Field of Bar Magnet at axial position is defined as a region around a magnetic material or a moving electric charge within which the force of magnetism acts and is represented as B_axial = (2*[Permeability-vacuum]*M)/(4*pi*a^3) or Field at Axial Position of Bar Magnet = (2*[Permeability-vacuum]*Magnetic Moment)/(4*pi*Distance from Center to Point^3). Magnetic Moment is a determination of its tendency to get arranged through a magnetic field & Distance from center to point is the length of line segment measured from the center of a body to a particular point.

How to calculate Field of Bar Magnet at Axial position?

Field of Bar Magnet at axial position is defined as a region around a magnetic material or a moving electric charge within which the force of magnetism acts is calculated using Field at Axial Position of Bar Magnet = (2*[Permeability-vacuum]*Magnetic Moment)/(4*pi*Distance from Center to Point^3). To calculate Field of Bar Magnet at Axial position, you need Magnetic Moment (M) & Distance from Center to Point (a). With our tool, you need to enter the respective value for Magnetic Moment & Distance from Center to Point and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

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