Field of Bar Magnet at Equatorial position Calculator

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✖Magnetic Moment is a determination of its tendency to get arranged through a magnetic field.ⓘ Magnetic Moment [M]			+10% -10%
✖Distance from center to point is the length of line segment measured from the center of a body to a particular point.ⓘ Distance from Center to Point [a]			+10% -10%

✖Field at Equitorial Position of Bar Magnet is magnetic field at perpendicular bisector of the segment joining the north pole and south pole of a bar magnet.ⓘ Field of Bar Magnet at Equatorial position [B_equitorial]

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Formula

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Field of Bar Magnet at Equatorial position

Formula

`"B"_{"equitorial"} = ("[Permeability-vacuum]"*"M")/(4*pi*"a"^3)`

Example

`"2.04038Wb/m²"=("[Permeability-vacuum]"*"90Wb/m²")/(4*pi*("16.4mm")^3)`

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Download Magnetic Field due to Current Formulas PDF

Field of Bar Magnet at Equatorial position Solution

STEP 0: Pre-Calculation Summary

Formula Used

Field at Equitorial Position of Bar Magnet = ([Permeability-vacuum]*Magnetic Moment)/(4*pi*Distance from Center to Point^3)
B_equitorial = ([Permeability-vacuum]*M)/(4*pi*a^3)
This formula uses 2 Constants, 3 Variables

Constants Used

[Permeability-vacuum] - Permeability of vacuum Value Taken As 1.2566E-6
pi - Archimedes' constant Value Taken As 3.14159265358979323846264338327950288

Variables Used

Field at Equitorial Position of Bar Magnet - (Measured in Tesla) - Field at Equitorial Position of Bar Magnet is magnetic field at perpendicular bisector of the segment joining the north pole and south pole of a bar magnet.
Magnetic Moment - (Measured in Tesla) - Magnetic Moment is a determination of its tendency to get arranged through a magnetic field.
Distance from Center to Point - (Measured in Meter) - Distance from center to point is the length of line segment measured from the center of a body to a particular point.

STEP 1: Convert Input(s) to Base Unit

Magnetic Moment: 90 Weber per Square Meter --> 90 Tesla (Check conversion here)
Distance from Center to Point: 16.4 Millimeter --> 0.0164 Meter (Check conversion here)

STEP 2: Evaluate Formula

Substituting Input Values in Formula

B_equitorial = ([Permeability-vacuum]*M)/(4*pi*a^3) --> ([Permeability-vacuum]*90)/(4*pi*0.0164^3)

Evaluating ... ...

B_equitorial = 2.04037956500921

STEP 3: Convert Result to Output's Unit

2.04037956500921 Tesla -->2.04037956500921 Weber per Square Meter (Check conversion here)

FINAL ANSWER

2.04037956500921 ≈ 2.04038 Weber per Square Meter <-- Field at Equitorial Position of Bar Magnet

(Calculation completed in 00.004 seconds)

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Created by Aditya Ranjan

Indian Institute of Technology (IIT), Mumbai

Aditya Ranjan has created this Calculator and 6 more calculators!

Verified by Mona Gladys

St Joseph's College (SJC), Bengaluru

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< 15 Magnetic Field due to Current Calculators

Magnetic Field due to Straight Conductor

Go Magnetic Field = ([Permeability-vacuum]*Electric Current)/(4*pi*Perpendicular Distance)*(cos(Theta 1)-cos(Theta 2))

Magnetic Field for Tangent Galvanometer

Go Horizontal Component of Earth's Magnetic Field = ([Permeability-vacuum]*Number of Turns of Coil*Electric Current)/(2*Radius of Ring*tan(Angle of Deflection of Galvanometer))

Force between Parallel Wires

Go Magnetic Force per Unit Length = ([Permeability-vacuum]*Electric Current in Conductor 1*Electric Current in Conductor 2)/(2*pi*Perpendicular Distance)

Current in Moving Coil Galvanometer

Go Electric Current = (Spring Constant*Angle of Deflection of Galvanometer)/(Number of Turns of Coil*Cross-Sectional Area*Magnetic Field)

Magnetic Field on Axis of Ring

Go Magnetic Field = ([Permeability-vacuum]*Electric Current*Radius of Ring^2)/(2*(Radius of Ring^2+Perpendicular Distance^2)^(3/2))

Time Period of Magnetometer

Go Time Period of Magnetometer = 2*pi*sqrt(Moment of Inertia/(Magnetic Moment*Horizontal Component of Earth's Magnetic Field))

Magnetic Field at Center of Arc

Go Field at Center of Arc = ([Permeability-vacuum]*Electric Current*Angle Obtained by Arc at Center)/(4*pi*Radius of Ring)

Field of Bar Magnet at Equatorial position

Go Field at Equitorial Position of Bar Magnet = ([Permeability-vacuum]*Magnetic Moment)/(4*pi*Distance from Center to Point^3)

Field of Bar Magnet at Axial position

Go Field at Axial Position of Bar Magnet = (2*[Permeability-vacuum]*Magnetic Moment)/(4*pi*Distance from Center to Point^3)

Field Inside Solenoid

Go Magnetic Field = ([Permeability-vacuum]*Electric Current*Number of Turns)/Length of Solonoid

Magnetic Field Due to Infinite Straight Wire

Go Magnetic Field = ([Permeability-vacuum]*Electric Current)/(2*pi*Perpendicular Distance)

Electric Current for Tangent Galvanometer

Go Electric Current = Reduction Factor of Tangent Galvanometer*tan(Angle of Deflection of Galvanometer)

Angle of Dip

Go Angle of Dip = arccos(Horizontal Component of Earth's Magnetic Field/Net Earth's Magnetic Field)

Magnetic Field at Center of Ring

Go Field at Center of Ring = ([Permeability-vacuum]*Electric Current)/(2*Radius of Ring)

Magnetic Permeability

Go Magnetic Permeability of Medium = Magnetic Field/Magnetic Field Intensity

Field of Bar Magnet at Equatorial position Formula

Field at Equitorial Position of Bar Magnet = ([Permeability-vacuum]*Magnetic Moment)/(4*pi*Distance from Center to Point^3)
B_equitorial = ([Permeability-vacuum]*M)/(4*pi*a^3)

How to calculate magnetic field at a point along the equatorial line of a bar magnet ?

NS is the bar magnet of length 2l and pole strength m. P is a point on the equatorial line at a distance d from its mid point O (Fig.).

Magnetic induction (B1) at P due to north pole of the magnet,

B1 = mu_0/4π . m/NP2 along NP

= Mu_0/4π . m/(d2+l2) along NP

NP2 = NO2 + OP2

Magnetic induction (B2) at P due to south pole of the magnet,

B2 = mu_0/4π . m/PS2 along PS

= mu_0/4π . m/(d2+l2) along PS

Resolving B1 and B2 into their horizontal and vertical components.

Vertical components B1 sin θ and B2 sin θ are equal and opposite and therefore cancel each other (Fig.).

The horizontal components B1 cos θ and B2 cos θ will get added along PT.

Resultant magnetic induction at P due to the bar magnet is

B = B1 cos θ + B2 cos θ. (along PT)

After apply B1 and B2

B = = mu_0/4π . M/d3

The direction of B is along PT parallel to NS.

How to Calculate Field of Bar Magnet at Equatorial position?

Field of Bar Magnet at Equatorial position calculator uses Field at Equitorial Position of Bar Magnet = ([Permeability-vacuum]*Magnetic Moment)/(4*pi*Distance from Center to Point^3) to calculate the Field at Equitorial Position of Bar Magnet, Field of Bar Magnet at equatorial position is the magnetic field generated by bar magnet at the point that goes through its perpendicular bisector at a distance of d from the center of a bar magnet. Field at Equitorial Position of Bar Magnet is denoted by B_equitorial symbol.

How to calculate Field of Bar Magnet at Equatorial position using this online calculator? To use this online calculator for Field of Bar Magnet at Equatorial position, enter Magnetic Moment (M) & Distance from Center to Point (a) and hit the calculate button. Here is how the Field of Bar Magnet at Equatorial position calculation can be explained with given input values -> 2.04038 = ([Permeability-vacuum]*90)/(4*pi*0.0164^3).

FAQ

What is Field of Bar Magnet at Equatorial position?

Field of Bar Magnet at equatorial position is the magnetic field generated by bar magnet at the point that goes through its perpendicular bisector at a distance of d from the center of a bar magnet and is represented as B_equitorial = ([Permeability-vacuum]*M)/(4*pi*a^3) or Field at Equitorial Position of Bar Magnet = ([Permeability-vacuum]*Magnetic Moment)/(4*pi*Distance from Center to Point^3). Magnetic Moment is a determination of its tendency to get arranged through a magnetic field & Distance from center to point is the length of line segment measured from the center of a body to a particular point.

How to calculate Field of Bar Magnet at Equatorial position?

Field of Bar Magnet at equatorial position is the magnetic field generated by bar magnet at the point that goes through its perpendicular bisector at a distance of d from the center of a bar magnet is calculated using Field at Equitorial Position of Bar Magnet = ([Permeability-vacuum]*Magnetic Moment)/(4*pi*Distance from Center to Point^3). To calculate Field of Bar Magnet at Equatorial position, you need Magnetic Moment (M) & Distance from Center to Point (a). With our tool, you need to enter the respective value for Magnetic Moment & Distance from Center to Point and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

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