Time Period of Magnetometer Solution

STEP 0: Pre-Calculation Summary
Formula Used
Time Period of Magnetometer = 2*pi*sqrt(Moment of Inertia/(Magnetic Moment*Horizontal Component of Earth's Magnetic Field))
T = 2*pi*sqrt(I/(M*BH))
This formula uses 1 Constants, 1 Functions, 4 Variables
Constants Used
pi - Archimedes' constant Value Taken As 3.14159265358979323846264338327950288
Functions Used
sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)
Variables Used
Time Period of Magnetometer - (Measured in Second) - Time Period of Magnetometer is the time period of oscillation of experimental bar magnet in earth's magnetic field.
Moment of Inertia - (Measured in Kilogram Square Meter) - Moment of Inertia is the measure of the resistance of a body to angular acceleration about a given axis.
Magnetic Moment - (Measured in Tesla) - Magnetic Moment is a determination of its tendency to get arranged through a magnetic field.
Horizontal Component of Earth's Magnetic Field - (Measured in Tesla) - Horizontal Component of Earth's Magnetic Field Vector is denoted by the symbol BH.
STEP 1: Convert Input(s) to Base Unit
Moment of Inertia: 1.125 Kilogram Square Meter --> 1.125 Kilogram Square Meter No Conversion Required
Magnetic Moment: 90 Weber per Square Meter --> 90 Tesla (Check conversion here)
Horizontal Component of Earth's Magnetic Field: 2E-05 Weber per Square Meter --> 2E-05 Tesla (Check conversion here)
STEP 2: Evaluate Formula
Substituting Input Values in Formula
T = 2*pi*sqrt(I/(M*BH)) --> 2*pi*sqrt(1.125/(90*2E-05))
Evaluating ... ...
T = 157.07963267949
STEP 3: Convert Result to Output's Unit
157.07963267949 Second --> No Conversion Required
FINAL ANSWER
157.07963267949 157.0796 Second <-- Time Period of Magnetometer
(Calculation completed in 00.004 seconds)

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15 Magnetic Field due to Current Calculators

Magnetic Field due to Straight Conductor
Go Magnetic Field = ([Permeability-vacuum]*Electric Current)/(4*pi*Perpendicular Distance)*(cos(Theta 1)-cos(Theta 2))
Magnetic Field for Tangent Galvanometer
Go Horizontal Component of Earth's Magnetic Field = ([Permeability-vacuum]*Number of Turns of Coil*Electric Current)/(2*Radius of Ring*tan(Angle of Deflection of Galvanometer))
Force between Parallel Wires
Go Magnetic Force per Unit Length = ([Permeability-vacuum]*Electric Current in Conductor 1*Electric Current in Conductor 2)/(2*pi*Perpendicular Distance)
Current in Moving Coil Galvanometer
Go Electric Current = (Spring Constant*Angle of Deflection of Galvanometer)/(Number of Turns of Coil*Cross-Sectional Area*Magnetic Field)
Magnetic Field on Axis of Ring
Go Magnetic Field = ([Permeability-vacuum]*Electric Current*Radius of Ring^2)/(2*(Radius of Ring^2+Perpendicular Distance^2)^(3/2))
Time Period of Magnetometer
Go Time Period of Magnetometer = 2*pi*sqrt(Moment of Inertia/(Magnetic Moment*Horizontal Component of Earth's Magnetic Field))
Magnetic Field at Center of Arc
Go Field at Center of Arc = ([Permeability-vacuum]*Electric Current*Angle Obtained by Arc at Center)/(4*pi*Radius of Ring)
Field of Bar Magnet at Equatorial position
Go Field at Equitorial Position of Bar Magnet = ([Permeability-vacuum]*Magnetic Moment)/(4*pi*Distance from Center to Point^3)
Field of Bar Magnet at Axial position
Go Field at Axial Position of Bar Magnet = (2*[Permeability-vacuum]*Magnetic Moment)/(4*pi*Distance from Center to Point^3)
Field Inside Solenoid
Go Magnetic Field = ([Permeability-vacuum]*Electric Current*Number of Turns)/Length of Solonoid
Magnetic Field Due to Infinite Straight Wire
Go Magnetic Field = ([Permeability-vacuum]*Electric Current)/(2*pi*Perpendicular Distance)
Electric Current for Tangent Galvanometer
Go Electric Current = Reduction Factor of Tangent Galvanometer*tan(Angle of Deflection of Galvanometer)
Angle of Dip
Go Angle of Dip = arccos(Horizontal Component of Earth's Magnetic Field/Net Earth's Magnetic Field)
Magnetic Field at Center of Ring
Go Field at Center of Ring = ([Permeability-vacuum]*Electric Current)/(2*Radius of Ring)
Magnetic Permeability
Go Magnetic Permeability of Medium = Magnetic Field/Magnetic Field Intensity

Time Period of Magnetometer Formula

Time Period of Magnetometer = 2*pi*sqrt(Moment of Inertia/(Magnetic Moment*Horizontal Component of Earth's Magnetic Field))
T = 2*pi*sqrt(I/(M*BH))

What is a Vibration Magnetometer ?

Vibration magnetometer is used for comparison of magnetic moments and magnetic fields. This device works on the principle, that whenever a freely suspended magnet in a uniform magnetic field, is disturbed from it's equilibrium position, it starts vibrating about the mean position. It is an instrument used to compare magnetic moments of two bar magnets, comparison of horizontal components of earth's magnetic field at two places and for measuring the horizontal component of earth's magnetic field .

How to Calculate Time Period of Magnetometer?

Time Period of Magnetometer calculator uses Time Period of Magnetometer = 2*pi*sqrt(Moment of Inertia/(Magnetic Moment*Horizontal Component of Earth's Magnetic Field)) to calculate the Time Period of Magnetometer, The Time Period of Magnetometer formula is defined as the time period of oscillation of a bar magnet in the horizontal component of the earth's magnetic field. Time Period of Magnetometer is denoted by T symbol.

How to calculate Time Period of Magnetometer using this online calculator? To use this online calculator for Time Period of Magnetometer, enter Moment of Inertia (I), Magnetic Moment (M) & Horizontal Component of Earth's Magnetic Field (BH) and hit the calculate button. Here is how the Time Period of Magnetometer calculation can be explained with given input values -> 157.0796 = 2*pi*sqrt(1.125/(90*2E-05)).

FAQ

What is Time Period of Magnetometer?
The Time Period of Magnetometer formula is defined as the time period of oscillation of a bar magnet in the horizontal component of the earth's magnetic field and is represented as T = 2*pi*sqrt(I/(M*BH)) or Time Period of Magnetometer = 2*pi*sqrt(Moment of Inertia/(Magnetic Moment*Horizontal Component of Earth's Magnetic Field)). Moment of Inertia is the measure of the resistance of a body to angular acceleration about a given axis, Magnetic Moment is a determination of its tendency to get arranged through a magnetic field & Horizontal Component of Earth's Magnetic Field Vector is denoted by the symbol BH.
How to calculate Time Period of Magnetometer?
The Time Period of Magnetometer formula is defined as the time period of oscillation of a bar magnet in the horizontal component of the earth's magnetic field is calculated using Time Period of Magnetometer = 2*pi*sqrt(Moment of Inertia/(Magnetic Moment*Horizontal Component of Earth's Magnetic Field)). To calculate Time Period of Magnetometer, you need Moment of Inertia (I), Magnetic Moment (M) & Horizontal Component of Earth's Magnetic Field (BH). With our tool, you need to enter the respective value for Moment of Inertia, Magnetic Moment & Horizontal Component of Earth's Magnetic Field and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
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