11 Other formulas that you can solve using the same Inputs

Total Surface Area of a Cone
Total Surface Area=pi*Radius*(Radius+sqrt(Radius^2+Height^2)) GO
Lateral Surface Area of a Cone
Lateral Surface Area=pi*Radius*sqrt(Radius^2+Height^2) GO
Surface Area of a Capsule
Surface Area=2*pi*Radius*(2*Radius+Side) GO
Volume of a Capsule
Volume=pi*(Radius)^2*((4/3)*Radius+Side) GO
Volume of a Circular Cone
Volume=(1/3)*pi*(Radius)^2*Height GO
Base Surface Area of a Cone
Base Surface Area=pi*Radius^2 GO
Top Surface Area of a Cylinder
Top Surface Area=pi*Radius^2 GO
Volume of a Circular Cylinder
Volume=pi*(Radius)^2*Height GO
Area of a Circle when radius is given
Area of Circle=pi*Radius^2 GO
Volume of a Hemisphere
Volume=(2/3)*pi*(Radius)^3 GO
Volume of a Sphere
Volume=(4/3)*pi*(Radius)^3 GO

5 Other formulas that calculate the same Output

Gravitational field of a ring
Gravitational Field=-([G.]*Mass*Distance from center to a point)/((Radius of ring)^2+(Distance from center to a point)^2)^(3/2) GO
Gravitational field of a ring when cosθ is given
Gravitational Field=-([G.]*Mass*cos(Theta))/((Distance from center to a point)^2+(Radius of ring)^2)^2 GO
Gravitational field when point P is inside of non conducting solid sphere
Gravitational Field=-([G.]*Mass*Distance from center to a point)/(radius)^3 GO
Gravitational field when point P is outside of non conducting solid sphere
Gravitational Field=-([G.]*Mass)/(Distance from center to a point)^2 GO
Gravitational field when point P is outside of conducting solid sphere
Gravitational Field=-([G.]*Mass)/(Distance from center to a point)^2 GO

Gravitational field of a thin circular disc Formula

Gravitational Field=-(2*[G.]*Mass*(1-cos(Theta)))/(Radius)^2
More formulas
Gravitational potential of a ring GO
Gravitational field of a ring GO
Gravitational field of a ring when cosθ is given GO
Gravitational potential of a thin circular disc GO
Gravitational potential when point p is inside of non conducting solid sphere GO
Gravitational field when point P is inside of non conducting solid sphere GO
Gravitational potential when point P is outside of non-conducting solid sphere GO
Gravitational potential when point p is inside of conducting solid sphere GO
Gravitational field when point P is outside of non conducting solid sphere GO
Gravitational field when point P is outside of conducting solid sphere GO
Gravitational potential when point p is outside of conducting solid sphere GO
Variation of acceleration due to gravity on altitude GO
Variation of acceleration due to gravity on the depth GO
Variation of acceleration due to gravity effect on the surface of earth GO

How is gravitational field of a thin circular disc calculated?

The gravitational field of a thin circular disc is calculated by the formula E = 2GM[1-cosθ] / a2 where G is the universal gravitational constant whose value is G = 6.674×10-11 m3⋅kg-1⋅s-2 , M is the mass , cosθ is the angle between the line of that point to center of ring and line from that point to circumference of ring,a is the radius of the ring and r is the distance from center of ring to the point where mass is placed.

What is the unit and dimension of gravitational field of a ring?

The unit of gravitational field intensity is N/kg. The dimensional formula is given by [M0L1T-2].

How to Calculate Gravitational field of a thin circular disc?

Gravitational field of a thin circular disc calculator uses Gravitational Field=-(2*[G.]*Mass*(1-cos(Theta)))/(Radius)^2 to calculate the Gravitational Field, Gravitational field of a thin circular disc at any point is equal to the negative gradient at that point. Gravitational Field and is denoted by E symbol.

How to calculate Gravitational field of a thin circular disc using this online calculator? To use this online calculator for Gravitational field of a thin circular disc, enter Radius (r), Mass (m) and Theta (ϑ) and hit the calculate button. Here is how the Gravitational field of a thin circular disc calculation can be explained with given input values -> -1.957E-8 = -(2*[G.]*35.45*(1-cos(30)))/(0.18)^2.

FAQ

What is Gravitational field of a thin circular disc?
Gravitational field of a thin circular disc at any point is equal to the negative gradient at that point and is represented as E=-(2*[G.]*m*(1-cos(ϑ)))/(r)^2 or Gravitational Field=-(2*[G.]*Mass*(1-cos(Theta)))/(Radius)^2. Radius is a radial line from the focus to any point of a curve, Mass is the quantity of matter in a body regardless of its volume or of any forces acting on it and Theta is an angle that can be defined as the figure formed by two rays meeting at a common endpoint.
How to calculate Gravitational field of a thin circular disc?
Gravitational field of a thin circular disc at any point is equal to the negative gradient at that point is calculated using Gravitational Field=-(2*[G.]*Mass*(1-cos(Theta)))/(Radius)^2. To calculate Gravitational field of a thin circular disc, you need Radius (r), Mass (m) and Theta (ϑ). With our tool, you need to enter the respective value for Radius, Mass and Theta and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Gravitational Field?
In this formula, Gravitational Field uses Radius, Mass and Theta. We can use 5 other way(s) to calculate the same, which is/are as follows -
  • Gravitational Field=-([G.]*Mass*Distance from center to a point)/((Radius of ring)^2+(Distance from center to a point)^2)^(3/2)
  • Gravitational Field=-([G.]*Mass*cos(Theta))/((Distance from center to a point)^2+(Radius of ring)^2)^2
  • Gravitational Field=-([G.]*Mass*Distance from center to a point)/(radius)^3
  • Gravitational Field=-([G.]*Mass)/(Distance from center to a point)^2
  • Gravitational Field=-([G.]*Mass)/(Distance from center to a point)^2
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