Mayank Tayal
National Institute of Technology (NIT), Durgapur
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Rushi Shah
K J Somaiya College of Engineering (K J Somaiya), Mumbai
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## < 11 Other formulas that you can solve using the same Inputs

Displacement of Body when initial velocity, time and acceleration are given
Displacement of Body=(Initial Velocity*Time Taken to Travel)+(Acceleration*(Time Taken to Travel)^2)/2 GO
Displacement of Body when initial velocity, final velocity and acceleration are given
Displacement of Body=((Final Velocity)^2-(Initial Velocity)^2)/(2*Acceleration) GO
Displacement of Body when initial velocity, final velocity and time are given
Displacement of Body=((Initial Velocity+Final Velocity)*Time Taken to Travel)/2 GO
Impulsive Force
Impulsive Force=(Mass*(Final Velocity-Initial Velocity))/Time Taken to Travel GO
Final Velocity of freely falling body from height h, when it reaches ground
Velocity on reaching ground=sqrt(2*Acceleration Due To Gravity*Height) GO
Final Velocity of body
Final Velocity=Initial Velocity+Acceleration*(Time Taken to Travel) GO
Archimedes Principle
Archimedes Principle=Density*Acceleration Due To Gravity*Velocity GO
Distance Traveled
Distance Traveled=Initial Velocity*T+(1/2)*Acceleration*(T)^2 GO
Potential Energy
Potential Energy=Mass*Acceleration Due To Gravity*Height GO
Average Velocity of body when initial and final velocity are given
Average Velocity=(Initial Velocity+Final Velocity)/2 GO
Pressure when density and height are given
Pressure=Density*Acceleration Due To Gravity*Height GO

## < 11 Other formulas that calculate the same Output

Height of a trapezoid when area and sum of parallel sides are given
Height=(2*Area)/Sum of parallel sides of a trapezoid GO
Height of a triangular prism when lateral surface area is given
Height=Lateral Surface Area/(Side A+Side B+Side C) GO
Height of an isosceles trapezoid
Height=sqrt(Side C^2-0.25*(Side A-Side B)^2) GO
Altitude of an isosceles triangle
Height=sqrt((Side A)^2+((Side B)^2/4)) GO
Height of a triangular prism when base and volume are given
Height=(2*Volume)/(Base*Length) GO
Altitude of the largest right pyramid with a square base that can be inscribed in a sphere of radius a
Height=4*Radius of Sphere/3 GO
Height of Cone inscribed in a sphere for maximum volume of cone in terms of radius of sphere
Height=4*Radius of Sphere/3 GO
Height of Cone circumscribing a sphere such that volume of cone is minimum
Height=4*Radius of Sphere GO
Height of parabolic section that can be cut from a cone for maximum area of parabolic section
Height=0.75*Slant Height GO
Height of a circular cylinder of maximum convex surface area in a given circular cone
Height=Height of Cone/2 GO
Height of Largest right circular cylinder that can be inscribed within a cone
Height=Height of Cone/3 GO

### Maximum height attained by object Formula

Height=((Initial Velocity*sin(Theta))^2)/(2*Acceleration Due To Gravity)
More formulas
Time of flight GO
Range of motion GO
Initial Speed when time of flight is given GO
Initial Speed when Maximum Height is given GO
Initial Velocity when Range is given GO
Maximum Height attained GO
Time of Flight for Inclined Projectile GO
Maximum Range of Flight GO

## What is Projectile Motion ?

Projectile motion is a type of two-dimensional motion or motion in a plane. It is assumed that the only force acting on a projectile (the object experiencing projectile motion) is the force due to gravity.

## How to Calculate Maximum height attained by object?

Maximum height attained by object calculator uses Height=((Initial Velocity*sin(Theta))^2)/(2*Acceleration Due To Gravity) to calculate the Height, The Maximum height attained by object formula is defined as ( ( initial_velocity * sin ( theta ) ) ^ 2 ) / ( 2 * acceleration_due_to_gravity ). Height and is denoted by h symbol.

How to calculate Maximum height attained by object using this online calculator? To use this online calculator for Maximum height attained by object, enter Acceleration Due To Gravity (g), Initial Velocity (u) and Theta (ϑ) and hit the calculate button. Here is how the Maximum height attained by object calculation can be explained with given input values -> 25.82908 = ((45*sin(30))^2)/(2*9.8).

### FAQ

What is Maximum height attained by object?
The Maximum height attained by object formula is defined as ( ( initial_velocity * sin ( theta ) ) ^ 2 ) / ( 2 * acceleration_due_to_gravity ) and is represented as h=((u*sin(ϑ))^2)/(2*g) or Height=((Initial Velocity*sin(Theta))^2)/(2*Acceleration Due To Gravity). The Acceleration Due To Gravity is acceleration gained by an object because of gravitational force, Initial Velocity is the velocity at which motion starts and Theta is an angle that can be defined as the figure formed by two rays meeting at a common endpoint.
How to calculate Maximum height attained by object?
The Maximum height attained by object formula is defined as ( ( initial_velocity * sin ( theta ) ) ^ 2 ) / ( 2 * acceleration_due_to_gravity ) is calculated using Height=((Initial Velocity*sin(Theta))^2)/(2*Acceleration Due To Gravity). To calculate Maximum height attained by object, you need Acceleration Due To Gravity (g), Initial Velocity (u) and Theta (ϑ). With our tool, you need to enter the respective value for Acceleration Due To Gravity, Initial Velocity and Theta and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Height?
In this formula, Height uses Acceleration Due To Gravity, Initial Velocity and Theta. We can use 11 other way(s) to calculate the same, which is/are as follows -
• Height=4*Radius of Sphere/3
• Height=4*Radius of Sphere
• Height=Height of Cone/3
• Height=4*Radius of Sphere/3
• Height=Height of Cone/2
• Height=0.75*Slant Height
• Height=sqrt(Side C^2-0.25*(Side A-Side B)^2)
• Height=(2*Area)/Sum of parallel sides of a trapezoid
• Height=sqrt((Side A)^2+((Side B)^2/4))
• Height=(2*Volume)/(Base*Length)
• Height=Lateral Surface Area/(Side A+Side B+Side C)
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