Maximum Height Attained by Object Solution

STEP 0: Pre-Calculation Summary
Formula Used
Height of Crack = ((Initial Velocity*sin(Angle of Projection))^2)/(2*Acceleration due to Gravity)
h = ((u*sin(θpr))^2)/(2*g)
This formula uses 1 Functions, 4 Variables
Functions Used
sin - Sine is a trigonometric function that describes the ratio of the length of the opposite side of a right triangle to the length of the hypotenuse., sin(Angle)
Variables Used
Height of Crack - (Measured in Meter) - Height of Crack is the size of a flaw or crack in a material that can lead to catastrophic failure under a given stress.
Initial Velocity - (Measured in Meter per Second) - Initial Velocity is the velocity at which motion starts.
Angle of Projection - (Measured in Radian) - Angle of Projection is angle made by the particle with horizontal when projected upwards with some initial velocity.
Acceleration due to Gravity - (Measured in Meter per Square Second) - Acceleration due to Gravity is acceleration gained by an object because of gravitational force.
STEP 1: Convert Input(s) to Base Unit
Initial Velocity: 35 Meter per Second --> 35 Meter per Second No Conversion Required
Angle of Projection: 0.4 Radian --> 0.4 Radian No Conversion Required
Acceleration due to Gravity: 9.8 Meter per Square Second --> 9.8 Meter per Square Second No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
h = ((u*sin(θpr))^2)/(2*g) --> ((35*sin(0.4))^2)/(2*9.8)
Evaluating ... ...
h = 9.47791533290108
STEP 3: Convert Result to Output's Unit
9.47791533290108 Meter -->9477.91533290108 Millimeter (Check conversion ​here)
FINAL ANSWER
9477.91533290108 9477.915 Millimeter <-- Height of Crack
(Calculation completed in 00.011 seconds)

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Created by Mayank Tayal
National Institute of Technology (NIT), Durgapur
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National Institute Of Technology (NIT), Hamirpur
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7 Projectile Motion ( object thrown at some angle 'theta' ) Calculators

Height of Object given Horizontal Distance
​ Go Height of Crack = Horizontal Distance*tan(Angle of Projection)-(Acceleration due to Gravity*Horizontal Distance^2)/(2*(Initial Velocity*cos(Angle of Projection))^2)
Initial Speed given Maximum Height
​ Go Initial Velocity = (sqrt(Maximum Height*2*Acceleration due to Gravity))/sin(Angle of Projection)
Initial Velocity using Range
​ Go Initial Velocity = sqrt(Acceleration due to Gravity*Range of Motion/sin(2*Angle of Projection))
Maximum Height Attained by Object
​ Go Height of Crack = ((Initial Velocity*sin(Angle of Projection))^2)/(2*Acceleration due to Gravity)
Range of Projectile Motion
​ Go Range of Motion = (Initial Velocity^2*sin(2*Angle of Projection))/Acceleration due to Gravity
Initial Speed using Time of Flight
​ Go Initial Velocity = (Time of Flight*Acceleration due to Gravity)/(2*sin(Angle of Projection))
Time of Flight
​ Go Time of Flight = (2*Initial Velocity*sin(Angle of Projection))/Acceleration due to Gravity

Maximum Height Attained by Object Formula

Height of Crack = ((Initial Velocity*sin(Angle of Projection))^2)/(2*Acceleration due to Gravity)
h = ((u*sin(θpr))^2)/(2*g)

What is Projectile Motion ?

Projectile motion is a type of two-dimensional motion or motion in a plane. It is assumed that the only force acting on a projectile (the object experiencing projectile motion) is the force due to gravity.

How to Calculate Maximum Height Attained by Object?

Maximum Height Attained by Object calculator uses Height of Crack = ((Initial Velocity*sin(Angle of Projection))^2)/(2*Acceleration due to Gravity) to calculate the Height of Crack, The Maximum Height Attained by Object formula is defined when the projectile reaches zero vertical velocity. From this point, the vertical component of the velocity vector will point downwards. Height of Crack is denoted by h symbol.

How to calculate Maximum Height Attained by Object using this online calculator? To use this online calculator for Maximum Height Attained by Object, enter Initial Velocity (u), Angle of Projection pr) & Acceleration due to Gravity (g) and hit the calculate button. Here is how the Maximum Height Attained by Object calculation can be explained with given input values -> 9.477915 = ((35*sin(0.4))^2)/(2*9.8).

FAQ

What is Maximum Height Attained by Object?
The Maximum Height Attained by Object formula is defined when the projectile reaches zero vertical velocity. From this point, the vertical component of the velocity vector will point downwards and is represented as h = ((u*sin(θpr))^2)/(2*g) or Height of Crack = ((Initial Velocity*sin(Angle of Projection))^2)/(2*Acceleration due to Gravity). Initial Velocity is the velocity at which motion starts, Angle of Projection is angle made by the particle with horizontal when projected upwards with some initial velocity & Acceleration due to Gravity is acceleration gained by an object because of gravitational force.
How to calculate Maximum Height Attained by Object?
The Maximum Height Attained by Object formula is defined when the projectile reaches zero vertical velocity. From this point, the vertical component of the velocity vector will point downwards is calculated using Height of Crack = ((Initial Velocity*sin(Angle of Projection))^2)/(2*Acceleration due to Gravity). To calculate Maximum Height Attained by Object, you need Initial Velocity (u), Angle of Projection pr) & Acceleration due to Gravity (g). With our tool, you need to enter the respective value for Initial Velocity, Angle of Projection & Acceleration due to Gravity and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Height of Crack?
In this formula, Height of Crack uses Initial Velocity, Angle of Projection & Acceleration due to Gravity. We can use 1 other way(s) to calculate the same, which is/are as follows -
  • Height of Crack = Horizontal Distance*tan(Angle of Projection)-(Acceleration due to Gravity*Horizontal Distance^2)/(2*(Initial Velocity*cos(Angle of Projection))^2)
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