 Anshika Arya
National Institute Of Technology (NIT), Hamirpur
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## < 11 Other formulas that you can solve using the same Inputs

Restoring torque for simple pendulum
Torque=Mass*Acceleration Due To Gravity*sin(Angle through which the string is displaced)*Length of the string GO
Weight
Weight of body on which frictional force is applied=Mass*Acceleration Due To Gravity GO
Minimum periodic time of SHM for compound pendulum
Time Period SHM=2*pi*sqrt(2*Radius of gyration/Acceleration Due To Gravity) GO
Deflection of spring when mass m is attached to it
Deflection of Spring=Mass*Acceleration Due To Gravity/Stiffness of spring GO
Periodic time for one beat of SHM
Time Period SHM=pi*sqrt(Length of the string/Acceleration Due To Gravity) GO
Final Velocity of freely falling body from height h, when it reaches ground
Velocity on reaching ground=sqrt(2*Acceleration Due To Gravity*Height) GO
Force of Friction between the cylinder and the surface of inclined plane if cylinder is rolling without slipping down a ramp
Force=(Mass*Acceleration Due To Gravity*sin(Angle of Inclination))/3 GO
Periodic time for SHM
Time Period SHM=2*pi*sqrt(Displacement/Acceleration Due To Gravity) GO
Archimedes Principle
Archimedes Principle=Density*Acceleration Due To Gravity*Velocity GO
Potential Energy
Potential Energy=Mass*Acceleration Due To Gravity*Height GO
Pressure when density and height are given
Pressure=Density*Acceleration Due To Gravity*Height GO

### Periodic time of SHM for compound pendulum in terms of radius of gyration Formula

Periodic time for compound pendulum=2*pi*sqrt(((Radius of gyration^2)+(Distance of point of suspension of pendulum from the center of gravity^2))/(Acceleration Due To Gravity*Distance of point of suspension of pendulum from the center of gravity))
More formulas
Frequency of oscillation for SHM GO
Periodic time for SHM GO
Restoring torque for simple pendulum GO
Moment of inertia of bob of pendulum, about an axis through the point of suspension GO
Restoring force due to spring GO
Deflection of spring when mass m is attached to it GO
Periodic time for one beat of SHM GO
Frequency of SHM for compound pendulum GO
Minimum periodic time of SHM for compound pendulum GO

## What is the meaning of time period or periodic time?

The time period is the time taken by a complete cycle of the wave to pass a point, Frequency is the number of complete cycle of waves passing a point in unit time. Angular frequency is angular displacement of any element of the wave per unit time.

## How to Calculate Periodic time of SHM for compound pendulum in terms of radius of gyration?

Periodic time of SHM for compound pendulum in terms of radius of gyration calculator uses Periodic time for compound pendulum=2*pi*sqrt(((Radius of gyration^2)+(Distance of point of suspension of pendulum from the center of gravity^2))/(Acceleration Due To Gravity*Distance of point of suspension of pendulum from the center of gravity)) to calculate the Periodic time for compound pendulum, Periodic time of SHM for compound pendulum in terms of radius of gyration is the time taken for one complete cycle of vibration to pass a given point. Periodic time for compound pendulum and is denoted by tp symbol.

How to calculate Periodic time of SHM for compound pendulum in terms of radius of gyration using this online calculator? To use this online calculator for Periodic time of SHM for compound pendulum in terms of radius of gyration, enter Acceleration Due To Gravity (g), Radius of gyration (kG) and Distance of point of suspension of pendulum from the center of gravity (h) and hit the calculate button. Here is how the Periodic time of SHM for compound pendulum in terms of radius of gyration calculation can be explained with given input values -> 5.496642 = 2*pi*sqrt(((3^2)+(6^2))/(9.8*6)).

### FAQ

What is Periodic time of SHM for compound pendulum in terms of radius of gyration?
Periodic time of SHM for compound pendulum in terms of radius of gyration is the time taken for one complete cycle of vibration to pass a given point and is represented as tp=2*pi*sqrt(((kG^2)+(h^2))/(g*h)) or Periodic time for compound pendulum=2*pi*sqrt(((Radius of gyration^2)+(Distance of point of suspension of pendulum from the center of gravity^2))/(Acceleration Due To Gravity*Distance of point of suspension of pendulum from the center of gravity)). The Acceleration Due To Gravity is acceleration gained by an object because of gravitational force, Radius of gyration or gyradius of a body about an axis of rotation is defined as the radial distance to a point which would have a moment of inertia the same as the body's actual distribution of mass, if the total mass of the body were concentrated there and Distance of point of suspension of pendulum from the center of gravity is measured length between that point and center of gravity of the body.
How to calculate Periodic time of SHM for compound pendulum in terms of radius of gyration?
Periodic time of SHM for compound pendulum in terms of radius of gyration is the time taken for one complete cycle of vibration to pass a given point is calculated using Periodic time for compound pendulum=2*pi*sqrt(((Radius of gyration^2)+(Distance of point of suspension of pendulum from the center of gravity^2))/(Acceleration Due To Gravity*Distance of point of suspension of pendulum from the center of gravity)). To calculate Periodic time of SHM for compound pendulum in terms of radius of gyration, you need Acceleration Due To Gravity (g), Radius of gyration (kG) and Distance of point of suspension of pendulum from the center of gravity (h). With our tool, you need to enter the respective value for Acceleration Due To Gravity, Radius of gyration and Distance of point of suspension of pendulum from the center of gravity and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well. Let Others Know