Sum of 4th Powers of First N Natural Numbers Solution

STEP 0: Pre-Calculation Summary
Formula Used
Sum of 4th Powers of First N Natural Numbers = (Value of N*(Value of N+1)*(2*Value of N+1)*(3*Value of N^2+3*Value of N-1))/30
Sn4 = (n*(n+1)*(2*n+1)*(3*n^2+3*n-1))/30
This formula uses 2 Variables
Variables Used
Sum of 4th Powers of First N Natural Numbers - The Sum of 4th Powers of First N Natural Numbers is the summation of 4th powers of the natural numbers starting from 1 to the nth natural number.
Value of N - The Value of N is the total number of terms from the beginning of the series up to where the sum of series is calculating.
STEP 1: Convert Input(s) to Base Unit
Value of N: 3 --> No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
Sn4 = (n*(n+1)*(2*n+1)*(3*n^2+3*n-1))/30 --> (3*(3+1)*(2*3+1)*(3*3^2+3*3-1))/30
Evaluating ... ...
Sn4 = 98
STEP 3: Convert Result to Output's Unit
98 --> No Conversion Required
FINAL ANSWER
98 <-- Sum of 4th Powers of First N Natural Numbers
(Calculation completed in 00.004 seconds)

Credits

Created by Dipto Mandal
Indian Institute of Information Technology (IIIT), Guwahati
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Indian Institute of Information Technology (IIIT), Bhopal
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7 Sum of 4th Powers Calculators

Sum of 10th Powers of First N Natural Numbers
Go Sum of 10th Powers of First N Natural Numbers = (Value of N*(Value of N+1)*(2*Value of N+1)*(Value of N^2+Value of N-1)*(3*Value of N^6+9*Value of N^5+2*Value of N^4-11*Value of N^3+3*Value of N^2+10*Value of N-5))/66
Sum of 8th Powers of First N Natural Numbers
Go Sum of 8th Powers of First N Natural Numbers = (Value of N*(Value of N+1)*(2*Value of N+1)*(5*Value of N^6+15*Value of N^5+5*Value of N^4-15*Value of N^3-Value of N^2+9*Value of N-3))/90
Sum of 9th Powers of First N Natural Numbers
Go Sum of 9th Powers of First N Natural Numbers = (Value of N^2*(Value of N^2+Value of N-1)*(2*Value of N^4+4*Value of N^3-Value of N^2-3*Value of N+3)*(Value of N+1)^2)/20
Sum of 6th Powers of First N Natural Numbers
Go Sum of 6th Powers of First N Natural Numbers = (Value of N*(Value of N+1)*(2*Value of N+1)*(3*Value of N^4+6*Value of N^3-3*Value of N+1))/42
Sum of 7th Powers of First N Natural Numbers
Go Sum of 7th Powers of First N Natural Numbers = (Value of N^2*(3*Value of N^4+6*Value of N^3-Value of N^2-4*Value of N+2)*(Value of N+1)^2)/24
Sum of 4th Powers of First N Natural Numbers
Go Sum of 4th Powers of First N Natural Numbers = (Value of N*(Value of N+1)*(2*Value of N+1)*(3*Value of N^2+3*Value of N-1))/30
Sum of 5th Powers of First N Natural Numbers
Go Sum of 5th Powers of First N Natural Numbers = (Value of N^2*(2*Value of N^2 +2*Value of N-1)*(Value of N+1)^2)/12

Sum of 4th Powers of First N Natural Numbers Formula

Sum of 4th Powers of First N Natural Numbers = (Value of N*(Value of N+1)*(2*Value of N+1)*(3*Value of N^2+3*Value of N-1))/30
Sn4 = (n*(n+1)*(2*n+1)*(3*n^2+3*n-1))/30

What is a General Series?

Suppose a1, a2, a3, …, an is a sequence such that the expression a1 + a2 + a3 +,…+ an is called the series associated with the given sequence.

Where are Series used?

Series are used in most areas of mathematics, even for studying finite structures (such as in combinatorics) through generating functions. In addition to their ubiquity in mathematics, infinite series are also widely used in other quantitative disciplines such as physics, computer science, statistics and finance.

How to Calculate Sum of 4th Powers of First N Natural Numbers?

Sum of 4th Powers of First N Natural Numbers calculator uses Sum of 4th Powers of First N Natural Numbers = (Value of N*(Value of N+1)*(2*Value of N+1)*(3*Value of N^2+3*Value of N-1))/30 to calculate the Sum of 4th Powers of First N Natural Numbers, Sum of 4th Powers of First N Natural Numbers formula is defined as the summation of 4th powers of the natural numbers starting from 1 to the nth natural number. Sum of 4th Powers of First N Natural Numbers is denoted by Sn4 symbol.

How to calculate Sum of 4th Powers of First N Natural Numbers using this online calculator? To use this online calculator for Sum of 4th Powers of First N Natural Numbers, enter Value of N (n) and hit the calculate button. Here is how the Sum of 4th Powers of First N Natural Numbers calculation can be explained with given input values -> 98 = (3*(3+1)*(2*3+1)*(3*3^2+3*3-1))/30.

FAQ

What is Sum of 4th Powers of First N Natural Numbers?
Sum of 4th Powers of First N Natural Numbers formula is defined as the summation of 4th powers of the natural numbers starting from 1 to the nth natural number and is represented as Sn4 = (n*(n+1)*(2*n+1)*(3*n^2+3*n-1))/30 or Sum of 4th Powers of First N Natural Numbers = (Value of N*(Value of N+1)*(2*Value of N+1)*(3*Value of N^2+3*Value of N-1))/30. The Value of N is the total number of terms from the beginning of the series up to where the sum of series is calculating.
How to calculate Sum of 4th Powers of First N Natural Numbers?
Sum of 4th Powers of First N Natural Numbers formula is defined as the summation of 4th powers of the natural numbers starting from 1 to the nth natural number is calculated using Sum of 4th Powers of First N Natural Numbers = (Value of N*(Value of N+1)*(2*Value of N+1)*(3*Value of N^2+3*Value of N-1))/30. To calculate Sum of 4th Powers of First N Natural Numbers, you need Value of N (n). With our tool, you need to enter the respective value for Value of N and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
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