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## < 11 Other formulas that you can solve using the same Inputs

Gravitational potential of a thin circular disc
Gravitational Potential=-(2*[G.]*Mass*(sqrt((Distance from center to a point)^2+(radius)^2)-Distance from center to a point))/(radius)^2 GO
Gravitational field of a ring
Gravitational Field=-([G.]*Mass*Distance from center to a point)/((Radius of ring)^2+(Distance from center to a point)^2)^(3/2) GO
Field of a Bar Magnet at axial position
Field at the axial position of a bar magnet=[Permeability-vacuum]*2*Magnetic Moment/(4*pi*(Distance from center to a point)^3) GO
Gravitational potential when point p is inside of non conducting solid sphere
Gravitational field of a ring when cosθ is given
Gravitational Field=-([G.]*Mass*cos(Theta))/((Distance from center to a point)^2+(Radius of ring)^2)^2 GO
Gravitational potential of a ring
Gravitational Potential=-([G.]*Mass)/sqrt((Radius of ring)^2+(Distance from center to a point)^2) GO
Gravitational field when point P is inside of non conducting solid sphere
Gravitational Field=-([G.]*Mass*Distance from center to a point)/(radius)^3 GO
Gravitational potential when point P is outside of non-conducting solid sphere
Gravitational Potential=-([G.]*Mass)/Distance from center to a point GO
Gravitational field when point P is outside of non conducting solid sphere
Gravitational Field=-([G.]*Mass)/(Distance from center to a point)^2 GO
Gravitational potential when point p is outside of conducting solid sphere
Gravitational Potential=-([G.]*Mass)/Distance from center to a point GO
Gravitational field when point P is outside of conducting solid sphere
Gravitational Field=-([G.]*Mass)/(Distance from center to a point)^2 GO

### Field of a Bar Magnet at equatorial position Formula

Field at the equitorial position of a bar magnet=[Permeability-vacuum]*Magnetic Moment/(4*pi*Distance from center to a point)^3
More formulas
Magnetic Field Due to a Straight Conductor GO
Magnetic Field Due to an Infinite Straight Wire GO
Magnetic Field on the Axis of a Ring GO
Force Between Parallel Wires GO
Field at the Center of an Arc GO
Field at the Center of an arc GO
Field Inside a Solenoid GO
field at the center of the ring GO
Field of a Bar Magnet at axial position GO
Angle of Dip GO
Magnetic Field for a Tangent Galvanometer GO
Electric Current for a Tangent Galvanometer GO
Current for a Moving Coil Galvanometer GO
Time Period of Magnetometer GO
Magnetic Permeability GO

## How to calculate magnetic field at a point along the equatorial line of a bar magnet ?

NS is the bar magnet of length 2l and pole strength m. P is a point on the equatorial line at a distance d from its mid point O (Fig.). Magnetic induction (B1) at P due to north pole of the magnet, B1 = mu_0/4π . m/NP2 along NP = Mu_0/4π . m/(d2+l2) along NP NP2 = NO2 + OP2 Magnetic induction (B2) at P due to south pole of the magnet, B2 = mu_0/4π . m/PS2 along PS = mu_0/4π . m/(d2+l2) along PS Resolving B1 and B2 into their horizontal and vertical components. Vertical components B1 sin θ and B2 sin θ are equal and opposite and therefore cancel each other (Fig.). The horizontal components B1 cos θ and B2 cos θ will get added along PT. Resultant magnetic induction at P due to the bar magnet is B = B1 cos θ + B2 cos θ. (along PT) After apply B1 and B2 B = = mu_0/4π . M/d3 The direction of B is along PT parallel to NS.

## How to Calculate Field of a Bar Magnet at equatorial position?

Field of a Bar Magnet at equatorial position calculator uses Field at the equitorial position of a bar magnet=[Permeability-vacuum]*Magnetic Moment/(4*pi*Distance from center to a point)^3 to calculate the Field at the equitorial position of a bar magnet, Field of a Bar Magnet at equatorial position is the magnetic field generated by bar magnet at the point goes through it's perpendicular bisector at a distance of d from center of bar magnet. Field at the equitorial position of a bar magnet and is denoted by B symbol.

How to calculate Field of a Bar Magnet at equatorial position using this online calculator? To use this online calculator for Field of a Bar Magnet at equatorial position, enter Distance from center to a point (a) and Magnetic Moment (M) and hit the calculate button. Here is how the Field of a Bar Magnet at equatorial position calculation can be explained with given input values -> 6.333E-7 = [Permeability-vacuum]*1/(4*pi*0.1)^3.

### FAQ

What is Field of a Bar Magnet at equatorial position?
Field of a Bar Magnet at equatorial position is the magnetic field generated by bar magnet at the point goes through it's perpendicular bisector at a distance of d from center of bar magnet and is represented as B=[Permeability-vacuum]*M/(4*pi*a)^3 or Field at the equitorial position of a bar magnet=[Permeability-vacuum]*Magnetic Moment/(4*pi*Distance from center to a point)^3. Distance from center to a point is the length of line segment measured from the center of a body to a particular point and Magnetic Moment is a determination of its tendency to get arranged through a magnetic field.
How to calculate Field of a Bar Magnet at equatorial position?
Field of a Bar Magnet at equatorial position is the magnetic field generated by bar magnet at the point goes through it's perpendicular bisector at a distance of d from center of bar magnet is calculated using Field at the equitorial position of a bar magnet=[Permeability-vacuum]*Magnetic Moment/(4*pi*Distance from center to a point)^3. To calculate Field of a Bar Magnet at equatorial position, you need Distance from center to a point (a) and Magnetic Moment (M). With our tool, you need to enter the respective value for Distance from center to a point and Magnetic Moment and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well. Let Others Know